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Common Core: 2nd Grade Math : Operations & Algebraic Thinking

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

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All Common Core: 2nd Grade Math Resources

7 Diagnostic Tests 217 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}20\\ -\ 1\end{array}}{ \ \ \ \space?}$ $\displaystyle \frac{\begin{array}[b]{r}20\\ -\ 1\end{array}}{ \ \ \ \space?}$

Possible Answers:

$\displaystyle 19$

$\displaystyle 18$

$\displaystyle 17$

$\displaystyle 15$

$\displaystyle 16$

Correct answer:

$\displaystyle 19$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 20$ and count back $\displaystyle 1.$

20,19 $\displaystyle 20,19$

$\frac{\begin{array}[b]{r}20\\ -\ 1\end{array}}{ \ \ \space19}$ $\displaystyle \frac{\begin{array}[b]{r}20\\ -\ 1\end{array}}{ \ \ \space19}$

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Example Question #2 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}19\\ -\ 2\end{array}}{ \ \ \ \space?}$ $\displaystyle \frac{\begin{array}[b]{r}19\\ -\ 2\end{array}}{ \ \ \ \space?}$

Possible Answers:

$\displaystyle 15$

$\displaystyle 17$

$\displaystyle 18$

$\displaystyle 16$

$\displaystyle 14$

Correct answer:

$\displaystyle 17$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 19$ and count back $\displaystyle 2.$

$\displaystyle 19,18,17$

$\frac{\begin{array}[b]{r}19\\ -\ 2\end{array}}{ \ \ \space17}$ $\displaystyle \frac{\begin{array}[b]{r}19\\ -\ 2\end{array}}{ \ \ \space17}$

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Example Question #3 : Operations & Algebraic Thinking

Solve the following:

$\frac{\begin{array}[b]{r}16\\ -\ 14\end{array}}{ \ \ \ \space}$ $\displaystyle \frac{\begin{array}[b]{r}16\\ -\ 14\end{array}}{ \ \ \ \space}$

Possible Answers:

$\displaystyle 3$

$\displaystyle 4$

$\displaystyle 6$

$\displaystyle 5$

$\displaystyle 2$

Correct answer:

$\displaystyle 2$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 16$ and count back 14. $\displaystyle 14.$

$\displaystyle 16, 15, 14, 13, 12, 11, 10, 9, 8, 7, 6, 5, 4, 3, 2$

$\frac{\begin{array}[b]{r}16\\ -\ 14\end{array}}{ \ \ \ \ \ \space2}$ $\displaystyle \frac{\begin{array}[b]{r}16\\ -\ 14\end{array}}{ \ \ \ \ \ \space2}$

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Example Question #4 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}13\\ -\ 6\end{array}}{ \ \ \ \space?}$ $\displaystyle \frac{\begin{array}[b]{r}13\\ -\ 6\end{array}}{ \ \ \ \space?}$

Possible Answers:

$\displaystyle 6$

$\displaystyle 5$

$\displaystyle 8$

$\displaystyle 7$

$\displaystyle 9$

Correct answer:

$\displaystyle 7$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 13$ and count back $\displaystyle 6$.

$\displaystyle 13, 12, 11, 10, 9, 8, 7$

$\frac{\begin{array}[b]{r}13\\ -\ 6\end{array}}{ \ \ \ \space7}$ $\displaystyle \frac{\begin{array}[b]{r}13\\ -\ 6\end{array}}{ \ \ \ \space7}$

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Example Question #5 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}9\\ -\ 3\end{array}}{ \ \ \ \space?}$ $\displaystyle \frac{\begin{array}[b]{r}9\\ -\ 3\end{array}}{ \ \ \ \space?}$

Possible Answers:

$\displaystyle 2$

$\displaystyle 8$

$\displaystyle 5$

$\displaystyle 6$

$\displaystyle 7$

Correct answer:

$\displaystyle 6$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 9$ and count back $\displaystyle 3$.

$\displaystyle 9, 8, 7, 6$

$\frac{\begin{array}[b]{r}9\\ -\ 3\end{array}}{ \ \ \ \space6}$ $\displaystyle \frac{\begin{array}[b]{r}9\\ -\ 3\end{array}}{ \ \ \ \space6}$

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Example Question #6 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}7\\ -\ 7\end{array}}{ \ \ \ \space?}$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 7\end{array}}{ \ \ \ \space?}$

Possible Answers:

$\displaystyle 7$

$\displaystyle 2$

$\displaystyle 3$

$\displaystyle 0$

$\displaystyle 1$

Correct answer:

$\displaystyle 0$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 7$ and count back $\displaystyle 7$.

