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Common Core: High School - Number and Quantity : Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

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Example Questions

Example Question #1 : Use, Understand, And Interpret Units: Ccss.Math.Content.Hsn Q.A.1

Evaluate: $169^{\frac{3}{2}}$ $\displaystyle 169^{\frac{3}{2}}$

Possible Answers:

$\displaystyle 13$

235.5 $\displaystyle 235.5$

2197 $\displaystyle 2197$

169 $\displaystyle 169$

Correct answer:

2197 $\displaystyle 2197$

Explanation:

To evaluate this, let's rewrite the problem.

$169^{\frac{3}{2}}=(\sqrt[]{64})^3$ $\displaystyle 169^{\frac{3}{2}}=(\sqrt[]{64})^3$

Now lets break down the square root.

$(\sqrt[]{169})^3=(\sqrt[]{13\cdot13})^3=(\sqrt[]{13^2})^3=13^3=2197$ $\displaystyle (\sqrt[]{169})^3=(\sqrt[]{13\cdot13})^3=(\sqrt[]{13^2})^3=13^3=2197$

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Example Question #1 : Use, Understand, And Interpret Units: Ccss.Math.Content.Hsn Q.A.1

If the temperature is $33 ^{\circ} C$ $\displaystyle 33 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

92.4 $\displaystyle 92.4$

59.4 $\displaystyle 59.4$

$\displaystyle 65$

91.4 $\displaystyle 91.4$

$\displaystyle 33$

Correct answer:

91.4 $\displaystyle 91.4$

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

$\displaystyle F = 1.8 C + 32$

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ $\displaystyle \uptext{C}$.

$F = 1.8 \cdot 33 +32$ $\displaystyle F = 1.8 \cdot 33 +32$

$\displaystyle F = 59.4 +32$

$\displaystyle F = 91.4$

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Example Question #2 : Quantities*

If the temperature is $43 ^{\circ} C$ $\displaystyle 43 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

110.4 $\displaystyle 110.4$

$\displaystyle 43$

109.4 $\displaystyle 109.4$

77.4 $\displaystyle 77.4$

$\displaystyle 75$

Correct answer:

109.4 $\displaystyle 109.4$

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

$\displaystyle F = 1.8 C + 32$

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ $\displaystyle \uptext{C}$.

$F = 1.8 \cdot 43 +32$ $\displaystyle F = 1.8 \cdot 43 +32$

$\displaystyle F = 77.4 +32$

$\displaystyle F = 109.4$

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Example Question #26 : High School: Number And Quantity

If the temperature is $63 ^{\circ} C$ $\displaystyle 63 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

$\displaystyle 95$

113.4 $\displaystyle 113.4$

$\displaystyle 63$

146.4 $\displaystyle 146.4$

145.4 $\displaystyle 145.4$

Correct answer:

145.4 $\displaystyle 145.4$

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

$\displaystyle F = 1.8 C + 32$

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ $\displaystyle \uptext{C}$.

$F = 1.8 \cdot 63 +32$ $\displaystyle F = 1.8 \cdot 63 +32$

$\displaystyle F = 113.4 +32$

$\displaystyle F = 145.4$

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Example Question #27 : High School: Number And Quantity

If the temperature is $67 ^{\circ} C$ $\displaystyle 67 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

$\displaystyle 67$

120.6 $\displaystyle 120.6$

153.6 $\displaystyle 153.6$

152.6 $\displaystyle 152.6$

$\displaystyle 99$

Correct answer:

152.6 $\displaystyle 152.6$

Explanation:

$\displaystyle F = 120.60 +32$

$\displaystyle F = 152.6$

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Example Question #28 : High School: Number And Quantity

If the temperature is $30 ^{\circ} C$ $\displaystyle 30 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

$\displaystyle 30$

$\displaystyle 62$

86.0 $\displaystyle 86.0$

87.0 $\displaystyle 87.0$

54.0 $\displaystyle 54.0$

Correct answer:

86.0 $\displaystyle 86.0$

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

$\displaystyle F = 1.8 C + 32$

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ $\displaystyle \uptext{C}$.

