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ACT Math : Square of Difference

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Example Questions

Example Question #1 : How To Find The Square Of Difference

$\small (3a-2b)^{2}$ can be rewritten as:

Possible Answers:

$\small 9a^{2}+4b^{2}$

$\small 9a^{2}-6ab+4b^{2}$

$\small 9a^{2}-4b^{2}$

$\small 9a^{2}+12ab+4b^{2}$

$\small 9a^{2}-12ab+4b^{2}$

Correct answer:

$\small 9a^{2}-12ab+4b^{2}$

Explanation:

Use the formula for solving the square of a difference, $\small (x-y)^{2}=x^{2}-2xy+y^{2}$ . In this case, $\small \small \small (3a-2b)^{2}=9a^{2}-12ab+4b^{2}$

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Example Question #2 : How To Find The Square Of Difference

Expand:

(2x-6)^2

Possible Answers:

4x^2-12x+36

4x^2-24x+36

2x^2-12x+24

4x-12

Correct answer:

4x^2-24x+36

Explanation:

To multiply a difference squared, square the first term and add two times the multiplication of the two terms. Then add the second term squared.

(2x^)^2+2(2x)(-6)+(-6)^2=4x^2-24x+36

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Example Question #1 : Square Of Difference

The expression $\frac{x^2-25}{x^2+11x+30}$ is equivalent to:

Possible Answers:

x+6

$\frac{x-5}{x+6}$

$\frac{x-6}{x-5}$

$\frac{x+5}{x-6}$

$\frac{x+6}{x+5}$

Correct answer:

$\frac{x-5}{x+6}$

Explanation:

First, we need to factor the numerator and denominator separately and cancel out similar terms. We will start with the numerator because it can be factored easily as the difference of two squares.

x^2 - 25 = (x + 5)(x - 5)

Now factor the quadratic in the denominator.

x^2 + 11x + 30 = (x + 5)(x + 6)

Substitute these factorizations back into the original expression.

$\frac{(x+5)(x-5)}{(x+5)(x+6)}$

The (x+5) terms cancel out, leaving us with the following answer:

$\frac{x-5}{x+6}$

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ACT Math : Square of Difference

Study concepts, example questions & explanations for ACT Math

All ACT Math Resources

Example Questions

Example Question #1 : How To Find The Square Of Difference

Example Question #2 : How To Find The Square Of Difference

Example Question #1 : Square Of Difference

All ACT Math Resources

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