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Common Core: 4th Grade Math : Adding multi-digit numbers

Study concepts, example questions & explanations for Common Core: 4th Grade Math

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All Common Core: 4th Grade Math Resources

7 Diagnostic Tests 189 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Adding Multi Digit Numbers

Solve:

$\frac{\begin{array}[b]{r}687\\ +\ 410\end{array}}{\space }$

Possible Answers:

$1\textup,098$

$1\textup,095$

$1\textup,096$

$1\textup,097$

Correct answer:

$1\textup,097$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

7+0=7

Add the numbers in the tens place:

8+1=9

Add the numbers in the hundreds place:

6+4=10

Your final answer should be 1097:

$\frac{\begin{array}[b]{r}687\\ +\ 410\end{array}}{\ \ 1097}$

Report an Error

Example Question #2 : Adding Multi Digit Numbers

Solve:

$\frac{\begin{array}[b]{r}412\\ +\ 896\end{array}}{\space }$

Possible Answers:

$1\textup,309$

$1\textup,307$

$1\textup,310$

$1\textup,308$

Correct answer:

$1\textup,308$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

2+6=8

Add the numbers in the tens place:

1+9=10

Because this sum is greater than , we write the from the ones place and carry the from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}^{{\color{Red} 1}}412\\ +\ 896\end{array}}{\ \ \ \ \ 08 }$

Add the numbers in the hundreds place, including the that was carried over:

1+4+8=13

Your final answer should be 1308:

$\frac{\begin{array}[b]{r}^{1}412\\ +\ 896\end{array}}{\ \ 1308 }$

Report an Error

Example Question #3 : Adding Multi Digit Numbers

Solve:

$\frac{\begin{array}[b]{r}569\\ +\ 221\end{array}}{\space }$

Possible Answers:

790

791

793

792

Correct answer:

790

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

9+1=10

Because this sum is greater than , we write the from the ones place and carry the from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}5^{{\color{Red} 1}}6\ 9\\ +\ 2\ 2\ 1\end{array}}{\ \ \ \ \ \ \ \ 0 }$

Add the numbers in the tens place, including the that was carried over:

1+6+2=9

Add the numbers in the hundreds place:

5+2=7

Your final answer should be 790:

$\frac{\begin{array}[b]{r}569\\ +\ 221\end{array}}{\ \ \ 790 }$

Report an Error

Example Question #4 : Adding Multi Digit Numbers

Solve:

$\frac{\begin{array}[b]{r}495\\ +\ 519\end{array}}{\space }$

Possible Answers:

$1\textup,014$

$1\textup,013$

$1\textup,012$

$1\textup,011$

Correct answer:

$1\textup,014$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

5+9=14

Because this sum is greater than , we write the from the ones place and carry the from he tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}4^{{\color{Red} 1}}9\ 5\\ +\ 5\ 1\ 9\end{array}}{\ \ \ \ \ \ \ \ 4 }$

Add the numbers in the tens place, including the that was carried over:

1+9+1=11

Because this sum is greater than , we write the from the ones place and carry the from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}^{{\color{Red} 1}}4^{{\color{Red} 1}}9\ 5\\ +\ 5\ 1\ 9\end{array}}{\ \ \ \ \ \ 1\ 4 }$

Add the numbers in the hundreds place, including the that was carried over:

1+4+5=10

Your final answer should be 1014:

$\frac{\begin{array}[b]{r}295\\ +\ 519\end{array}}{\ \ 1014}$

Report an Error

Example Question #5 : Adding Multi Digit Numbers

Solve:

$\frac{\begin{array}[b]{r}700\\ +\ 224\end{array}}{\space }$

Possible Answers:

923

925

924

922

Correct answer:

924

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

0+4=4

Add the numbers in the tens place:

0+2=2

Add the numbers in the hundreds place:

7+2=9

Your final answer should be 924:

$\frac{\begin{array}[b]{r}700\\ +\ 224\end{array}}{\ \ \ 924 }$

Report an Error

Example Question #6 : Adding Multi Digit Numbers

Solve:

$\frac{\begin{array}[b]{r}469\\ +\ 323\end{array}}{\space }$

Possible Answers:

