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Common Core: 2nd Grade Math : Subtract within 1000

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

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All Common Core: 2nd Grade Math Resources

7 Diagnostic Tests 217 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #2132 : Common Core Math: Grade 2

Solve:

$\frac{\begin{array}[b]{r}683\\ -\ 347\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}683\\ -\ 347\end{array}}{\space }$

Possible Answers:

334 $\displaystyle 334$

333 $\displaystyle 333$

335 $\displaystyle 335$

336 $\displaystyle 336$

Correct answer:

336 $\displaystyle 336$

Explanation:

When we subtract multi-digit numbers, we start with the digits in the ones place and move to the left.

Let's look at the numbers in the ones place:

$\frac{\begin{array}[b]{r}3\\ -\ 7\end{array}}{\ \ \ }$ $\displaystyle \frac{\begin{array}[b]{r}3\\ -\ 7\end{array}}{\ \ \ }$

When the top number is smaller than the bottom number, we have to borrow from the number to the left because we can't take $\displaystyle 7$ away from $\displaystyle 3$ since $\displaystyle 3$ is the smaller number. In this case, we are going to look to the $\displaystyle 8$. We only ever need to take $\displaystyle 1$ away from the number to the left. For this problem, that will leave us with a $\displaystyle 7$ to replace the $\displaystyle 8$. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}6 ^{7}\not8 \ \ \ 3\\ -\ 3\ \ \ 4\ \ \ 7\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}6 ^{7}\not8 \ \ \ 3\\ -\ 3\ \ \ 4\ \ \ 7\end{array}}{\space }$

Remember, we've borrowed $\displaystyle 1$ from the tens place, so we can put a $\displaystyle 1$ in front of the number in the ones place. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}6 ^{7}\not8 \ ^{13}\not3\\ -\ 3 \ \ \ 4\ \ \ \ \ 7\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}6 ^{7}\not8 \ ^{13}\not3\\ -\ 3 \ \ \ 4\ \ \ \ \ 7\end{array}}{\space }$

Now, let's subtract the numbers in the ones place:

$\frac{\begin{array}[b]{r}13\\ -\ 7\end{array}}{\ \ \ 6 }$ $\displaystyle \frac{\begin{array}[b]{r}13\\ -\ 7\end{array}}{\ \ \ 6 }$

Next, let's look at the numbers in the tens place:

$\frac{\begin{array}[b]{r}7\\ -\ 4\end{array}}{\ \ \ 3 }$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 4\end{array}}{\ \ \ 3 }$

Finally, we can subtract the numbers in the hundreds place:

$\frac{\begin{array}[b]{r}6\\ -\ 3\end{array}}{\ \ \ 3}$ $\displaystyle \frac{\begin{array}[b]{r}6\\ -\ 3\end{array}}{\ \ \ 3}$

Your final answer should be 336 $\displaystyle 336$

$\frac{\begin{array}[b]{r}6 ^{7}\not8 \ ^{13}\not3\\ -\ 3 \ \ \ 4\ \ \ \ \ 7\end{array}}{\ \ \ 3\ \ \ 3\ \ \ \ 6 }$ $\displaystyle \frac{\begin{array}[b]{r}6 ^{7}\not8 \ ^{13}\not3\\ -\ 3 \ \ \ 4\ \ \ \ \ 7\end{array}}{\ \ \ 3\ \ \ 3\ \ \ \ 6 }$

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Example Question #2133 : Common Core Math: Grade 2

Solve:

$\frac{\begin{array}[b]{r}817\\ -\ 670\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}817\\ -\ 670\end{array}}{\space }$

Possible Answers:

146 $\displaystyle 146$

148 $\displaystyle 148$

147 $\displaystyle 147$

145 $\displaystyle 145$

Correct answer:

147 $\displaystyle 147$

Explanation:

When we subtract multi-digit numbers, we start with the digits in the ones place and move to the left.

