All GRE Math Resources
Example Questions
Example Question #1 : Basic Squaring / Square Roots
Which of the following is equivalent to:
?
To begin with, factor out the contents of the radicals. Â This will make answering much easier:
They both have a common factor .  This means that you could rewrite your equation like this:
This is the same as:
These have a common .  Therefore, factor that out:
Example Question #25 : Arithmetic
Simplify:
These three roots all have a  in common; therefore, you can rewrite them:
Now, this could be rewritten:
Now, note thatÂ
Therefore, you can simplify again:
Now, that looks messy! Still, if you look carefully, you see that all of your factors have ; therefore, factor that out:
This is the same as:
Example Question #31 : Arithmetic
Simplify the following:
It cannot be simplified any further
Begin by factoring each of the roots to see what can be taken out of each:
These can be rewritten as:
Notice that each of these has a common factor of .  Thus, we know that we can rewrite it as:
Example Question #32 : Basic Squaring / Square Roots
Simplify the following:
The expression cannot be simplified any further.
Clearly, all three of these roots have a common factor  inside of their radicals. We can start here with our simplification. Therefore, rewrite the radicals like this:
We can simplify this a bit further:
From this, we can factor out the common :
Example Question #5 : How To Find The Common Factor Of Square Roots
To attempt this problem, attempt to simplify the roots of the numerator and denominator:
Notice how both numerator and denominator have a perfect square:
The  term can be eliminated from the numerator and denominator, leaving
Example Question #32 : Arithmetic
For this problem, begin by simplifying the roots. As it stands, numerator and denominator have a common factor of  in the radical:
And as it stands, this  is multiplied by a perfect square in the numerator and denominator:
The  term can be eliminated from the top and bottom, leaving
Example Question #612 : Gre Quantitative Reasoning
To solve this problem, try simplifying the roots by factoring terms; it may be noticeable from observation that both numerator and denominator have a factor of  in the radical:
We can see that the denominator has a perfect square; now try factoring the  in the numerator:
We can see that there's a perfect square in the numerator:
Since there is a  in the radical in both the numerator and denominator, we can eliminate it, leaving