All PSAT Math Resources
Example Questions
Example Question #1 : How To Use Foil
Factor 2x2 - 5x – 12
(x - 4) (2x + 3)
(x + 4) (2x + 3)
(x + 4) (2x + 3)
(x – 4) (2x – 3)
(x - 4) (2x + 3)
Via the FOIL method, we can attest that x(2x) + x(3) + –4(2x) + –4(3) = 2x2 – 5x – 12.
Example Question #1 : How To Use Foil
x > 0.
Quantity A: (x+3)(x-5)(x)
Quantity B: (x-3)(x-1)(x+3)
The two quantities are equal
Quantity B is greater
Quantity A is greater
The relationship cannot be determined from the information given
Quantity B is greater
Use FOIL:
(x+3)(x-5)(x) = (x2 - 5x + 3x - 15)(x) = x3 - 5x2 + 3x2 - 15x = x3 - 2x2 - 15x for A.
(x-3)(x-1)(x+3) = (x-3)(x+3)(x-1) = (x2 + 3x - 3x - 9)(x-1) = (x2 - 9)(x-1)
(x2 - 9)(x-1) = x3 - x2 - 9x + 9 for B.
The difference between A and B:
(x3 - 2x2 - 15x) - (x3 - x2 - 9x + 9) = x3 - 2x2 - 15x - x3 + x2 + 9x - 9
= - x2 - 4x - 9. Since all of the terms are negative and x > 0:
A - B < 0.
Rearrange A - B < 0:
A < B
Example Question #1 : Exponents And The Distributive Property
Solve for all real values of .
First, move all terms to one side of the equation to set them equal to zero.
All terms contain an , so we can factor it out of the equation.
Now, we can factor the quadratic in parenthesis. We need two numbers that add to and multiply to .
We now have three terms that multiply to equal zero. One of these terms must equal zero in order for the product to be zero.
Our answer will be .
Example Question #1 : Exponents And The Distributive Property
Simplify:
In order to simplify this expression, you need to use the FOIL method. First rewrite the expression to look like this:
Next, multiply your first terms together:
Then, multiply your outside terms together:
Then, multiply your inside terms together:
Lastly, multiply your last terms together:
Together, you have
You can combine your like terms, , to give you the final answer:
Example Question #5 : Exponents And The Distributive Property
Use FOIL to simplify the following product:
Use the FOIL method (first, outside, inside, last) to find the product of:
First:
Outside:
Inside:
Last:
Sum the products to find the polynomial:
Example Question #6 : Exponents And The Distributive Property
Simplify:
To solve this problem, use the FOIL method. Start by multiplying the First term in each set of parentheses:
Then multiply the outside terms:
Next, multiply the inside terms:
Finally, multiply the last terms:
When you put the pieces together, you have . Notice that the middle terms cancel each other out, and you are left with . When you distribute the two, you reach the answer:
Example Question #2 : Exponents And The Distributive Property
If , which of the following could be the value of ?
Take the square root of both sides.
Add 3 to both sides of each equation.
Example Question #3 : Exponents And The Distributive Property
Simplify:
= x3y3z3 + x2y + x0y0 + x2y
= x3y3z3 + x2y + 1 + x2y
= x3y3z3 + 2x2y + 1
Example Question #5 : Exponents And The Distributive Property
Use the FOIL method to find the product. Remember to add the exponents when multiplying.
First:
Outside:
Inside:
Last:
Add all the terms:
Example Question #3 : Exponents And The Distributive Property
Square the binomial.
We will need to FOIL.
First:
Inside:
Outside:
Last:
Sum all of the terms and simplify.