In order to solve this problem we must subtract the second number from the first number. 

\(\displaystyle \frac{\begin{array}[b]{r}999\\ -\ 82\end{array}}{ \ \ \ \space 917}\)

To square a number means to multiply it by itself, so we seek to compute

\(\displaystyle 0.44 \times 0.44\)

To multiply two decimal fractions, first multiply, ignoring the decimal points:

\(\displaystyle 44 \times 44 = 1,936\)

Move the (implied) decimal point the number of spaces right equal to the total number of digits right of the decimal points in the factors; this can be seen to be four:

\(\displaystyle 0.{\color{Red} 44} \times 0.{\color{Red} 44} = 0.{\color{Red} 1936}\)

The square of 0.44 is 0.1936.

Start by finding out how much Mark makes. Since he makes \(\displaystyle 15\%\) less than Tiffany, we can write the following to find Mark's weekly salary:

\(\displaystyle 1500-0.15(1500)=1275\)

Mark must make \(\displaystyle \$1275\) each week. Now, add together their salaries to find the sum.

\(\displaystyle 1500+1275=2775\)

Start by figuring out how much Rachel can earn in each week by multiplying her hourly rate by the number of hours worked each week.

\(\displaystyle \text{Earning each week}=12.50\times 40=500\)

Now, divide the amount she needs to earn by the amount earned each week to find how many weeks she will need to work to earn that amount.

\(\displaystyle \frac{3000}{500}=6\)

Rachel must work for \(\displaystyle 6\) weeks in order to earn enough for the car.

In order to solve this problem we need to line up the decimal places and add.

\(\displaystyle \frac{\begin{array}[b]{r}3.740\\\ +\ 22.786\end{array}}{ \ \ \ \space 26.526}\)

Start with finding the value of \(\displaystyle \frac{3}{4 }+\frac{1}{2}\).

In order to add fractions with different denominators, we will need to change one or both denominators first. Notice that \(\displaystyle 2\) is a factor of \(\displaystyle 4\), which means we can multiply the numerator and the denominator of \(\displaystyle \frac{1}{2}\) by \(\displaystyle 2\) to get \(\displaystyle \frac{2}{4}\).

Now, add the two fractions together as they have the same denominator.

\(\displaystyle \frac{3}{4}+\frac{1}{2}=\frac{3}{4}+\frac{2}{4}=\frac{5}{4}\)

Next, solve \(\displaystyle \frac{5}{4}-\frac{2}{3}\).

The least common multiple of \(\displaystyle 3\) and \(\displaystyle 4\) is \(\displaystyle 12\).

Thus, \(\displaystyle \frac{5}{4}-\frac{2}{3}=\frac{15}{12}-\frac{8}{12}=\frac{7}{12}\)

Start by finding out how many gallons is currently in Janice's tank.

Since it is only \(\displaystyle \frac{2}{3}\) full, 

\(\displaystyle \frac{2}{3}\times 15=10\).

The tank only has \(\displaystyle 10\) gallons in it right now. Multiply this by the number of miles traveled per gallon to find how far Janice can travel before the tank is empty.

\(\displaystyle 10 \times 30 = 300\)

Since the question asks for the product, you will need to multiply the two fractions. Recall that in multiplying two fractions, you will multiply the numerators together and then multiply the denominators together.

\(\displaystyle \frac{5}{6}\times \frac{3}{8}=\frac{15}{48}\)

Next, reduce the fraction.

\(\displaystyle \frac{15}{48}=\frac{5}{16}\)

Since the question asks you to find the difference, you will need to subtract the two fractions:

\(\displaystyle \frac{11}{12}-\frac{3}{4}\)

Start by making both denominators the same. Multiply the numerator and denominator of \(\displaystyle \frac{3}{4}\) by \(\displaystyle 3\) to get \(\displaystyle \frac{9}{12}\).

Now, subtract.

\(\displaystyle \frac{11}{12}-\frac{3}{4}=\frac{11}{12}-\frac{9}{12}=\frac{2}{12}\)

Make sure to simplify the answer.

\(\displaystyle \frac{2}{12}=\frac{1}{6}\)

Start by finding out Josie's typing rate.

Since she types \(\displaystyle 15\%\) faster, we can find her rate with the following equation:

\(\displaystyle 60+0.15(60)=69\)

Since Josie types at \(\displaystyle 69\) words per minute, we can multiply by the total number of given minutes to find out how many words she can type in the given time frame.

\(\displaystyle 69 \times 15=1035\)