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Flashcards: Add Vectors End-to-End, Component-Wise, and by Parallelogram Rule: CCSS.Math.Content.HSN-VM.B.4a

If v=<0, 4> \(\displaystyle v=< 0, 4>\), and w=<-3, -2> \(\displaystyle w=< -3, -2>\), find v+w \(\displaystyle v+w\).

v+w=<2,-3> \(\displaystyle v+w=< 2,-3>\)

v+w=<6,3> \(\displaystyle v+w=< 6,3>\)

v+w=<3,6> \(\displaystyle v+w=< 3,6>\)

v+w=<0,-2> \(\displaystyle v+w=< 0,-2>\)

v+w=<-3,2> \(\displaystyle v+w=< -3,2>\)

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All Common Core: High School - Number and Quantity Resources

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Want to review Common Core: High School - Number and Quantity but don’t feel like sitting for a whole test at the moment? Varsity Tutors has you covered with thousands of different Common Core: High School - Number and Quantity flashcards! Our Common Core: High School - Number and Quantity flashcards allow you to practice with as few or as many questions as you like. Get some studying in now with our numerous Common Core: High School - Number and Quantity flashcards.

Flashcards: Add Vectors End-to-End, Component-Wise, and by Parallelogram Rule: CCSS.Math.Content.HSN-VM.B.4a

If v=<0, 4> \(\displaystyle v=< 0, 4>\), and w=<-3, -2> \(\displaystyle w=< -3, -2>\), find v+w \(\displaystyle v+w\).

v+w=<2,-3> \(\displaystyle v+w=< 2,-3>\)

v+w=<6,3> \(\displaystyle v+w=< 6,3>\)

v+w=<3,6> \(\displaystyle v+w=< 3,6>\)

v+w=<0,-2> \(\displaystyle v+w=< 0,-2>\)

v+w=<-3,2> \(\displaystyle v+w=< -3,2>\)

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Flashcards: Add Vectors End-to-End, Component-Wise, and by Parallelogram Rule: CCSS.Math.Content.HSN-VM.B.4a

If v=<0, 4> \(\displaystyle v=< 0, 4>\), and w=<-3, -2> \(\displaystyle w=< -3, -2>\), find v+w \(\displaystyle v+w\).

Your answer:

v+w=<2,-3> \(\displaystyle v+w=< 2,-3>\)

Your answer:

v+w=<6,3> \(\displaystyle v+w=< 6,3>\)

Your answer:

v+w=<3,6> \(\displaystyle v+w=< 3,6>\)

Your answer:

v+w=<0,-2> \(\displaystyle v+w=< 0,-2>\)

Correct answer:

v+w=<-3,2> \(\displaystyle v+w=< -3,2>\)

Explanation:

This problem is asking us to add vectors \(\displaystyle v\), and \(\displaystyle w\). To add vectors together, we need to sum up like components together. This means that we sum up the x's \(\displaystyle x's\), and the y's \(\displaystyle y's\).

\(\displaystyle x=0+(-3)=-3\)

\(\displaystyle y=4+(-2)=4-2=2\)

v+w=<-3,2> \(\displaystyle v+w=< -3,2>\)

Below is a visual representation of what we just did.

Vecadd

Flashcards: Add Vectors End-to-End, Component-Wise, and by Parallelogram Rule: CCSS.Math.Content.HSN-VM.B.4a

If v=<1, -4> \(\displaystyle v=< 1, -4>\), and w=<-1, 9> \(\displaystyle w=< -1, 9>\), find v+w \(\displaystyle v+w\).

v+w=<-2,5> \(\displaystyle v+w=< -2,5>\)

v+w=<5,0> \(\displaystyle v+w=< 5,0>\)

v+w=<5,2> \(\displaystyle v+w=< 5,2>\)

v+w=<0,5> \(\displaystyle v+w=< 0,5>\)

v+w=<2,5> \(\displaystyle v+w=< 2,5>\)

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Flashcards: Add Vectors End-to-End, Component-Wise, and by Parallelogram Rule: CCSS.Math.Content.HSN-VM.B.4a

If v=<1, -4> \(\displaystyle v=< 1, -4>\), and w=<-1, 9> \(\displaystyle w=< -1, 9>\), find v+w \(\displaystyle v+w\).

Your answer:

v+w=<-2,5> \(\displaystyle v+w=< -2,5>\)

Your answer:

v+w=<5,0> \(\displaystyle v+w=< 5,0>\)

Your answer:

v+w=<5,2> \(\displaystyle v+w=< 5,2>\)

Your answer:

v+w=<2,5> \(\displaystyle v+w=< 2,5>\)

Correct answer:

v+w=<0,5> \(\displaystyle v+w=< 0,5>\)

Explanation:

\(\displaystyle x=1+(-1)=1-1=0\)

\(\displaystyle y=-4+9=5\)

v+w=<0,5> \(\displaystyle v+w=< 0,5>\)

Below is a visual representation of what we just did.

Screen shot 2016 03 14 at 3.09.45 pm

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Flashcards: Add Vectors End-to-End, Component-Wise, and by Parallelogram Rule: CCSS.Math.Content.HSN-VM.B.4a

All Common Core: High School - Number and Quantity Resources

Flashcards: Add Vectors End-to-End, Component-Wise, and by Parallelogram Rule: CCSS.Math.Content.HSN-VM.B.4a

Flashcards: Add Vectors End-to-End, Component-Wise, and by Parallelogram Rule: CCSS.Math.Content.HSN-VM.B.4a

Flashcards: Add Vectors End-to-End, Component-Wise, and by Parallelogram Rule: CCSS.Math.Content.HSN-VM.B.4a

Flashcards: Add Vectors End-to-End, Component-Wise, and by Parallelogram Rule: CCSS.Math.Content.HSN-VM.B.4a

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