$F = 1.8 \cdot 30 +32$ $\displaystyle F = 1.8 \cdot 30 +32$

$\displaystyle F = 54.0 +32$

$\displaystyle F = 86.0$

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Example Question #29 : High School: Number And Quantity

If the temperature is $58 ^{\circ} C$ $\displaystyle 58 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

137.4 $\displaystyle 137.4$

$\displaystyle 58$

$\displaystyle 90$

104.4 $\displaystyle 104.4$

136.4 $\displaystyle 136.4$

Correct answer:

136.4 $\displaystyle 136.4$

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

$\displaystyle F = 1.8 C + 32$

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ $\displaystyle \uptext{C}$.

$F = 1.8 \cdot 58 +32$ $\displaystyle F = 1.8 \cdot 58 +32$

$\displaystyle F = 104.4 +32$

$\displaystyle F = 136.4$

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Example Question #1 : Quantities*

If the temperature is $20 ^{\circ} C$ $\displaystyle 20 ^{\circ} C$, find the temperature in degrees Fahrenheit.

Possible Answers:

$\displaystyle 69$

$\displaystyle 20$

$\displaystyle 68$

$\displaystyle 36$

$\displaystyle 52$

Correct answer:

$\displaystyle 68$

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

$\displaystyle F = 1.8 C + 32$

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ $\displaystyle \uptext{C}$.

$F = 1.8 \cdot 20 +32$ $\displaystyle F = 1.8 \cdot 20 +32$

$\displaystyle F = 36.0 +32$

$\displaystyle F = 68.0$

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Example Question #1 : Use, Understand, And Interpret Units: Ccss.Math.Content.Hsn Q.A.1

If the temperature is $49 ^{\circ} C$ $\displaystyle 49 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

121.2 $\displaystyle 121.2$

88.2 $\displaystyle 88.2$

$\displaystyle 81$

$\displaystyle 49$

120.2 $\displaystyle 120.2$

Correct answer:

120.2 $\displaystyle 120.2$

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

$\displaystyle F = 1.8 C + 32$

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ $\displaystyle \uptext{C}$.

$F = 1.8 \cdot 49 +32$ $\displaystyle F = 1.8 \cdot 49 +32$

$\displaystyle F = 88.2 +32$

$\displaystyle F = 120.2$

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Example Question #2 : Use, Understand, And Interpret Units: Ccss.Math.Content.Hsn Q.A.1

If the temperature is $59 ^{\circ} C$ $\displaystyle 59 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Possible Answers:

138.2 $\displaystyle 138.2$

$\displaystyle 91$

106.2 $\displaystyle 106.2$

139.2 $\displaystyle 139.2$

$\displaystyle 59$

Correct answer:

138.2 $\displaystyle 138.2$

Explanation:

$F = 1.8 \cdot 59 +32$ $\displaystyle F = 1.8 \cdot 59 +32$

$\displaystyle F = 106.2 +32$

$\displaystyle F = 138.2$

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All Common Core: High School - Number and Quantity Resources

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Common Core: High School - Number and Quantity : Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

Study concepts, example questions & explanations for Common Core: High School - Number and Quantity

All Common Core: High School - Number and Quantity Resources

Example Questions

Example Question #1 : Use, Understand, And Interpret Units: Ccss.Math.Content.Hsn Q.A.1

Example Question #1 : Use, Understand, And Interpret Units: Ccss.Math.Content.Hsn Q.A.1

Example Question #2 : Quantities*

Example Question #26 : High School: Number And Quantity

Example Question #27 : High School: Number And Quantity

Example Question #28 : High School: Number And Quantity

Example Question #29 : High School: Number And Quantity

Example Question #1 : Quantities*

Example Question #1 : Use, Understand, And Interpret Units: Ccss.Math.Content.Hsn Q.A.1

Example Question #2 : Use, Understand, And Interpret Units: Ccss.Math.Content.Hsn Q.A.1

All Common Core: High School - Number and Quantity Resources

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