Organic Chemistry : Elimination Mechanisms

Study concepts, example questions & explanations for Organic Chemistry

varsity tutors app store varsity tutors android store

Example Questions

← Previous 1

Example Question #1 : Elimination Mechanisms

E1

The above image undergoes an E1 elimination reaction in a lab. The researchers note that the major product formed was the "Zaitsev" product. Which of the following compounds did the observers see most abundantly when the reaction was complete?

Possible Answers:

None of these

E3

E7

E4

E2

Correct answer:

E4

Explanation:

The Zaitsev product is the most stable alkene that can be formed. This is the major product formed in E1 elimination reactions, because the carbocation can undergo hydride shifts to stabilize the positive charge. The most stable alkene is the most substituted alkene, and thus the correct answer.

E4

Example Question #1 : Elimination Mechanisms

Which series of carbocations is arranged from most stable to least stable? 

Possible Answers:

Methyl, primary, secondary, tertiary

The stability of a carbocation depends only on the solvent of the solution

Primary, secondary, tertiary, methyl

Tertiary, secondary, primary, methyl

Methyl, tertiary, secondary, primary

Correct answer:

Tertiary, secondary, primary, methyl

Explanation:

Tertiary carbocations are stabilized by the induction of nearby alkyl groups. Since the carbocation is electron deficient, it is stabilized by multiple alkyl groups (which are electron-donating). Less substituted carbocations lack stability.

Example Question #2 : Elimination Mechanisms

Which of the following is true for E2 reactions?

Possible Answers:

All of these

The proton and the leaving group should be anti-periplanar

A double bond is formed

The reaction is bimolecular

Correct answer:

All of these

Explanation:

All are true for E2 reactions. E2 reactions are bimolecular, with the rate dependent upon the substrate and base. Both E1 and E2 reactions generally follow Zaitsev's rule and form the substituted double bond. The stereochemistry for E2 should be antiperiplanar (this is not necessary for E1).

Example Question #11 : Reaction Mechanisms, Energetics, And Kinematics

Which of the following compounds could NEVER undergo an E2 reaction when treated with potassium tert-butoxide?

Possible Answers:

Cyclopentylbromide

3-methyl-3-iodopentane

Benzylbromide

Bromoethane

Cis-2-bromo-1-methylcyclohexane

Correct answer:

Benzylbromide

Explanation:

For an E2 reaction to occur, there must be a hydrogen on the carbon adjacent to the carbon with the leaving group. Benzyl bromide contains no hydrogens on the carbon next to the carbon with the bromide, and would therefore undergo only a substitution reaction.

Example Question #1 : Help With E2 Reactions

Which of the following statements concerning substitution and elimination reactions is true?

Possible Answers:

In the absence of heat, strong bases, and good nucleophiles, tertiary alkyl halides will react via the SN1 mechanism

SN1 reactions follow a 2-step mechanism; SN2 reactions follow a 1-step mechanism

Acetate  is a better nucleophile than acetic acid 

The more hindered a strong base is, the more likely it is to produce an E2 reaction

All of these are true statements

Correct answer:

All of these are true statements

Explanation:

All of the statements are correct.

SN1 substitution reactions take place in 2 steps, and SN2 substitution reactions take place on one step. Acetate is a better nucleophile than acetic acid because acetate is a negative ion, and therefore donates electrons as a nucleophile. The more hindered a strong base is, the more likely it is to produce an E2 reaction because the base will more easily remove a good leaving group to become more stable (done through elimination in one step via E2). In the absence of heat, strong bases, and good nucleophiles, tertiary alkyl halides will react via the SN1 mechanism because strong bases/good nucleophiles will always undergo SN1 mechanisms (substitution in two steps), with the exception of alkyl halides.

Example Question #11 : Reaction Mechanisms, Energetics, And Kinematics

If the following disubstituted cyclohexane is refluxed (reacted in boiling solvent) in THF and sodium methoxide, which of the following will be the major product?

                                        Q11

Possible Answers:

I

V

III

IV

II

Correct answer:

I

Explanation:

This is an elimination reaction because refluxing conditions indicate high heat, an essential component for these reactions. We can eliminate answer choices that include substitution products, namely those containing methoxy groups, thus addressing answers IV and V.

Because the leaving group, bromide, is bonded to a tertiary carbon, this reaction will undergo an E2 mechanism. This means a carbocation will be formed at carbon one, and a subsequent deprotonation of an adjacent hydrogen will form the alkene. As answer choice III cannot be formed via deprotonation of an adjacent hydrogen, we can eliminate it.

By Zaitsev's rule, we know that the most substituted alkene product of an elimination reaction will be the most stable, and thus most favorable, product. This allows us to see that the product formed in reaction I will be the most favorable.

Example Question #1 : Elimination Mechanisms

Which of the following represents the general rate law for E2 elimination reactions?

Possible Answers:

Correct answer:

Explanation:

An E2 elimination reaction is a bimolecular reaction and its rate is dependent on the concentration of substrate and base. On the contrary, an E1 elimination reaction is a unimolecular reaction and its rate is dependent solely on the concentration of substrate.

Example Question #1 : Help With E2 Reactions

A student is carrying out an E2 reaction in the lab on a tertiary substrate. Which of the following bases should the student use to obtain the least substituted product?

Possible Answers:

Correct answer:

Explanation:

An E2 reaction will form the less substituted product when the base is big and bulky. We are looking for an answer choice that is sterically hindered, and thus will remove a proton "more within it's reach," over removing the proton that forms the most stable (most substituted) product.

( t-butoxide) is a bulky base that is commonly used to favor the less substituted product. There are 3 methyl groups connected to the central carbon, and as such it is sterically hindered.

An E2 reaction requires a strong base, which eliminates water and  (acetic acid) as answer choices. and are both incorrect because they are not sterically hindered. The E2 reaction would result in the most substituted product.

 

Example Question #1 : Help With E2 Reactions

Which of the following products will result from this reaction?

Screen shot 2015 10 24 at 10.12.29 am

Possible Answers:


Screen shot 2015 10 24 at 10.12.43 am


Screen shot 2015 10 24 at 10.12.39 am

Screen shot 2015 10 24 at 10.12.54 am

Screen shot 2015 10 24 at 10.12.50 am

Screen shot 2015 10 24 at 10.12.34 am

Correct answer:


Screen shot 2015 10 24 at 10.12.43 am

Explanation:

The elimination reaction (as opposed to the SN2 because of the big bulky base reagent) only proceeds with the anti-periplanar product. 


Screen shot 2015 10 24 at 10.12.58 am

Example Question #6 : Help With E2 Reactions

What is the product of the following reaction?

Screen shot 2015 10 24 at 10.13.33 am

Possible Answers:

Screen shot 2015 10 24 at 10.13.49 am

Screen shot 2015 10 24 at 10.13.42 am

No reaction.

More than one of these.

Screen shot 2015 10 24 at 10.13.46 am

Correct answer:

Screen shot 2015 10 24 at 10.13.49 am

Explanation:

Because both hydrogens neighboring the  are anti-periplanar, both elimination products would be formed. 

← Previous 1
Learning Tools by Varsity Tutors