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SAT II Math II : Sine, Cosine, Tangent

Study concepts, example questions & explanations for SAT II Math II

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Example Questions

Example Question #3 : Understanding Sine, Cosine, And Tangent

If sin(x)=0.5 , what is sin(8x) if is between and $2\pi$ ?

Possible Answers:

0.5

-1.5

$\frac{\sqrt{3}}{2}$

$-\frac{\sqrt{3}}{2}$

-0.5

Correct answer:

$-\frac{\sqrt{3}}{2}$

Explanation:

Recall that $sin(\frac{\pi}{6}) =0.5$ .

Therefore, we are looking for $sin(8*\frac{\pi}{6})$ or $sin(\frac{4\pi}{3})$ .

Now, this has a reference angle of $\frac{\pi}{3}$ , but it is in the third quadrant. This means that the value will be negative. The value of $sin(\frac{\pi}{3})$ is $\frac{\sqrt{3}}{2}$ . However, given the quadrant of our angle, it will be $-\frac{\sqrt{3}}{2}$ .

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Example Question #457 : Sat Subject Test In Math Ii

Find the value of 5tan(60) in exact form.

Possible Answers:

$\frac{5\sqrt{3}}{3}$

$10\sqrt3$

$\frac{10\sqrt3}{3}$

$\frac{5\sqrt{3}}{2}$

$5\sqrt{3}$

Correct answer:

$5\sqrt{3}$

Explanation:

Recall that:

$tan(\theta) = \frac{sin(\theta)}{cos(\theta)}$

This means that: $tan(60) = \frac{sin(60)}{cos(60)}$

$sin(60) = \frac{\sqrt3}{2}$

$cos(60) = \frac{1}{2}$

Divide the two terms.

$\frac{\sqrt3}{2} \div \frac{1}{2} = \frac{\sqrt3}{2} \times \frac{2}{1} = \sqrt3$

This means that $5tan(60) = 5\sqrt{3}$ .

The answer is: $5\sqrt{3}$

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SAT II Math II : Sine, Cosine, Tangent

Study concepts, example questions & explanations for SAT II Math II

All SAT II Math II Resources

Example Questions

Example Question #3 : Understanding Sine, Cosine, And Tangent

Example Question #457 : Sat Subject Test In Math Ii

All SAT II Math II Resources

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