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Example Questions
Example Question #1 : How To Simplify Square Roots
Simplify the following: (√(6) + √(3)) / √(3)
3√(2)
√(2) + 1
√(3)
1
None of the other answers
√(2) + 1
Begin by multiplying top and bottom by √(3):
(√(18) + √(9)) / 3
Note the following:
√(9) = 3
√(18) = √(9 * 2) = √(9) * √(2) = 3 * √(2)
Therefore, the numerator is: 3 * √(2) + 3. Factor out the common 3: 3 * (√(2) + 1)
Rewrite the whole fraction:
(3 * (√(2) + 1)) / 3
Simplfy by dividing cancelling the 3 common to numerator and denominator: √(2) + 1
Example Question #1 : How To Simplify Square Roots
what is
√0.0000490
0.007
7
49
0.07
0.00007
0.007
easiest way to simplify: turn into scientific notation
√0.0000490= √4.9 X 10-5
finding the square root of an even exponent is easy, and 49 is a perfect square, so we can write out an improper scientific notation:
√4.9 X 10-5 = √49 X 10-6
√49 = 7; √10-6 = 10-3 this is equivalent to raising 10-6 to the 1/2 power, in which case all that needs to be done is multiply the two exponents: 7 X 10-3= 0.007
Example Question #11 : Arithmetic
Simplify:
In order to take the square root, divide 576 by 2.
Example Question #1 : How To Simplify Square Roots
Simplify .
Example Question #1 : How To Simplify Square Roots
Simplfy the following radical .
You can rewrite the equation as .
This simplifies to .
Example Question #791 : New Sat
Which of the following is equal to ?
√75 can be broken down to √25 * √3. Which simplifies to 5√3.
Example Question #11 : Simplifying Square Roots
Simplify .
Rewrite what is under the radical in terms of perfect squares:
Therefore, .
Example Question #1 : Simplifying Square Roots
What is ?
We know that 25 is a factor of 50. The square root of 25 is 5. That leaves which can not be simplified further.
Example Question #21 : Arithmetic
Which of the following is equivalent to ?
Multiply by the conjugate and the use the formula for the difference of two squares:
Example Question #2 : How To Simplify Square Roots
Which of the following is the most simplified form of:
First find all of the prime factors of
So
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