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ISEE Lower Level Quantitative : How to find the area of a trapezoid

Study concepts, example questions & explanations for ISEE Lower Level Quantitative

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All ISEE Lower Level Quantitative Resources

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Example Questions

Example Question #1 : How To Find The Area Of A Trapezoid

Trapezoid3

What is the area of a trapezoid if its height is 1, its long base is 4, and its short base is 2?

Possible Answers:

8.5

Correct answer:

Explanation:

The area of a trapezoid is given by the formula $\frac{1}{2} *height* (base_{long} + base_{short})$ .

We know that the height is 1, the long base is 4, and the short base is 2.

$\frac{1}{2} *height* (base_{long} + base_{short})=\frac{1}{2} *(1)* ((4) + (2))$

$\frac{1}{2}*(6)$

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Example Question #2 : How To Find The Area Of A Trapezoid

Which formula would you use to find the area of a trapezoid?

Possible Answers:

$area=\left ( \frac{b1\times b2}{2} \right )\times h$

$area=\left ( \frac{h}{2} \right )\times b1+b2$

$area=\left ( \frac{b1+b2}{h} \right )\times 2$

$area=\left ( \frac{b1+b2}{2} \right )\times h$

Correct answer:

$area=\left ( \frac{b1+b2}{2} \right )\times h$

Explanation:

The find the area of a trapezoid, use:

$area=\left ( \frac{b1+b2}{2} \right )\times h$

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Example Question #2 : Quadrilaterals

Yard

The above diagram shows a trapezoidal home within a rectangular yard. What is the area of the yard?

Possible Answers:

$8,925 \textrm{ m}^{2}$

$10,325 \textrm{ m}^{2}$

$6,125 \textrm{ m}^{2}$

$11,350 \textrm{ m}^{2}$

$7,525 \textrm{ m}^{2}$

Correct answer:

$7,525 \textrm{ m}^{2}$

Explanation:

The area of the yard is the area of the small trapezoid subtracted from that of the large rectangle. The area of a rectangle is the product of its length and its height, so the large rectangle has area

$105 \times 85 = 8,925$ square meters.

The area of a trapezoid is half the product of its height and the sum of its two parallel sides (bases), so the small trapezoid has area

$\frac{1}{2} \times 40 \times (30 + 40) = \frac{1}{2} \times 40 \times 70 = 1,400$ square meters.

The area of the yard is the difference of the two:

8,925- 1,400 = 7,525 square meters.

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Example Question #2 : Quadrilaterals

Yard

Note: Figure NOT drawn to scale.

Mr. Smith owns the triangular piece of land seen in the above diagram. He sells the trapezoidal parcel shown at bottom right to his brother. What is the area of the land he retains?

Possible Answers:

$16,000 \textrm{ ft}^{2}$

$20,500\textrm{ ft}^{2}$

$35,600 \textrm{ ft}^{2}$

$41,000 \textrm{ ft}^{2}$

$46,500 \textrm{ ft}^{2}$

Correct answer:

$20,500\textrm{ ft}^{2}$

Explanation:

The area of a triangle is half the product of its base and its height, so Mr. Smith's parcel originally had area

$\frac{1}{2 } \times 200 \times 250 = 25,000$ square feet.

The area of a trapezoid is the half product of its height and the sum of its two parallel sides (bases), so the portion Mr. Smith sold to his brother has area

$\frac{1}{2} \times 50 \times (80 + 100) = 4,500$ square feet.

Therefore, Mr. Smith retains a parcel of area

25,000 - 4,500 = 20,500 square feet.

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Example Question #4 : Trapezoids

Screenshot_2015-03-29_at_3.04.28_pm

What is the area of the above trapezoid?

Possible Answers:

$52\:in^2$

$40\:in^2$

$35\:in^2$

$45\:in^2$

$63\:in^2$

Correct answer:

$40\:in^2$

Explanation:

The formula for the area of a trapezoid is $\frac{base_1 + base_2}{2}\cdot height$

In other words, find the average of the bases and multiply by the height. Substituting in the values of the bases for the given trapezoid, and , you get:

$\frac{9\:in+7\:in}{2}\cdot 5\:in = 8\:in\cdot 5\:in=40\:in^2$

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Example Question #3 : Quadrilaterals

Screenshot_2015-03-29_at_3.18.30_pm

What is the area of the above trapezoid?

Possible Answers:

$35\:cm^2$

$96\:cm^2$

$60\:cm^2$

$40\:cm^2$

$50\:cm^2$

Correct answer:

$50\:cm^2$

Explanation:

The formula for the area of a trapezoid is $\frac{base_1 + base_2}{2}\cdot height$

In other words, find the average of the bases and multiply by the height. Substituting the values of the bases of the given trapezoid, $8\:cm$ and $12\:cm$ , into the equation, you get:

$\frac{8\:cm+12\:cm}{2}\cdot 5\:cm = 10\:cm\cdot 5\:cm=50\:cm^2$

The area of the trapezoid is thus $50\:cm^2$ .

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All ISEE Lower Level Quantitative Resources

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ISEE Lower Level Quantitative : How to find the area of a trapezoid

Study concepts, example questions & explanations for ISEE Lower Level Quantitative

All ISEE Lower Level Quantitative Resources

Example Questions

Example Question #1 : How To Find The Area Of A Trapezoid

Example Question #2 : How To Find The Area Of A Trapezoid

Example Question #2 : Quadrilaterals

Example Question #2 : Quadrilaterals

Example Question #4 : Trapezoids

Example Question #3 : Quadrilaterals

All ISEE Lower Level Quantitative Resources

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