High School Math : How to find the area of a rectangle in pre-algebra

Study concepts, example questions & explanations for High School Math

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Example Questions

Example Question #1 : How To Find The Area Of A Rectangle In Pre Algebra

Find the area of a rectangle with a length of 18 meters and a width of 4 meters. 

Possible Answers:

\(\displaystyle 108\ m^{2}\)

\(\displaystyle 64\ m^{2}\)

\(\displaystyle 72\ m^{2}\)

\(\displaystyle 100\ m^{2}\)

\(\displaystyle 74\ m^{2}\)

Correct answer:

\(\displaystyle 72\ m^{2}\)

Explanation:

The area formula for a rectangle is \(\displaystyle length\times width\). Plug in the values and you get 72. Since area is squared, make sure your units are squared as well.

Example Question #2 : How To Find The Area Of A Rectangle In Pre Algebra

What is the area of a rectangle with a base of \(\displaystyle 27\) and a height of \(\displaystyle 21\)?

Possible Answers:

\(\displaystyle 567\)

\(\displaystyle 617\)

\(\displaystyle 581\)

\(\displaystyle 603\)

Correct answer:

\(\displaystyle 567\)

Explanation:

To find the area of a rectangle we multiply the base by the height. \(\displaystyle Area=b*h\)

Plug the number \(\displaystyle 27\) for base and \(\displaystyle 21\) for height into the equation to get \(\displaystyle Area=27*21\).

We then multiply to find the answer for the area is \(\displaystyle 567\).

Example Question #3 : How To Find The Area Of A Rectangle In Pre Algebra

What is the area of a rectangle with a base of \(\displaystyle 5\) and a height of \(\displaystyle 52\)?

Possible Answers:

\(\displaystyle 255\)

\(\displaystyle 260\)

\(\displaystyle 248\)

\(\displaystyle 250\)

Correct answer:

\(\displaystyle 260\)

Explanation:

To find the area of a rectangle we multiply the base by the height. 

Plug the number \(\displaystyle 5\) for base and \(\displaystyle 52\) for height into the equation to get \(\displaystyle Area=5*52\).

We then multiply to find the answer for the area is \(\displaystyle 260\).

Example Question #3 : How To Find The Area Of A Rectangle In Pre Algebra

The area of a rectangle is \(\displaystyle 32\). If the length of the rectangle is \(\displaystyle 8\), what is the width?

Possible Answers:

\(\displaystyle 24\)

\(\displaystyle 8\)

\(\displaystyle 12\)

\(\displaystyle 16\)

\(\displaystyle 4\)

Correct answer:

\(\displaystyle 4\)

Explanation:

The formula for the area of a rectangle is the length times the width: \(\displaystyle A=l*w\).

Plug in our given information:

\(\displaystyle 32=8*w\)

Divide both sides by 8.

\(\displaystyle \frac{32}{8}=w\)

\(\displaystyle 4=w\)

Example Question #4 : How To Find The Area Of A Rectangle In Pre Algebra

The area of a quadrilateral is \(\displaystyle 52\). If the length of one side is \(\displaystyle 4\), what is the width of the figure?

Possible Answers:

\(\displaystyle 13\)

\(\displaystyle 34\)

\(\displaystyle 16\)

\(\displaystyle 48\)

\(\displaystyle 4\)

Correct answer:

\(\displaystyle 13\)

Explanation:

The area of a quadrilateral is the length times the width, or \(\displaystyle A=l*w\). The problem gives us the area and the length, so we can solve:

\(\displaystyle A=l*w\)

\(\displaystyle 52=4*w\)

Divide both sides by \(\displaystyle 4\):

\(\displaystyle \frac{52}{4}=w\)

\(\displaystyle 13=w\)

Example Question #5 : How To Find The Area Of A Rectangle In Pre Algebra

What is the area of a rectangle with a length of \(\displaystyle 5\) and a width of \(\displaystyle 2\)?

Possible Answers:

\(\displaystyle 14\)

\(\displaystyle 10\)

\(\displaystyle 7\)

\(\displaystyle 20\)

\(\displaystyle 5\)

Correct answer:

\(\displaystyle 10\)

Explanation:

The area of a rectangle is the length times the width: \(\displaystyle A=l*w\)

Plug in our given values and solve:

\(\displaystyle A=l*w\)

\(\displaystyle A=5*2\)

\(\displaystyle A=10\)

Example Question #2 : How To Find The Area Of A Rectangle In Pre Algebra

If a rectangle has an area of \(\displaystyle 36\) and a length of \(\displaystyle 3\), what is the width?

Possible Answers:

\(\displaystyle 12\)

\(\displaystyle 36\)

\(\displaystyle 6\)

\(\displaystyle 4\)

\(\displaystyle \sqrt{12}\)

Correct answer:

\(\displaystyle 12\)

Explanation:

The formula for the area of a rectangle is \(\displaystyle A=l*w\)

We can plug in our given information to solve:

\(\displaystyle A=l*w\)

\(\displaystyle 36=3*w\)

Divide both sides by \(\displaystyle 3\).

\(\displaystyle \frac{36}{3}=w\)

\(\displaystyle 12=w\)

Example Question #2 : How To Find The Area Of A Rectangle In Pre Algebra

What is the area of a rectangle with a length of \(\displaystyle \small 5\) and a width of \(\displaystyle \small 3\)?

Possible Answers:

\(\displaystyle 7.5\)

\(\displaystyle 16\)

\(\displaystyle 8\)

\(\displaystyle 15\)

Correct answer:

\(\displaystyle 15\)

Explanation:

The area of a rectangle is equal to the product of the length and the width.

\(\displaystyle A=l\times w\)

We are given both values, so we simply multiply.

\(\displaystyle A=5\times 3=15\)

Example Question #6 : How To Find The Area Of A Rectangle In Pre Algebra

What is the area of a rectangle with a base of \(\displaystyle 3\) and a height of \(\displaystyle 16\)?

Possible Answers:

\(\displaystyle 48\)

\(\displaystyle 24\)

\(\displaystyle 38\)

\(\displaystyle 19\)

Correct answer:

\(\displaystyle 48\)

Explanation:

To find the area of a rectangle we multiply the base by the height. 

Plug the number \(\displaystyle 3\) for the base and \(\displaystyle 16\) for the height into the equation to get \(\displaystyle A=3*16\).

We then multiply to find the answer for the area is \(\displaystyle 48\).

Example Question #7 : How To Find The Area Of A Rectangle In Pre Algebra

What is the area of a rectangle with a base of \(\displaystyle 15\) and a height of \(\displaystyle 4\)?

Possible Answers:

\(\displaystyle A=17\)

\(\displaystyle A=45\)

\(\displaystyle A=60\)

\(\displaystyle A=30\)

Correct answer:

\(\displaystyle A=60\)

Explanation:

To find the area of a rectangle we multiply the base by the height.

Plug in the number \(\displaystyle 15\) for the base and \(\displaystyle 4\) for the height to get

\(\displaystyle A=4\cdot 15\)

We then multiply to find the answer for the area is \(\displaystyle A=60\).

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