$\displaystyle 7, 6, 5, 4, 3, 2, 1, 0$

$\frac{\begin{array}[b]{r}7\\ -\ 7\end{array}}{ \ \ \ \space0}$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 7\end{array}}{ \ \ \ \space0}$

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Example Question #7 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}6\\ -\ 5\end{array}}{ \ \ \ \space?}$ $\displaystyle \frac{\begin{array}[b]{r}6\\ -\ 5\end{array}}{ \ \ \ \space?}$

Possible Answers:

$\displaystyle 6$

$\displaystyle 0$

$\displaystyle 5$

$\displaystyle 2$

$\displaystyle 1$

Correct answer:

$\displaystyle 1$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 6$ and count back $\displaystyle 5$.

$\displaystyle 6, 5, 4, 3, 2, 1$

$\frac{\begin{array}[b]{r}6\\ -\ 5\end{array}}{ \ \ \ \space1}$ $\displaystyle \frac{\begin{array}[b]{r}6\\ -\ 5\end{array}}{ \ \ \ \space1}$

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Example Question #8 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}5\\ -\ 3\end{array}}{ \ \ \ \space?}$ $\displaystyle \frac{\begin{array}[b]{r}5\\ -\ 3\end{array}}{ \ \ \ \space?}$

Possible Answers:

$\displaystyle 2$

$\displaystyle 5$

$\displaystyle 0$

$\displaystyle 4$

$\displaystyle 1$

Correct answer:

$\displaystyle 2$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 5$ and count back $\displaystyle 3$.

$\displaystyle 5, 4, 3, 2$

$\frac{\begin{array}[b]{r}5\\ -\ 3\end{array}}{ \ \ \ \space2}$ $\displaystyle \frac{\begin{array}[b]{r}5\\ -\ 3\end{array}}{ \ \ \ \space2}$

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Example Question #9 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}4\\ -\ 1\end{array}}{ \ \ \ \space?}$ $\displaystyle \frac{\begin{array}[b]{r}4\\ -\ 1\end{array}}{ \ \ \ \space?}$

Possible Answers:

$\displaystyle 3$

$\displaystyle 2$

$\displaystyle 0$

$\displaystyle 5$

$\displaystyle 4$

Correct answer:

$\displaystyle 3$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 4$ and count back $\displaystyle 1.$

4, 3 $\displaystyle 4, 3$

$\frac{\begin{array}[b]{r}4\\ -\ 1\end{array}}{ \ \ \ \space3}$ $\displaystyle \frac{\begin{array}[b]{r}4\\ -\ 1\end{array}}{ \ \ \ \space3}$

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Example Question #10 : Operations & Algebraic Thinking

$\frac{\begin{array}[b]{r}7\\ -\ 2\end{array}}{ \ \ \ \space?}$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 2\end{array}}{ \ \ \ \space?}$

Possible Answers:

$\displaystyle 2$

$\displaystyle 5$

$\displaystyle 6$

$\displaystyle 3$

$\displaystyle 4$

Correct answer:

$\displaystyle 5$

Explanation:

To subtract we can count backwards. Start at $\displaystyle 7$ and count back $\displaystyle 2$.

7, 6, 5 $\displaystyle 7, 6, 5$

$\frac{\begin{array}[b]{r}7\\ -\ 2\end{array}}{ \ \ \ \space5}$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 2\end{array}}{ \ \ \ \space5}$

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All Common Core: 2nd Grade Math Resources

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Common Core: 2nd Grade Math : Operations & Algebraic Thinking

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

All Common Core: 2nd Grade Math Resources

Example Questions

Example Question #1 : Operations & Algebraic Thinking

Example Question #2 : Operations & Algebraic Thinking

Example Question #3 : Operations & Algebraic Thinking

Example Question #4 : Operations & Algebraic Thinking

Example Question #5 : Operations & Algebraic Thinking

Example Question #6 : Operations & Algebraic Thinking

Example Question #7 : Operations & Algebraic Thinking

Example Question #8 : Operations & Algebraic Thinking

Example Question #9 : Operations & Algebraic Thinking

Example Question #10 : Operations & Algebraic Thinking

All Common Core: 2nd Grade Math Resources

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