GRE Math : How to add rational expressions with different denominators

Study concepts, example questions & explanations for GRE Math

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Example Questions

Example Question #1 : Rational Expressions

Simplify the expression.

\(\displaystyle \frac{x}{2x+4}+\frac{x}{x+2}\)

Possible Answers:

\(\displaystyle \frac{2x}{3x+6}\)

\(\displaystyle \frac{1}{2x+4}\)

\(\displaystyle \frac{x}{x+2}\)

\(\displaystyle \frac{x+1}{2x+4}\)

\(\displaystyle \frac{3x}{2x+4}\)

Correct answer:

\(\displaystyle \frac{3x}{2x+4}\)

Explanation:

To add rational expressions, first find the least common denominator. Because the denominator of the first fraction factors to 2(x+2), it is clear that this is the common denominator. Therefore, multiply the numerator and denominator of the second fraction by 2.

\(\displaystyle \frac{x}{2x+4}+\frac{x}{x+2}\)

\(\displaystyle \frac{x}{2x+4}+\frac{(2)x}{(2)(x+2)}\)

\(\displaystyle \frac{x}{2x+4}+\frac{2x}{2x+4}\)

\(\displaystyle \frac{3x}{2x+4}\)

This is the most simplified version of the rational expression.

 

Example Question #1 : Rational Expressions

Simplify the following:

\(\displaystyle \frac{x+3}{x-2}+\frac{x-2}{x+3}\)

Possible Answers:

\(\displaystyle \frac{2(x+3)(x-2)}{(x+3)(x-2)}\)

\(\displaystyle 2x^2-4x+4\)

\(\displaystyle 2\)

\(\displaystyle \frac{(x+3)^2+(x-2)^2}{(x+3)(x-2)}\)

Correct answer:

\(\displaystyle \frac{(x+3)^2+(x-2)^2}{(x+3)(x-2)}\)

Explanation:

To simplify the following, a common denominator must be achieved. In this case, the first term must be multiplied by (x+2) in both the numerator and denominator and likewise with the second term with (x-3).

\(\displaystyle \frac{(x+3)(x+3)}{(x-2)(x+3)}+\frac{(x-2)(x-2)}{(x+3)(x-2)}\)

\(\displaystyle \frac{(x+3)^2+(x-2)^2}{(x+3)(x-2)}\)

Example Question #1 : How To Add Rational Expressions With Different Denominators

Choose the answer which best simplifies the following expression:

\(\displaystyle \frac{3a^2 + a}{2} + \frac{10}{2a^2-a}\)

Possible Answers:

\(\displaystyle \frac{6a^4 - a^3 - a^2 + 20}{4a^2 + 2a}\)

\(\displaystyle \frac{6a^4 - a^3 - a^2 + 20}{4a^2 - 2a}\)

\(\displaystyle \frac{6a^4 + a^3 + a^2 + 20}{4a^2 - 2a}\)

\(\displaystyle \frac{36a^4 - a^3 - a^2 + 20}{4a^2 - 2a}\)

\(\displaystyle \frac{5a^3 - a^2 + 20}{4a^2 - 2a}\)

Correct answer:

\(\displaystyle \frac{6a^4 - a^3 - a^2 + 20}{4a^2 - 2a}\)

Explanation:

To simplify, first multiply both terms by the denominator of the other term over itself:

\(\displaystyle \frac{3a^2 + a}{2} \left(\frac{2a^2 - a}{2a^2 - a}\right) + \frac{10}{2a^2-a}\left(\frac{2}{2}\right)\)

\(\displaystyle \frac{6a^4 + 2a^3 -3a^3 - a^2}{4a^2 -2a} + \frac{20}{4a^2 - 2a}\)

Then, you can combine the terms, now that they share a denominator:

\(\displaystyle \frac{6a^4 - a^3 -a^2 +20}{4a^2 - 2a}\)

Example Question #1 : How To Add Rational Expressions With Different Denominators

Choose the answer which best simplifies the following expression:

\(\displaystyle \frac{3p}{2} + \frac{2p}{p^3}\)

Possible Answers:

\(\displaystyle \frac{3p^3 +4}{2p^2}\)

\(\displaystyle \frac{6p^4+8p}{4p^3}\)

\(\displaystyle \frac{3p^3+4p}{2p^3}\)

\(\displaystyle \frac{3p^4+2p}{2p^3}\)

\(\displaystyle \frac{3p^4+4p}{p^3}\)

Correct answer:

\(\displaystyle \frac{3p^3 +4}{2p^2}\)

Explanation:

To simplify this expression, you have to get both numerators over a common denominator.  The best way to go about doing so is to multiply both expressions by the others denominator over itself:

\(\displaystyle \frac{3p}{2} \cdot \frac{p^3}{p^3 } + \frac{2p}{p^3} \cdot \frac{2}{2}\)

Then you are left with:

\(\displaystyle \frac{3p^4}{2p^3} + \frac{4p}{2p^3}\)

Which you can simplify into:

\(\displaystyle \frac{3p^4+4p}{2p^3}\)

From there, you can take out a \(\displaystyle p\):

\(\displaystyle \frac{p(3p^3 + 4)}{p(2p^2)}\)

Which gives you your final answer:

\(\displaystyle \frac{3p^3 +4}{2p^2}\)

Example Question #3 : How To Add Rational Expressions With Different Denominators

Choose the answer which best simplifies the following expression:

\(\displaystyle \frac{2a + 2}{3} + \frac{3}{a^2}\)

Possible Answers:

\(\displaystyle \frac{2a^3 + 2a^2 + 9}{3a}\)

\(\displaystyle \frac{2a^3 + 2a^2 + 3}{3a^2}\)

\(\displaystyle \frac{2a^3 + 2a^2 + 9}{3a^2}\)

\(\displaystyle \frac{2a^3 + 2a^2 + 9}{3a^3}\)

\(\displaystyle \frac{2a^2 + 2a + 9}{3a^2}\)

Correct answer:

\(\displaystyle \frac{2a^3 + 2a^2 + 9}{3a^2}\)

Explanation:

To solve this problem, first multiply both terms of the expression by the denominator of the other over itself:

\(\displaystyle \frac{2a + 2}{3} \cdot \frac{a^2}{a^2} + \frac{3}{a^2} \cdot \frac{3}{3}\)

\(\displaystyle \frac{2a^3 +2a^2}{3a^2} + \frac{9}{3a^2}\)

Now that both terms have a common denominator, you can add them together:

\(\displaystyle \frac{2a^3 +2a^2 + 9}{3a^2}\)

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