All HiSET: Math Resources
Example Questions
Example Question #1 : Algebraic Concepts
Identify the terms in the following equation:
All of these
All of these
In an equation, a term is a single number or a variable. in our equation we have the following terms:
Example Question #2 : Algebraic Concepts
How many terms are in the following expression: ?
None of the Above
Step 1: We need to separate and arrange the terms in the jumbled expression given to us in the question..
We will separate the terms by the exponent value.
For , there is only one term:
For , there are no terms.
For , there is two terms:
For , there are two terms:
For , there are two terms:
For , there is only one term:
For , there are two terms:
For , there are three terms:
There are four constant terms:
Step 2: We will now add up the coefficients in each designation of terms. This will give us the answer.
Example Question #2 : Algebraic Concepts
Simplify the polynomial
.
How many terms does the simplified form have?
Five
Four
Three
Two
Six
Four
Arrange and combine like terms (those with the same variable) as follows:
Since each term now has a different exponent for the variable, no further combining is possible. The simplified form has four terms.
Example Question #3 : Algebraic Concepts
Identify the coefficients in the following formula:
All of these
All of these
Generally speaking, in an equation a coefficient is a constant by which a variable is multiplied. For example, and are coefficients in the following equation:
In our equation, the following numbers are coefficients:
Example Question #3 : Algebraic Concepts
What is the coefficient of the second highest term in the expression: ?
Step 1: Rearrange the terms from highest power to lowest power.
We will get: .
Step 2: We count the second term from starting from the left since it is the second highest term in the rearranged expression.
Step 3: Isolate the term.
The second term is
Step 4: Find the coefficient. The coefficient of a term is considered as the number before any variables. In this case, the coefficient is .
So, the answer is .
Example Question #4 : Algebraic Concepts
Add these two expressions together: and .
Step 1: Add the terms based on their similarities...
and becomes .
and becomes .
and becomes
Step 2: Combine all the terms after "becomes" in step 1...
We add and get: .
Example Question #5 : Algebraic Concepts
Subtract and .
Step 1: Subtract these terms by separating by exponents...
Step 2: Add all the simplified terms together...
Example Question #6 : Algebraic Concepts
Add or subtract:
Step 1: Find the Least Common Denominator of these fraction. We will list out multiples of each denominator until we find a common number for all three fractions...
The smallest common denominator is .
Step 2: Since the denominator is , we will convert all denominators to .
Step 3: Add up all the values of x...
Step 4: The result from step is the numerator and is the denominator. We will put these together.
Final Answer:
Example Question #1 : Algebraic Concepts
A quadratic function has two zeroes, 3 and 7. What could this function be?
None of the other choices gives the correct response.
A polynomial function with zeroes 3 and 7 has as its factors and . The function is given to be quadratic, so this function is
.
Apply the FOIL method to rewrite the polynomial:
Collect like terms:
,
the correct choice.
Example Question #7 : Algebraic Concepts
Solve.
In order to solve for the variable, , we need to isolate it on the left side of the equation. We will do this by reversing the operations done to the variable by performing the opposite of each operation on both sides of the equation.
Let's begin by rewriting the given equation.
Subtract from both sides of the equation.
Simplify.
Multiply both sides of the equation by .
Solve.