GRE Math : Common Difference in Sequences

Study concepts, example questions & explanations for GRE Math

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Example Questions

Example Question #691 : Gre Quantitative Reasoning

The sequence \displaystyle s is defined as:

\displaystyle s_n=s_n_-_1+20

What is the difference between the 20th and the 30th elements of \displaystyle s?

Possible Answers:

\displaystyle 10

\displaystyle 50

The answer cannot be determined

\displaystyle 100

\displaystyle 200

Correct answer:

\displaystyle 200

Explanation:

For this sequence, you do not have a starting point (i.e. \displaystyle s_1); however, you are able to interpret it relatively easily. The sequence is merely one in which each number is twenty larger than the one preceding it. Therefore, if \displaystyle s_1 were \displaystyle 10, you would have:

\displaystyle 10,30,50,70,...

Now, to find difference between the 20th and the 30th element, it is merely necessary to count the number of twenties that would be added for each of those elements. For instance, the difference between the 21st and the 20th elements is \displaystyle 20. Thus, since you would add a total of ten twenties from the 20th to the 30th element, you know that the difference between these two values is \displaystyle 200.

Example Question #1 : Common Difference In Sequences

Which of the following defines any term in a linear sequence having \displaystyle 30 for its first term and \displaystyle 126 for its ninth term?

Possible Answers:

\displaystyle s_n = 2s_n_-_1 + 4

\displaystyle s_n = s_n_-_1 + \frac{32}{3}

\displaystyle s_n = s_n_-_1 + \frac{16}{3}

\displaystyle s_n = s_n_-_1 + 12

\displaystyle s_n = s_n_-_1 + 8

Correct answer:

\displaystyle s_n = s_n_-_1 + 12

Explanation:

Since this sequence is linear, we know that it will add the same amount for each element. This means that you can evenly divide the difference between the first and the ninth term. Be careful! There will be eight total increases between these terms. (Think this through: 1 to 2, 2 to 3, 3 to 4, etc.)

Thus, we know that the total difference between these terms is:

\displaystyle 126-30=96

Now, dividing this among the eight increases that happen, we know:

\displaystyle \frac{96}{8}=12

This means that for each element, we add \displaystyle 12 to the one prior to it. This means that our general sequence is defined as:

\displaystyle s_n = s_n_-_1 + 12

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