Let's look at the numbers in the ones place:

$\frac{\begin{array}[b]{r}7\\ -\ 0\end{array}}{\ \ \ 7 }$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 0\end{array}}{\ \ \ 7 }$

Next, let's look at the numbers in the tens place:

$\frac{\begin{array}[b]{r}1\\ -\ 7\end{array}}{\ \ \ }$ $\displaystyle \frac{\begin{array}[b]{r}1\\ -\ 7\end{array}}{\ \ \ }$

When the top number is smaller than the bottom number, we have to borrow from the number to the left because we can't take $\displaystyle 7$ away from $\displaystyle 1$ since $\displaystyle 1$ is the smaller number. In this case, we are going to look to the $\displaystyle 8$. We only ever need to take $\displaystyle 1$ away from the number to the left. For this problem, that will leave us with a $\displaystyle 7$ to replace the $\displaystyle 8$. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}^{7}\not817\\ -\ 670\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}^{7}\not817\\ -\ 670\end{array}}{\space }$

Remember, we've borrowed $\displaystyle 1$ from the hundreds place, so we can put a $\displaystyle 1$ in front of the number in the tens place. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}^{7} \not8\ ^{11}\not1\ \ \ \ \ 7\\ -\ 6 \ \ \ \ \ 7\ \ \ \ \ 0\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}^{7} \not8\ ^{11}\not1\ \ \ \ \ 7\\ -\ 6 \ \ \ \ \ 7\ \ \ \ \ 0\end{array}}{\space }$

Now, we can subtract the numbers in the tens place:

$\frac{\begin{array}[b]{r}11\\ -\ 7\end{array}}{\ \ \ 4}$ $\displaystyle \frac{\begin{array}[b]{r}11\\ -\ 7\end{array}}{\ \ \ 4}$

Next, we can subtract the numbers in the hundreds place:

$\frac{\begin{array}[b]{r}7\\ -\ 6\end{array}}{\ \ \ 1}$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 6\end{array}}{\ \ \ 1}$

Your final answer should be 147 $\displaystyle 147$

$\frac{\begin{array}[b]{r}^{7} \not8\ ^{11}\not1\ \ \ \ \ 7\\ -\ 6 \ \ \ \ \ 7\ \ \ \ \ 0\end{array}}{\ \ \ 1\ \ \ \ \ 4\ \ \ \ \ \ 7}$ $\displaystyle \frac{\begin{array}[b]{r}^{7} \not8\ ^{11}\not1\ \ \ \ \ 7\\ -\ 6 \ \ \ \ \ 7\ \ \ \ \ 0\end{array}}{\ \ \ 1\ \ \ \ \ 4\ \ \ \ \ \ 7}$

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Example Question #2134 : Common Core Math: Grade 2

Solve:

$\frac{\begin{array}[b]{r}316\\ -\ 250\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}316\\ -\ 250\end{array}}{\space }$

Possible Answers:

$\displaystyle 66$

$\displaystyle 68$

$\displaystyle 65$

$\displaystyle 67$

Correct answer:

$\displaystyle 66$

Explanation:

When we subtract multi-digit numbers, we start with the digits in the ones place and move to the left.

Let's look at the numbers in the ones place:

$\frac{\begin{array}[b]{r}6\\ -\ 0\end{array}}{\ \ \ 6 }$ $\displaystyle \frac{\begin{array}[b]{r}6\\ -\ 0\end{array}}{\ \ \ 6 }$

Next, let's look at the numbers in the tens place:

$\frac{\begin{array}[b]{r}1\\ -\ 5\end{array}}{\ \ \ }$ $\displaystyle \frac{\begin{array}[b]{r}1\\ -\ 5\end{array}}{\ \ \ }$

When the top number is smaller than the bottom number, we have to borrow from the number to the left because we can't take $\displaystyle 5$ away from $\displaystyle 1$ since $\displaystyle 1$ is the smaller number. In this case, we are going to look to the $\displaystyle 3$. We only ever need to take $\displaystyle 1$ away from the number to the left. For this problem, that will leave us with a $\displaystyle 2$ to replace the $\displaystyle 3$. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}^{2} \not316\\ -\ 250\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}^{2} \not316\\ -\ 250\end{array}}{\space }$

Remember, we've borrowed $\displaystyle 1$ from the hundreds place, so we can put a $\displaystyle 1$ in front of the number in the tens place. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}^{2} \not3\ ^{11}\not1\ \ \ \ \ 6\\ -\ 2 \ \ \ \ \ 5\ \ \ \ \ 0\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}^{2} \not3\ ^{11}\not1\ \ \ \ \ 6\\ -\ 2 \ \ \ \ \ 5\ \ \ \ \ 0\end{array}}{\space }$

Now, we can subtract the numbers in the tens place:

$\frac{\begin{array}[b]{r}11\\ -\ 5\end{array}}{\ \ \ 6}$ $\displaystyle \frac{\begin{array}[b]{r}11\\ -\ 5\end{array}}{\ \ \ 6}$

Next, we can subtract the numbers in the hundreds place:

