Call Now to Set Up Tutoring:

(888) 888-0446

Common Core: High School - Geometry : Apply Density Concepts to Area and Volume Situations: CCSS.Math.Content.HSG-MG.A.2

Study concepts, example questions & explanations for Common Core: High School - Geometry

Create An Account

All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 58398 cubic meters of xenon with a density of 0.1629 kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to 2 decimal places

Possible Answers:

$58397.84 \text{ kilograms}$ $\displaystyle 58397.84 \text{ kilograms}$

$4756.52 \text{ kilograms}$ $\displaystyle 4756.52 \text{ kilograms}$

$9513.03 \text{ kilograms}$ $\displaystyle 9513.03 \text{ kilograms}$

$58398.16 \text{ kilograms}$ $\displaystyle 58398.16 \text{ kilograms}$

$358489.87 \text{ kilograms}$ $\displaystyle 358489.87 \text{ kilograms}$

Correct answer:

$9513.03 \text{ kilograms}$ $\displaystyle 9513.03 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$ $\displaystyle d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ( $\uptext{m}$ $\displaystyle \uptext{m}$).

$0.1629 = \frac{m}{58398}$ $\displaystyle 0.1629 = \frac{m}{58398}$

$\displaystyle m = 9513.03$

Thus the mass of the balloon is 9513.03 kilograms.

Report an Error

Example Question #2 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 53678 $\displaystyle 53678$ cubic meters of xenon with a density of 0.9606 $\displaystyle 0.9606$ kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to $\displaystyle 2$ decimal places.

Possible Answers:

$51563.09 \text{ kilograms}$ $\displaystyle 51563.09 \text{ kilograms}$

$53678.96 \text{ kilograms}$ $\displaystyle 53678.96 \text{ kilograms}$

$55879.66 \text{ kilograms}$ $\displaystyle 55879.66 \text{ kilograms}$

$25781.54 \text{ kilograms}$ $\displaystyle 25781.54 \text{ kilograms}$

$53677.04 \text{ kilograms}$ $\displaystyle 53677.04 \text{ kilograms}$

Correct answer:

$51563.09 \text{ kilograms}$ $\displaystyle 51563.09 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$ $\displaystyle d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ($\displaystyle m$).

$\\0.9606 = \frac{m}{53678} \\\\m = 51563.09$ $\displaystyle \\0.9606 = \frac{m}{53678} \\\\m = 51563.09$

Thus the mass of the balloon is $51563.09 \text{ kilograms}$ $\displaystyle 51563.09 \text{ kilograms}$.

Report an Error

Example Question #442 : High School: Geometry

If a balloon is filled with 58398 $\displaystyle 58398$ cubic meters of xenon with a density of 0.1629 $\displaystyle 0.1629$ kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to $\displaystyle 2$ decimal places

Possible Answers:

$4756.52 \text{ kilograms}$ $\displaystyle 4756.52 \text{ kilograms}$

$9513.03 \text{ kilograms}$ $\displaystyle 9513.03 \text{ kilograms}$

$358489.87 \text{ kilograms}$ $\displaystyle 358489.87 \text{ kilograms}$

$58398.16 \text{ kilograms}$ $\displaystyle 58398.16 \text{ kilograms}$

$58397.84 \text{ kilograms}$ $\displaystyle 58397.84 \text{ kilograms}$

Correct answer:

$9513.03 \text{ kilograms}$ $\displaystyle 9513.03 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$ $\displaystyle d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ( $\uptext{m}$ $\displaystyle \uptext{m}$).

$0.1629 = \frac{m}{58398}$ $\displaystyle 0.1629 = \frac{m}{58398}$

$\displaystyle m = 9513.03$

Thus the mass of the balloon is $9513.03 \text{ kilograms}$ $\displaystyle 9513.03 \text{ kilograms}$.

Report an Error

Example Question #4 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 58744 $\displaystyle 58744$ cubic meters of xenon with a density of 0.1417 $\displaystyle 0.1417$ kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to $\displaystyle 2$ decimal places.

Possible Answers:

$4162.01 \text{ kilograms}$ $\displaystyle 4162.01 \text{ kilograms}$

$58743.86 \text{ kilograms}$ $\displaystyle 58743.86 \text{ kilograms}$

$414565.98 \text{ kilograms}$ $\displaystyle 414565.98 \text{ kilograms}$

$8324.02 \text{ kilograms}$ $\displaystyle 8324.02 \text{ kilograms}$

$58744.14 \text{ kilograms}$ $\displaystyle 58744.14 \text{ kilograms}$

Correct answer:

$8324.02 \text{ kilograms}$ $\displaystyle 8324.02 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$ $\displaystyle d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ( $\uptext{m}$ $\displaystyle \uptext{m}$).

