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Physical Chemistry : Photons and Photon Energy

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Example Questions

Example Question #1 : Photons And Photon Energy

Which of the following quantities is zero for photons?

Possible Answers:

Mass

Speed

Both mass and speed

Neither mass nor speed

Correct answer:

Mass

Explanation:

Photons are fundamental particles that make up electromagnetic waves (light). The key aspect of photon is that it has very high speed $\left (3*10^8 \frac{m}{s}\right)$ and no mass; therefore, mass for photons is always zero.

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Example Question #2 : Photons And Photon Energy

Which of the following is/are the same for photons in gamma rays and in visible light?

I. frequency

II. wavelength

III. speed

Possible Answers:

None of these

III only

I and II

I only

Correct answer:

III only

Explanation:

Electromagnetic spectrum is a spectrum of different types of light. Each type of electromagnetic wave differs from one another based on the frequency and wavelength; however, the speed of every electromagnetic wave in air is $3\times10^8 \frac{m}{s}$ . The wave equation relates the speed of an electromagnetic to its wavelength and frequency as follows.

$c=\lambda f$

Here, is speed of light, $\lambda$ is wavelength, and is frequency. Since is always constant, wavelength and frequency are inversely proportional to each other. This means that if the wavelength increases the frequency decreases.

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Example Question #1 : Photons And Photon Energy

Photons in ultraviolet rays have a wavelength of 10nm. What is the energy of photons in radio waves?

$h=4.14* 10^-^1^5 eV\cdot s$

Possible Answers:

124eV

1.24neV

124keV

12.4keV

Correct answer:

1.24neV

Explanation:

To solve this question, we need to use the equation relating energy of a wave to its wavelength.

$E = \frac{hc}{\lambda }$

Here, is the energy, is Planck’s constant, is speed of light (for us it’s always $3* 10^8 \frac{m}{s}$ ), and $\lambda$ is the wavelength (in meters). The energy of the ultraviolet rays is

$E = \frac{(4.14* 10^-14 eV\cdot s)(3* 10^8 \frac{m}{s})}{10* 10^-^9m}$

E = 124.2eV

If we look at the electromagnetic spectrum we will notice that the wavelength of radio waves is a lot higher than ultraviolet rays. Since energy is inversely proportional to wavelength we can conclude that the energy of radio waves is lower than ultraviolet's. The only answer choice with an energy lower than ultraviolet rays energy is 1.24neV.

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Physical Chemistry : Photons and Photon Energy

Study concepts, example questions & explanations for Physical Chemistry

All Physical Chemistry Resources

Example Questions

Example Question #1 : Photons And Photon Energy

Example Question #2 : Photons And Photon Energy

Example Question #1 : Photons And Photon Energy

All Physical Chemistry Resources

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