790

791

793

792

Correct answer:

792

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

9+3=12

Because this sum is greater than , we write the from the ones place and carry the from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}4^{{\color{Red} 1}}6\ 9\\ +\ 3\ 2\ 3\end{array}}{\ \ \ \ \ \ \ \ 2 }$

Add the numbers in the tens place, including the that was carried over:

1+6+2=9

Add the numbers in the hundreds place:

4+3=7

Your final answer should be 792:

$\frac{\begin{array}[b]{r}469\\ +\ 323\end{array}}{\ \ \ 792 }$

Report an Error

Example Question #7 : Adding Multi Digit Numbers

Solve:

$\frac{\begin{array}[b]{r}428\\ +\ 548\end{array}}{\space }$

Possible Answers:

975

976

974

973

Correct answer:

976

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

8+8=16

Because this sum is greater than , we write the from the ones place and carry the from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}4^{{\color{Red} 1}}2\ 8\\ +\ 5\ 4\ 8\end{array}}{\ \ \ \ \ \ \ \ 6 }$

Add the numbers in the tens place, including the that was carried over:

1+2+4=7

Add the numbers in the hundreds place:

4+5=9

Your final answer should be 976:

$\frac{\begin{array}[b]{r}428\\ +\ 548\end{array}}{\ \ \ 976}$

Report an Error

Example Question #1291 : Common Core Math: Grade 4

Solve:

$\frac{\begin{array}[b]{r}707\\ +\ 328\end{array}}{\space }$

Possible Answers:

$1\textup,034$

$1\textup,035$

$1\textup,037$

$1\textup,036$

Correct answer:

$1\textup,035$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

7+8=15

Because this sum is greater than , we write the from the ones place and carry the from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}7^{{\color{Red} 1}}0\ 7\\ +\ 3\ 2\ 8\end{array}}{\ \ \ \ \ \ \ \ 5 }$

Add the numbers in the tens place, including the that was carried over:

1+0+2=3

Add the numbers in the hundreds place:

7+3=10

Your final answer should be 1035:

$\frac{\begin{array}[b]{r}707\\ +\ 328\end{array}}{\ \ 1035}$

Report an Error

Example Question #1292 : Common Core Math: Grade 4

Solve:

$\frac{\begin{array}[b]{r}411\\ +\ 221\end{array}}{\space }$

Possible Answers:

633

634

632

635

Correct answer:

632

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

1+1=2

Add the numbers in the tens place:

1+2=3

Add the numbers in the hundreds place:

4+2=4

Your final answer should be 632:

$\frac{\begin{array}[b]{r}411\\ +\ 221\end{array}}{\ \ \ 632}$

Report an Error

Example Question #1293 : Common Core Math: Grade 4

Solve the following:

$\frac{\begin{array}[b]{r}935\\ +\ 204\end{array}}{\space }$

Possible Answers:

$1\textup,139$

$1\textup,137$

$1\textup,136$

$1\textup,138$

Correct answer:

$1\textup,139$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

5+4=9

Add the numbers in the tens place:

3+0=3

Add the numbers in the hundreds place:

9+2=11

Your final answer should be 1139:

$\frac{\begin{array}[b]{r}935\\ +\ 204\end{array}}{\ \ 1139 }$

Report an Error

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Common Core: 4th Grade Math : Adding multi-digit numbers

Study concepts, example questions & explanations for Common Core: 4th Grade Math

All Common Core: 4th Grade Math Resources

Example Questions

Example Question #1 : Adding Multi Digit Numbers

Example Question #2 : Adding Multi Digit Numbers

Example Question #3 : Adding Multi Digit Numbers

Example Question #4 : Adding Multi Digit Numbers

Example Question #5 : Adding Multi Digit Numbers

Example Question #6 : Adding Multi Digit Numbers

Example Question #7 : Adding Multi Digit Numbers

Example Question #1291 : Common Core Math: Grade 4

Example Question #1292 : Common Core Math: Grade 4

Example Question #1293 : Common Core Math: Grade 4

All Common Core: 4th Grade Math Resources

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