PSAT Math : How to find the length of a chord

Study concepts, example questions & explanations for PSAT Math

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Example Questions

Example Question #1 : Diameter And Chords

Circle_120_degrees

The circle above has a radius of \(\displaystyle 6\), and the measure of \(\displaystyle \angle AOB\) is \(\displaystyle 120 ^\circ\). What is the length of chord \(\displaystyle AB\)?

Possible Answers:

\(\displaystyle 6\)

\(\displaystyle 6\sqrt{2}\)

\(\displaystyle 6\sqrt{3}\)

\(\displaystyle 9\)

\(\displaystyle 3\sqrt{3}\)

Correct answer:

\(\displaystyle 6\sqrt{3}\)

Explanation:

To solve a chord problem, draw right triangles using the chord, the radii, and a line connecting the center of the circle to the chord at a right angle. 

Circle_120_degrees_chord 

Now, the chord is split into two equal pieces, and angle AOB is bisected. Instead of one 120 degree angle, you now have two 30-60-90 triangles. 30-60-90 triangles are characterized by having sides in the following ratio:Triangle306090-3

So, to find the length of the chord, first find the length of each half. Because the triangles in your circle are similar to the 30-60-90 triangle above, you can set up a proportion. The hypotenuse of our triangle is 6 (the radius of the circle) so it is set over 2 (the hypotenuse of our model 30-60-90 triangle). Half of the chord of the circle is the leg of the triangle that is across from the 60 degree angle (120/2), so it corresponds to the \(\displaystyle \sqrt{3}\) side of the model triangle. 

\(\displaystyle \frac{x}{6}=\frac{\sqrt{3}}{2}\)

Therefore, \(\displaystyle x=3\sqrt{3}\)

Because x is equal to half of the chord, the answer is \(\displaystyle 6\sqrt{3}\).

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