$\frac{\begin{array}[b]{r}2\\ -\ 2\end{array}}{\ \ \ 0}$ $\displaystyle \frac{\begin{array}[b]{r}2\\ -\ 2\end{array}}{\ \ \ 0}$

Your final answer should be $\displaystyle 66$

$\frac{\begin{array}[b]{r}^{2} \not3\ ^{11}\not1\ \ \ \ \ 6\\ -\ 2 \ \ \ \ \ 5\ \ \ \ \ 0\end{array}}{\ \ \ \ \ \ \ \ \ \ 6\ \ \ \ \ 6}$ $\displaystyle \frac{\begin{array}[b]{r}^{2} \not3\ ^{11}\not1\ \ \ \ \ 6\\ -\ 2 \ \ \ \ \ 5\ \ \ \ \ 0\end{array}}{\ \ \ \ \ \ \ \ \ \ 6\ \ \ \ \ 6}$

Report an Error

Example Question #2135 : Common Core Math: Grade 2

Solve:

$\frac{\begin{array}[b]{r}325\\ -\ 289\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}325\\ -\ 289\end{array}}{\space }$

Possible Answers:

$\displaystyle 36$

$\displaystyle 37$

$\displaystyle 38$

$\displaystyle 35$

Correct answer:

$\displaystyle 36$

Explanation:

When we subtract multi-digit numbers, we start with the digits in the ones place and move to the left.

Let's look at the numbers in the ones place:

$\frac{\begin{array}[b]{r}5\\ -\ 9\end{array}}{\ \ \ }$ $\displaystyle \frac{\begin{array}[b]{r}5\\ -\ 9\end{array}}{\ \ \ }$

When the top number is smaller than the bottom number, we have to borrow from the number to the left because we can't take $\displaystyle 9$ away from $\displaystyle 5$ since $\displaystyle 5$ is the smaller number. In this case, we are going to look to the $\displaystyle 2$. We only ever need to take $\displaystyle 1$ away from the number to the left. For this problem, that will leave us with a $\displaystyle 1$ to replace the $\displaystyle 2$. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}3 ^{1}\not2 \ \ \ 5\\ -\ 2\ \ \ 8\ \ \ 9\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}3 ^{1}\not2 \ \ \ 5\\ -\ 2\ \ \ 8\ \ \ 9\end{array}}{\space }$

Remember, we've borrowed $\displaystyle 1$ from the tens place, so we can put a $\displaystyle 1$ in front of the number in the ones place. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}3 ^{1}\not2 \ ^{15}\not5\\ -\ 2 \ \ \ 8\ \ \ \ \ 9\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}3 ^{1}\not2 \ ^{15}\not5\\ -\ 2 \ \ \ 8\ \ \ \ \ 9\end{array}}{\space }$

Now, let's subtract the numbers in the ones place:

$\frac{\begin{array}[b]{r}15\\ -\ 9\end{array}}{\ \ \ 6 }$ $\displaystyle \frac{\begin{array}[b]{r}15\\ -\ 9\end{array}}{\ \ \ 6 }$

Next, let's look at the numbers in the tens place:

$\frac{\begin{array}[b]{r}1\\ -\ 8\end{array}}{\ \ \ }$ $\displaystyle \frac{\begin{array}[b]{r}1\\ -\ 8\end{array}}{\ \ \ }$

When the top number is smaller than the bottom number, we have to borrow from the number to the left because we can't take $\displaystyle 8$ away from $\displaystyle 1$ since $\displaystyle 1$ is the smaller number. In this case, we are going to look to the $\displaystyle 3$. We only ever need to take $\displaystyle 1$ away from the number to the left. For this problem, that will leave us with a $\displaystyle 2$ to replace the $\displaystyle 3$. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}^{2}\not3 ^{1}\not2 \ ^{15}\not5\\ -\ 2 \ \ \ 8\ \ \ \ \ 9\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}^{2}\not3 ^{1}\not2 \ ^{15}\not5\\ -\ 2 \ \ \ 8\ \ \ \ \ 9\end{array}}{\space }$

Remember, we've borrowed $\displaystyle 1$ from the hundreds place, so we can put a $\displaystyle 1$ in front of the number in the tens place. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}^{2}\not3 ^{11}\not2 \ ^{15}\not5\\ -\ 2 \ \ \ 8\ \ \ \ \ 9\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}^{2}\not3 ^{11}\not2 \ ^{15}\not5\\ -\ 2 \ \ \ 8\ \ \ \ \ 9\end{array}}{\space }$

Now, let's subtract the numbers in the tens place:

$\frac{\begin{array}[b]{r}11\\ -\ 8\end{array}}{\ \ \ 3 }$ $\displaystyle \frac{\begin{array}[b]{r}11\\ -\ 8\end{array}}{\ \ \ 3 }$

Finally, we can subtract the numbers in the hundreds place:

$\frac{\begin{array}[b]{r}2\\ -\ 2\end{array}}{\ \ \ 0}$ $\displaystyle \frac{\begin{array}[b]{r}2\\ -\ 2\end{array}}{\ \ \ 0}$

Your final answer should be $\displaystyle 36$

$\frac{\begin{array}[b]{r}^{2}\not3 ^{11}\not2 \ ^{15}\not5\\ -\ 2 \ \ \ 8\ \ \ \ \ 9\end{array}}{\ \ \ \ \ \ \ \ 3\ \ \ \ \ 6 }$ $\displaystyle \frac{\begin{array}[b]{r}^{2}\not3 ^{11}\not2 \ ^{15}\not5\\ -\ 2 \ \ \ 8\ \ \ \ \ 9\end{array}}{\ \ \ \ \ \ \ \ 3\ \ \ \ \ 6 }$

Report an Error

Example Question #2136 : Common Core Math: Grade 2

Solve:

$\frac{\begin{array}[b]{r}818\\ -\ 181\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}818\\ -\ 181\end{array}}{\space }$

Possible Answers:

636 $\displaystyle 636$

635 $\displaystyle 635$

637 $\displaystyle 637$

634 $\displaystyle 634$

Correct answer:

637 $\displaystyle 637$

Explanation:

When we subtract multi-digit numbers, we start with the digits in the ones place and move to the left.

Let's look at the numbers in the ones place:

$\frac{\begin{array}[b]{r}8\\ -\ 1\end{array}}{\ \ \ 7 }$ $\displaystyle \frac{\begin{array}[b]{r}8\\ -\ 1\end{array}}{\ \ \ 7 }$

Next, let's look at the numbers in the tens place:

$\frac{\begin{array}[b]{r}1\\ -\ 8\end{array}}{\ \ \ }$ $\displaystyle \frac{\begin{array}[b]{r}1\\ -\ 8\end{array}}{\ \ \ }$

When the top number is smaller than the bottom number, we have to borrow from the number to the left because we can't take $\displaystyle 8$ away from $\displaystyle 1$ since $\displaystyle 1$ is the smaller number. In this case, we are going to look to the $\displaystyle 8$. We only ever need to take $\displaystyle 1$ away from the number to the left. For this problem, that will leave us with a $\displaystyle 7$ to replace the $\displaystyle 8$. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}^{7} \not818\\ -\ 181\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}^{7} \not818\\ -\ 181\end{array}}{\space }$

Remember, we've borrowed $\displaystyle 1$ from the hundreds place, so we can put a $\displaystyle 1$ in front of the number in the tens place. So far, your work should look something like this:

$\frac{\begin{array}[b]{r}^{7} \not8\ ^{11}\not1\ \ \ \ \ 8\\ -\ 1 \ \ \ \ \ 8\ \ \ \ \ 1\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}^{7} \not8\ ^{11}\not1\ \ \ \ \ 8\\ -\ 1 \ \ \ \ \ 8\ \ \ \ \ 1\end{array}}{\space }$

Now, we can subtract the numbers in the tens place:

$\frac{\begin{array}[b]{r}11\\ -\ 8\end{array}}{\ \ \ 3}$ $\displaystyle \frac{\begin{array}[b]{r}11\\ -\ 8\end{array}}{\ \ \ 3}$

Next, we can subtract the numbers in the hundreds place:

$\frac{\begin{array}[b]{r}7\\ -\ 1\end{array}}{\ \ \ 6}$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 1\end{array}}{\ \ \ 6}$

Your final answer should be 637 $\displaystyle 637$

$\frac{\begin{array}[b]{r}^{7} \not8\ ^{11}\not1\ \ \ \ \ 8\\ -\ 1 \ \ \ \ \ 8\ \ \ \ \ 1\end{array}}{\ \ \ 6 \ \ \ \ \ 3\ \ \ \ \ 7 }$ $\displaystyle \frac{\begin{array}[b]{r}^{7} \not8\ ^{11}\not1\ \ \ \ \ 8\\ -\ 1 \ \ \ \ \ 8\ \ \ \ \ 1\end{array}}{\ \ \ 6 \ \ \ \ \ 3\ \ \ \ \ 7 }$

Report an Error

Example Question #1 : Subtract Within 1000

Solve:

$\frac{\begin{array}[b]{r}979\\ -\ 930\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}979\\ -\ 930\end{array}}{\space }$

Possible Answers:

$\displaystyle 48$

$\displaystyle 47$

$\displaystyle 49$

$\displaystyle 50$

Correct answer:

$\displaystyle 49$

Explanation:

When we subtract multi-digit numbers, we start with the digits in the ones place and move to the left.

Let's look at the numbers in the ones place:

$\frac{\begin{array}[b]{r}9\\ -\ 0\end{array}}{\ \ \ 9 }$ $\displaystyle \frac{\begin{array}[b]{r}9\\ -\ 0\end{array}}{\ \ \ 9 }$

Next, let's look at the numbers in the tens place:

$\frac{\begin{array}[b]{r}7\\ -\ 3\end{array}}{\ \ \ 4 }$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 3\end{array}}{\ \ \ 4 }$

Finally, we can subtract the numbers in the hundreds place:

$\frac{\begin{array}[b]{r}9\\ -\ 9\end{array}}{\ \ \ 0}$ $\displaystyle \frac{\begin{array}[b]{r}9\\ -\ 9\end{array}}{\ \ \ 0}$

Your final answer should be $\displaystyle 49$

$\frac{\begin{array}[b]{r}979\\ -\ 930\end{array}}{\ \ \ \ \ 49}$ $\displaystyle \frac{\begin{array}[b]{r}979\\ -\ 930\end{array}}{\ \ \ \ \ 49}$

Report an Error

Example Question #2 : Subtract Within 1000

Solve:

$\frac{\begin{array}[b]{r}439\\ -\ 438\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}439\\ -\ 438\end{array}}{\space }$

Possible Answers:

$\displaystyle 3$

$\displaystyle 1$

$\displaystyle 4$

$\displaystyle 2$

Correct answer:

$\displaystyle 1$

Explanation:

When we subtract multi-digit numbers, we start with the digits in the ones place and move to the left.

Let's look at the numbers in the ones place:

$\frac{\begin{array}[b]{r}9\\ -\ 8\end{array}}{\ \ \ 1 }$ $\displaystyle \frac{\begin{array}[b]{r}9\\ -\ 8\end{array}}{\ \ \ 1 }$

Next, let's look at the numbers in the tens place:

$\frac{\begin{array}[b]{r}3\\ -\ 3\end{array}}{\ \ \ 0 }$ $\displaystyle \frac{\begin{array}[b]{r}3\\ -\ 3\end{array}}{\ \ \ 0 }$

Finally, we can subtract the numbers in the hundreds place:

$\frac{\begin{array}[b]{r}4\\ -\ 4\end{array}}{\ \ \ 0}$ $\displaystyle \frac{\begin{array}[b]{r}4\\ -\ 4\end{array}}{\ \ \ 0}$

Your final answer should be $\displaystyle 1$

$\frac{\begin{array}[b]{r}439\\ -\ 438\end{array}}{\ \ \ \ \ \ \ 1}$ $\displaystyle \frac{\begin{array}[b]{r}439\\ -\ 438\end{array}}{\ \ \ \ \ \ \ 1}$

Report an Error

Example Question #3 : Subtract Within 1000

Solve:

$\frac{\begin{array}[b]{r}810\\ -\ 110\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}810\\ -\ 110\end{array}}{\space }$

Possible Answers:

700 $\displaystyle 700$

702 $\displaystyle 702$

701 $\displaystyle 701$

703 $\displaystyle 703$

Correct answer:

700 $\displaystyle 700$

Explanation:

When we subtract multi-digit numbers, we start with the digits in the ones place and move to the left.

Let's look at the numbers in the ones place:

$\frac{\begin{array}[b]{r}0\\ -\ 0\end{array}}{\ \ \ 0 }$ $\displaystyle \frac{\begin{array}[b]{r}0\\ -\ 0\end{array}}{\ \ \ 0 }$

Next, let's look at the numbers in the tens place:

$\frac{\begin{array}[b]{r}1\\ -\ 1\end{array}}{\ \ \ 0 }$ $\displaystyle \frac{\begin{array}[b]{r}1\\ -\ 1\end{array}}{\ \ \ 0 }$

Finally, we can subtract the numbers in the hundreds place:

$\frac{\begin{array}[b]{r}8\\ -\ 1\end{array}}{\ \ \ 7}$ $\displaystyle \frac{\begin{array}[b]{r}8\\ -\ 1\end{array}}{\ \ \ 7}$

Your final answer should be 700 $\displaystyle 700$

$\frac{\begin{array}[b]{r}810\\ -\ 110\end{array}}{\ \ \ 700}$ $\displaystyle \frac{\begin{array}[b]{r}810\\ -\ 110\end{array}}{\ \ \ 700}$

Report an Error

Example Question #4 : Subtract Within 1000

Solve:

$\frac{\begin{array}[b]{r}596\\ -\ 335\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}596\\ -\ 335\end{array}}{\space }$

Possible Answers:

261 $\displaystyle 261$

260 $\displaystyle 260$

262 $\displaystyle 262$

263 $\displaystyle 263$

Correct answer:

261 $\displaystyle 261$

Explanation:

When we subtract multi-digit numbers, we start with the digits in the ones place and move to the left.

Let's look at the numbers in the ones place:

$\frac{\begin{array}[b]{r}6\\ -\ 5\end{array}}{\ \ \ 1 }$ $\displaystyle \frac{\begin{array}[b]{r}6\\ -\ 5\end{array}}{\ \ \ 1 }$

Next, let's look at the numbers in the tens place:

$\frac{\begin{array}[b]{r}9\\ -\ 3\end{array}}{\ \ \ 6 }$ $\displaystyle \frac{\begin{array}[b]{r}9\\ -\ 3\end{array}}{\ \ \ 6 }$

Finally, we can subtract the numbers in the hundreds place:

$\frac{\begin{array}[b]{r}5\\ -\ 3\end{array}}{\ \ \ 2}$ $\displaystyle \frac{\begin{array}[b]{r}5\\ -\ 3\end{array}}{\ \ \ 2}$

Your final answer should be 261 $\displaystyle 261$

$\frac{\begin{array}[b]{r}596\\ -\ 335\end{array}}{\ \ \ \ 261}$ $\displaystyle \frac{\begin{array}[b]{r}596\\ -\ 335\end{array}}{\ \ \ \ 261}$

Report an Error

Example Question #5 : Subtract Within 1000

Solve:

$\frac{\begin{array}[b]{r}374\\ -\ 231\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}374\\ -\ 231\end{array}}{\space }$

Possible Answers:

140 $\displaystyle 140$

143 $\displaystyle 143$

142 $\displaystyle 142$

141 $\displaystyle 141$

Correct answer:

143 $\displaystyle 143$

Explanation:

When we subtract multi-digit numbers, we start with the digits in the ones place and move to the left.

Let's look at the numbers in the ones place:

$\frac{\begin{array}[b]{r}4\\ -\ 1\end{array}}{\ \ \ 3 }$ $\displaystyle \frac{\begin{array}[b]{r}4\\ -\ 1\end{array}}{\ \ \ 3 }$

Next, let's look at the numbers in the tens place:

$\frac{\begin{array}[b]{r}7\\ -\ 3\end{array}}{\ \ \ 4 }$ $\displaystyle \frac{\begin{array}[b]{r}7\\ -\ 3\end{array}}{\ \ \ 4 }$

Finally, we can subtract the numbers in the hundreds place:

$\frac{\begin{array}[b]{r}3\\ -\ 2\end{array}}{\ \ \ 1}$ $\displaystyle \frac{\begin{array}[b]{r}3\\ -\ 2\end{array}}{\ \ \ 1}$

Your final answer should be 143 $\displaystyle 143$

$\frac{\begin{array}[b]{r}374\\ -\ 231\end{array}}{\ \ \ \ 143}$ $\displaystyle \frac{\begin{array}[b]{r}374\\ -\ 231\end{array}}{\ \ \ \ 143}$

Report an Error

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Common Core: 2nd Grade Math : Subtract within 1000

Study concepts, example questions & explanations for Common Core: 2nd Grade Math

All Common Core: 2nd Grade Math Resources

Example Questions

Example Question #2132 : Common Core Math: Grade 2

Example Question #2133 : Common Core Math: Grade 2

Example Question #2134 : Common Core Math: Grade 2

Example Question #2135 : Common Core Math: Grade 2

Example Question #2136 : Common Core Math: Grade 2

Example Question #1 : Subtract Within 1000

Example Question #2 : Subtract Within 1000

Example Question #3 : Subtract Within 1000

Example Question #4 : Subtract Within 1000

Example Question #5 : Subtract Within 1000

All Common Core: 2nd Grade Math Resources

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