$\\0.1417 = \frac{m}{58744} \\\\m = 8324.02$ $\displaystyle \\0.1417 = \frac{m}{58744} \\\\m = 8324.02$

Thus the mass of the balloon is $8324.02 \text{ kilograms}$ $\displaystyle 8324.02 \text{ kilograms}$.

Report an Error

Example Question #5 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 86938 $\displaystyle 86938$ cubic meters of xenon with a density of 0.5102 $\displaystyle 0.5102$ kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to $\displaystyle 2$ decimal places.

Possible Answers:

$170399.84 \text{ kilograms}$ $\displaystyle 170399.84 \text{ kilograms}$

$86937.49 \text{ kilograms}$ $\displaystyle 86937.49 \text{ kilograms}$

$44355.77 \text{ kilograms}$ $\displaystyle 44355.77 \text{ kilograms}$

$86938.51 \text{ kilograms}$ $\displaystyle 86938.51 \text{ kilograms}$

$22177.88 \text{ kilograms}$ $\displaystyle 22177.88 \text{ kilograms}$

Correct answer:

$44355.77 \text{ kilograms}$ $\displaystyle 44355.77 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$ $\displaystyle d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ($\displaystyle m$).

$\\0.5102 = \frac{m}{86938} \\\\m = 44355.77$ $\displaystyle \\0.5102 = \frac{m}{86938} \\\\m = 44355.77$

Thus the mass of the balloon is $44355.77 \text{ kilograms}$ $\displaystyle 44355.77 \text{ kilograms}$.

Report an Error

Example Question #6 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 72481 $\displaystyle 72481$ cubic meters of neon with a density of 0.0364 $\displaystyle 0.0364$ kilograms per cubic meter. How many kilograms of neon does the balloon contain?

Round your answer to $\displaystyle 2$ decimal places.

Possible Answers:

$1991236.26 \text{ kilograms }$ $\displaystyle 1991236.26 \text{ kilograms }$

$72481.04 \text{ kilograms}$ $\displaystyle 72481.04 \text{ kilograms}$

$72480.96 \text{ kilograms}$ $\displaystyle 72480.96 \text{ kilograms}$

$2638.31 \text{ kilograms}$ $\displaystyle 2638.31 \text{ kilograms}$

$1319.15 \text{ kilograms}$ $\displaystyle 1319.15 \text{ kilograms}$

Correct answer:

$2638.31 \text{ kilograms}$ $\displaystyle 2638.31 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$ $\displaystyle d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ($\displaystyle m$).

$\\0.0364 = \frac{m}{72481} \\\\m = 2638.31$ $\displaystyle \\0.0364 = \frac{m}{72481} \\\\m = 2638.31$

Thus the mass of the balloon is $2638.31 \text{ kilograms}$ $\displaystyle 2638.31 \text{ kilograms}$.

Report an Error

Example Question #7 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 78453 $\displaystyle 78453$ cubic meters of water with a density of 0.011 $\displaystyle 0.011$ kilograms per cubic meter. How many kilograms of water does the balloon contain?

Round your answer to $\displaystyle 2$ decimal places.

Possible Answers:

$431.49 \text{ kilograms}$ $\displaystyle 431.49 \text{ kilograms}$

$862.98 \text{ kilograms }$ $\displaystyle 862.98 \text{ kilograms }$

$78453.01 \text{ kilograms}$ $\displaystyle 78453.01 \text{ kilograms}$

$7132090.91 \text{ kilograms}$ $\displaystyle 7132090.91 \text{ kilograms}$

$78452.99 \text{ kilograms}$ $\displaystyle 78452.99 \text{ kilograms}$

Correct answer:

$862.98 \text{ kilograms }$ $\displaystyle 862.98 \text{ kilograms }$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$ $\displaystyle d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ($\displaystyle m$).

$\\0.011 = \frac{m}{78453} \\\\m = 862.98$ $\displaystyle \\0.011 = \frac{m}{78453} \\\\m = 862.98$

Thus the mass of the balloon is $862.98 \text{ kilograms }$ $\displaystyle 862.98 \text{ kilograms }$.

Report an Error

Example Question #8 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

If a balloon is filled with 77003 $\displaystyle 77003$ cubic meters of water with a density of 0.4689 $\displaystyle 0.4689$ kilograms per cubic meter. How many kilograms of water does the balloon contain?

