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Flashcards: Arc Length, Radii, Radian, and Sector Similarity and Proportionality: CCSS.Math.Content.HSG-C.B.5

If the radius is $\displaystyle 6$, and the central angle is $\frac{\pi}{24}$ $\displaystyle \frac{\pi}{24}$ find the arc length.

$\frac{144}{\pi}$ $\displaystyle \frac{144}{\pi}$

$\displaystyle 36$

$4 \pi$ $\displaystyle 4 \pi$

$\frac{\pi}{4}$ $\displaystyle \frac{\pi}{4}$

$\frac{\pi}{24} + 6$ $\displaystyle \frac{\pi}{24} + 6$

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Flashcards: Arc Length, Radii, Radian, and Sector Similarity and Proportionality: CCSS.Math.Content.HSG-C.B.5

If the radius is $\displaystyle 6$, and the central angle is $\frac{\pi}{24}$ $\displaystyle \frac{\pi}{24}$ find the arc length.

$\frac{144}{\pi}$ $\displaystyle \frac{144}{\pi}$

$\displaystyle 36$

$4 \pi$ $\displaystyle 4 \pi$

$\frac{\pi}{4}$ $\displaystyle \frac{\pi}{4}$

$\frac{\pi}{24} + 6$ $\displaystyle \frac{\pi}{24} + 6$

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Flashcards: Arc Length, Radii, Radian, and Sector Similarity and Proportionality: CCSS.Math.Content.HSG-C.B.5

If the radius is $\displaystyle 6$, and the central angle is $\frac{\pi}{24}$ $\displaystyle \frac{\pi}{24}$ find the arc length.

Your answer:

$\frac{144}{\pi}$ $\displaystyle \frac{144}{\pi}$

Your answer:

$\displaystyle 36$

Your answer:

$4 \pi$ $\displaystyle 4 \pi$

Your answer:

$\frac{\pi}{24} + 6$ $\displaystyle \frac{\pi}{24} + 6$

Correct answer:

$\frac{\pi}{4}$ $\displaystyle \frac{\pi}{4}$

Explanation:

To find the arc length, we simply multiply the radius by the central angle.

$\\s = \theta r \\s = 6 \cdot \frac{\pi}{24} \\s = \frac{\pi}{4}$ $\displaystyle \\s = \theta r \\s = 6 \cdot \frac{\pi}{24} \\s = \frac{\pi}{4}$

Flashcards: Arc Length, Radii, Radian, and Sector Similarity and Proportionality: CCSS.Math.Content.HSG-C.B.5

If the radius is $\displaystyle 13$ , and the central angle is $\frac{\pi}{5}$ $\displaystyle \frac{\pi}{5}$ find the arc length.

169 $\displaystyle 169$

$\frac{13 \pi}{5}$ $\displaystyle \frac{13 \pi}{5}$

$\frac{\pi}{5} + 13$ $\displaystyle \frac{\pi}{5} + 13$

$\frac{65}{\pi}$ $\displaystyle \frac{65}{\pi}$

$\frac{5 \pi}{13}$ $\displaystyle \frac{5 \pi}{13}$

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Flashcards: Arc Length, Radii, Radian, and Sector Similarity and Proportionality: CCSS.Math.Content.HSG-C.B.5

If the radius is $\displaystyle 13$ , and the central angle is $\frac{\pi}{5}$ $\displaystyle \frac{\pi}{5}$ find the arc length.

Your answer:

169 $\displaystyle 169$

Your answer:

$\frac{\pi}{5} + 13$ $\displaystyle \frac{\pi}{5} + 13$

Your answer:

$\frac{65}{\pi}$ $\displaystyle \frac{65}{\pi}$

Your answer:

$\frac{5 \pi}{13}$ $\displaystyle \frac{5 \pi}{13}$

Correct answer:

$\frac{13 \pi}{5}$ $\displaystyle \frac{13 \pi}{5}$

Explanation:

To find the arc length, we simply multiply the radius by the central angle.

$\\s = \theta r \\s = 13 \cdot \frac{\pi}{5} \\s = \frac{13 \pi}{5}$ $\displaystyle \\s = \theta r \\s = 13 \cdot \frac{\pi}{5} \\s = \frac{13 \pi}{5}$

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Flashcards: Arc Length, Radii, Radian, and Sector Similarity and Proportionality: CCSS.Math.Content.HSG-C.B.5

All Common Core: High School - Geometry Resources

Flashcards: Arc Length, Radii, Radian, and Sector Similarity and Proportionality: CCSS.Math.Content.HSG-C.B.5

Flashcards: Arc Length, Radii, Radian, and Sector Similarity and Proportionality: CCSS.Math.Content.HSG-C.B.5

Flashcards: Arc Length, Radii, Radian, and Sector Similarity and Proportionality: CCSS.Math.Content.HSG-C.B.5

Flashcards: Arc Length, Radii, Radian, and Sector Similarity and Proportionality: CCSS.Math.Content.HSG-C.B.5

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