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Flashcards: Similar Circles: CCSS.Math.Content.HSG-C.A.1

Given $\frac{C}{C'}=25$ $\displaystyle \frac{C}{C'}=25$ , and R=4 $\displaystyle R=4$ , what is R'? $\displaystyle R'?$

Screen shot 2020 07 01 at 7.06.26 pm

R'=25 $\displaystyle R'=25$

$R'=\frac{25}{4}$ $\displaystyle R'=\frac{25}{4}$

R'=100 $\displaystyle R'=100$

$R'=\frac{4}{25}$ $\displaystyle R'=\frac{4}{25}$

R'=4 $\displaystyle R'=4$

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Flashcards: Similar Circles: CCSS.Math.Content.HSG-C.A.1

Given $\frac{C}{C'}=25$ $\displaystyle \frac{C}{C'}=25$ , and R=4 $\displaystyle R=4$ , what is R'? $\displaystyle R'?$

Screen shot 2020 07 01 at 7.06.26 pm

R'=25 $\displaystyle R'=25$

$R'=\frac{25}{4}$ $\displaystyle R'=\frac{25}{4}$

R'=100 $\displaystyle R'=100$

$R'=\frac{4}{25}$ $\displaystyle R'=\frac{4}{25}$

R'=4 $\displaystyle R'=4$

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Flashcards: Similar Circles: CCSS.Math.Content.HSG-C.A.1

Given $\frac{C}{C'}=25$ $\displaystyle \frac{C}{C'}=25$ , and R=4 $\displaystyle R=4$ , what is R'? $\displaystyle R'?$

Screen shot 2020 07 01 at 7.06.26 pm

Your answer:

R'=25 $\displaystyle R'=25$

Your answer:

$R'=\frac{25}{4}$ $\displaystyle R'=\frac{25}{4}$

Your answer:

R'=100 $\displaystyle R'=100$

Your answer:

R'=4 $\displaystyle R'=4$

Correct answer:

$R'=\frac{4}{25}$ $\displaystyle R'=\frac{4}{25}$

Explanation:

In order to do this problem, we need to remember the relationship between Circumference's, and Radii. $\frac{C}{C'}=\frac{R}{R'}$ $\displaystyle \frac{C}{C'}=\frac{R}{R'}$ . With this relationship, we can determine what $\displaystyle R'$ is.

$\frac{C}{C'}=\frac{R}{R'}$ $\displaystyle \frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$25=\frac{4}{R'}$ $\displaystyle 25=\frac{4}{R'}$

Multiply by $\displaystyle R'$ on each side.

25R'=4 $\displaystyle 25R'=4$

Divide by $\displaystyle 25$ to get $\displaystyle R'$ .

$R'=\frac{4}{25}$ $\displaystyle R'=\frac{4}{25}$

Flashcards: Similar Circles: CCSS.Math.Content.HSG-C.A.1

Given $\frac{C}{C'}=118$ $\displaystyle \frac{C}{C'}=118$ , and R=12 $\displaystyle R=12$ , what is R'? $\displaystyle R'?$

Screen shot 2020 07 01 at 7.06.26 pm

$R'=\frac{6}{59}$ $\displaystyle R'=\frac{6}{59}$

R'=6 $\displaystyle R'=6$

$R'=\frac{1}{118}$ $\displaystyle R'=\frac{1}{118}$

R'=59 $\displaystyle R'=59$

R'=118 $\displaystyle R'=118$

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Flashcards: Similar Circles: CCSS.Math.Content.HSG-C.A.1

Given $\frac{C}{C'}=118$ $\displaystyle \frac{C}{C'}=118$ , and R=12 $\displaystyle R=12$ , what is R'? $\displaystyle R'?$

Screen shot 2020 07 01 at 7.06.26 pm

Your answer:

R'=6 $\displaystyle R'=6$

Your answer:

$R'=\frac{1}{118}$ $\displaystyle R'=\frac{1}{118}$

Your answer:

R'=59 $\displaystyle R'=59$

Your answer:

R'=118 $\displaystyle R'=118$

Correct answer:

$R'=\frac{6}{59}$ $\displaystyle R'=\frac{6}{59}$

Explanation:

$\frac{C}{C'}=\frac{R}{R'}$ $\displaystyle \frac{C}{C'}=\frac{R}{R'}$

Substitute for the variables given in the question.

$118=\frac{12}{R'}$ $\displaystyle 118=\frac{12}{R'}$

Multiply by $\displaystyle R'$ on each side.

$\displaystyle 118R'=12$

Divide by 118 $\displaystyle 118$ to get $\displaystyle R'$ .

$R'=\frac{12}{118}=\frac{6}{59}$ $\displaystyle R'=\frac{12}{118}=\frac{6}{59}$

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Flashcards: Similar Circles: CCSS.Math.Content.HSG-C.A.1

All Common Core: High School - Geometry Resources

Flashcards: Similar Circles: CCSS.Math.Content.HSG-C.A.1

Flashcards: Similar Circles: CCSS.Math.Content.HSG-C.A.1

Flashcards: Similar Circles: CCSS.Math.Content.HSG-C.A.1

Flashcards: Similar Circles: CCSS.Math.Content.HSG-C.A.1

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