Round your answer to $\displaystyle 2$ decimal places.

Possible Answers:

$18053.35 \text{ kilograms}$ $\displaystyle 18053.35 \text{ kilograms}$

$77003.47 \text{ kilograms}$ $\displaystyle 77003.47 \text{ kilograms}$

$77002.53 \text{ kilograms}$ $\displaystyle 77002.53 \text{ kilograms}$

$36106.71 \text{ kilograms}$ $\displaystyle 36106.71 \text{ kilograms}$

$164220.52 \text{ kilograms}$ $\displaystyle 164220.52 \text{ kilograms}$

Correct answer:

$36106.71 \text{ kilograms}$ $\displaystyle 36106.71 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$ $\displaystyle d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ($\displaystyle m$).

$\\0.4689 = \frac{m}{77003} \\\\m = 36106.71$ $\displaystyle \\0.4689 = \frac{m}{77003} \\\\m = 36106.71$Thus the mass of the balloon is $36106.71 \text{ kilograms}$ $\displaystyle 36106.71 \text{ kilograms}$.

Report an Error

Example Question #21 : Modeling With Geometry

If a balloon is filled with 97999 $\displaystyle 97999$ cubic meters of xenon with a density of 0.183 $\displaystyle 0.183$ kilograms per cubic meter. How many kilograms of xenon does the balloon contain?

Round your answer to $\displaystyle 2$ decimal places.

Possible Answers:

$535513.66 \text{ kilograms}$ $\displaystyle 535513.66 \text{ kilograms}$

$17933.82 \text{ kilograms}$ $\displaystyle 17933.82 \text{ kilograms}$

$97998.82 \text{ kilograms}$ $\displaystyle 97998.82 \text{ kilograms}$

$8966.91 \text{ kilograms}$ $\displaystyle 8966.91 \text{ kilograms}$

$97999.18 \text{ kilograms}$ $\displaystyle 97999.18 \text{ kilograms}$

Correct answer:

$17933.82 \text{ kilograms}$ $\displaystyle 17933.82 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume. Here is the equation that we need to use.

$d = \frac{m}{v}$ $\displaystyle d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ($\displaystyle m$).

$\\0.183 = \frac{m}{97999} \\\\m = 17933.82$ $\displaystyle \\0.183 = \frac{m}{97999} \\\\m = 17933.82$

Thus the mass of the balloon is $17933.82 \text{ kilograms}$ $\displaystyle 17933.82 \text{ kilograms}$.

Report an Error

Example Question #22 : Modeling With Geometry

If a balloon is filled with 70672 $\displaystyle 70672$ cubic meters of neon with a density of 0.2245 $\displaystyle 0.2245$ kilograms per cubic meter. How many kilograms of neon does the balloon contain?

Round your answer to $\displaystyle 2$ decimal places.

Possible Answers:

$314797.33 \text{ kilograms}$ $\displaystyle 314797.33 \text{ kilograms}$

$15865.86 \text{ kilograms}$ $\displaystyle 15865.86 \text{ kilograms}$

$70672.22 \text{ kilograms}$ $\displaystyle 70672.22 \text{ kilograms}$

$7932.93 \text{ kilograms}$ $\displaystyle 7932.93 \text{ kilograms}$

$70671.78 \text{ kilograms}$ $\displaystyle 70671.78 \text{ kilograms}$

Correct answer:

$15865.86 \text{ kilograms}$ $\displaystyle 15865.86 \text{ kilograms}$

Explanation:

In order to solve this problem, we need to use an equation that involves, density, mass, and volume.

Here is the equation that we need to use.

$d = \frac{m}{v}$ $\displaystyle d = \frac{m}{v}$

Since we are given the density, and volume, we can plug those values in, and then solve for the mass ($\displaystyle m$).

$\\0.2245 = \frac{m}{70672} \\\\m = 15865.86$ $\displaystyle \\0.2245 = \frac{m}{70672} \\\\m = 15865.86$

Thus the mass of the balloon is $15865.86 \text{ kilograms}$ $\displaystyle 15865.86 \text{ kilograms}$.

Report an Error

View Tutors

Cynthia
Certified Tutor

Arizona State University, Bachelors, Psychology. Arizona State University, Master in Public Health, Psychology.

View Tutors

Meredith
Certified Tutor

University of Arkansas at Little Rock, Bachelor in Arts, English. University of Arkansas at Little Rock, Masters in Education...

View Tutors

Lillian
Certified Tutor

Capella University, Master of Science, Health Services Administration.

