All High School Math Resources
Example Questions
Example Question #1 : Diameter And Chords
What is the diameter of a circle with a circumference of ?
To find the diameter we must understand the diameter in terms of circumference. The equation for the circumference of a circle is , where is the circumference and is the diameter. The circumference is equal to the diameter multiplied by .
We can rearrange to solve for .
All we have to do is plug in the circumference and divide by , and it will yield the diameter.
The s cancel and the diameter is .
Example Question #2 : Diameter And Chords
If the area of a circle is four times larger than the circumference of that same circle, what is the diameter of the circle?
4
32
8
16
2
16
Set the area of the circle equal to four times the circumference πr2 = 4(2πr).
Cross out both π symbols and one r on each side leaves you with r = 4(2) so r = 8 and therefore d = 16.
Example Question #2 : Diameter
The perimeter of a circle is 36 π. What is the diameter of the circle?
18
3
72
36
6
36
The perimeter of a circle = 2 πr = πd
Therefore d = 36
Example Question #3 : Diameter And Chords
If the area of the circle touching the square in the picture above is , what is the closest value to the area of the square?
Obtain the radius of the circle from the area.
Split the square up into 4 triangles by connecting opposite corners. These triangles will have a right angle at the center of the square, formed by two radii of the circle, and two 45-degree angles at the square's corners. Because you have a 45-45-90 triangle, you can calculate the sides of the triangles to be , , and . The radii of the circle (from the center to the corners of the square) will be 9. The hypotenuse (side of the square) must be .
The area of the square is then .
Example Question #4 : Diameter And Chords
Two legs of a right triangle measure 3 and 4, respectively. What is the area of the circle that circumscribes the triangle?
For the circle to contain all 3 vertices, the hypotenuse must be the diameter of the circle. The hypotenuse, and therefore the diameter, is 5, since this must be a 3-4-5 right triangle.
The equation for the area of a circle is A = πr2.