All Common Core: High School - Geometry Resources

6 Diagnostic Tests 114 Practice Tests Question of the Day Flashcards Learn by Concept

Popular Subjects

French Tutors in Washington DC, ACT Tutors in Chicago, English Tutors in Boston, English Tutors in San Diego, English Tutors in Washington DC, Reading Tutors in Denver, GMAT Tutors in Los Angeles, French Tutors in Phoenix, Reading Tutors in San Francisco-Bay Area, SSAT Tutors in Dallas Fort Worth

Popular Courses & Classes

MCAT Courses & Classes in Denver, ACT Courses & Classes in Miami, GRE Courses & Classes in Dallas Fort Worth, LSAT Courses & Classes in Miami, Spanish Courses & Classes in Washington DC, LSAT Courses & Classes in Seattle, ISEE Courses & Classes in Atlanta, GMAT Courses & Classes in Atlanta, ISEE Courses & Classes in Chicago, MCAT Courses & Classes in Miami

Popular Test Prep

ISEE Test Prep in Philadelphia, ISEE Test Prep in Chicago, ISEE Test Prep in Washington DC, SAT Test Prep in San Francisco-Bay Area, MCAT Test Prep in Los Angeles, SSAT Test Prep in Washington DC, ISEE Test Prep in San Francisco-Bay Area, ISEE Test Prep in San Diego, SSAT Test Prep in Houston, ISEE Test Prep in Atlanta

DMCA Complaint

If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing the information described below to the designated agent listed below. If Varsity Tutors takes action in response to an Infringement Notice, it will make a good faith attempt to contact the party that made such content available by means of the most recent email address, if any, provided by such party to Varsity Tutors.

Your Infringement Notice may be forwarded to the party that made the content available or to third parties such as ChillingEffects.org.

Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially misrepresent that a product or activity is infringing your copyrights. Thus, if you are not sure content located on or linked-to by the Website infringes your copyright, you should consider first contacting an attorney.

Please follow these steps to file a notice:

You must include the following:

A physical or electronic signature of the copyright owner or a person authorized to act on their behalf; An identification of the copyright claimed to have been infringed; A description of the nature and exact location of the content that you claim to infringe your copyright, in \ sufficient detail to permit Varsity Tutors to find and positively identify that content; for example we require a link to the specific question (not just the name of the question) that contains the content and a description of which specific portion of the question – an image, a link, the text, etc – your complaint refers to; Your name, address, telephone number and email address; and A statement by you: (a) that you believe in good faith that the use of the content that you claim to infringe your copyright is not authorized by law, or by the copyright owner or such owner’s agent; (b) that all of the information contained in your Infringement Notice is accurate, and (c) under penalty of perjury, that you are either the copyright owner or a person authorized to act on their behalf.

Send your complaint to our designated agent at:

Charles Cohn Varsity Tutors LLC
101 S. Hanley Rd, Suite 300
St. Louis, MO 63105

Or fill out the form below:

Do not fill in this field

Contact Information

* Full legal name

Company name

* Phone number

* Email address

Address

* Address1

Address2

* City

* State

* Zipcode

* Country

Complaint Details

* URL of copyrighted work (where your original material is located)

* Please describe the copyrighted work so that it may be easily identified

I am the owner, or an agent authorized to act on behalf of the owner of an exclusive right that is allegedly infringed.

I have a good faith belief that the use of the material in the manner complained of is not authorized by the copyright owner, its agent, or the law.

This notification is accurate.

I acknowledge that there may be adverse legal consequences for making false or bad faith allegations of copyright infringement by using this process.

* Signature (your digital signature is legally binding)

HIGH SCHOOL

GRADUATE SCHOOL

K-8

Search 50+ Tests

math tutoring

science tutoring

foreign languages

elementary tutoring

other

Search 350+ Subjects

Common Core: High School - Geometry : Apply Density Concepts to Area and Volume Situations: CCSS.Math.Content.HSG-MG.A.2

Study concepts, example questions & explanations for Common Core: High School - Geometry

All Common Core: High School - Geometry Resources

Example Questions

Example Question #1 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #2 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #442 : High School: Geometry

Example Question #4 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #5 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #6 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #7 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #8 : Apply Density Concepts To Area And Volume Situations: Ccss.Math.Content.Hsg Mg.A.2

Example Question #21 : Modeling With Geometry

Example Question #22 : Modeling With Geometry

All Common Core: High School - Geometry Resources

Report an issue with this question

DMCA Complaint

Contact Information

Address

Complaint Details

Email address:
Your name:
Feedback: