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Common Core: 3rd Grade Math : Find Areas of Rectilinear Figures: CCSS.Math.Content.3.MD.C.7d

Study concepts, example questions & explanations for Common Core: 3rd Grade Math

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All Common Core: 3rd Grade Math Resources

7 Diagnostic Tests 226 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

What is the area of the figure below?

Possible Answers:

47in^2 $\displaystyle 47in^2$

24in^2 $\displaystyle 24in^2$

35in^2 $\displaystyle 35in^2$

52in^2 $\displaystyle 52in^2$

59in^2 $\displaystyle 59in^2$

Correct answer:

59in^2 $\displaystyle 59in^2$

Explanation:

To find the area of the figure above, we need to split the figure into two rectangles.

12.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$A=7\times 5$ $\displaystyle A=7\times 5$ $A=6\times 4$ $\displaystyle A=6\times 4$

$\displaystyle A=35in^2$ $\displaystyle A=24in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 35in^2+24in^2=59in^2$

Report an Error

Example Question #1 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

What is the area of the figure below?

Possible Answers:

12in^2 $\displaystyle 12in^2$

28in^2 $\displaystyle 28in^2$

22in^2 $\displaystyle 22in^2$

10in^2 $\displaystyle 10in^2$

32in^2 $\displaystyle 32in^2$

Correct answer:

22in^2 $\displaystyle 22in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

11.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$A=6\times 2$ $\displaystyle A=6\times 2$ $A=5\times 2$ $\displaystyle A=5\times 2$

$\displaystyle A=12in^2$ $\displaystyle A=10in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 12in^2+10in^2=22in^2$

Report an Error

Example Question #411 : Measurement & Data

What is the area of the figure below?

Possible Answers:

32in^2 $\displaystyle 32in^2$

18in^2 $\displaystyle 18in^2$

28in^2 $\displaystyle 28in^2$

14in^2 $\displaystyle 14in^2$

40in^2 $\displaystyle 40in^2$

Correct answer:

32in^2 $\displaystyle 32in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

10.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$A=7\times 2$ $\displaystyle A=7\times 2$ $A=6\times 3$ $\displaystyle A=6\times 3$

$\displaystyle A=14in^2$ $\displaystyle A=18in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 14in^2+18in^2=32in^2$

Report an Error

Example Question #2 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

What is the area of the figure below?

Possible Answers:

72in^2 $\displaystyle 72in^2$

96in^2 $\displaystyle 96in^2$

24in^2 $\displaystyle 24in^2$

112in^2 $\displaystyle 112in^2$

100in^2 $\displaystyle 100in^2$

Correct answer:

96in^2 $\displaystyle 96in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

9.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$A=9\times 8$ $\displaystyle A=9\times 8$ $A=8\times 3$ $\displaystyle A=8\times 3$

$\displaystyle A=72in^2$ $\displaystyle A=24in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 72in^2+24in^2=96in^2$

Report an Error

Example Question #412 : Measurement & Data

What is the area of the figure below?

Possible Answers:

28in^2 $\displaystyle 28in^2$

32in^2 $\displaystyle 32in^2$

8in^2 $\displaystyle 8in^2$

12in^2 $\displaystyle 12in^2$

24in^2 $\displaystyle 24in^2$

Correct answer:

32in^2 $\displaystyle 32in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

8.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$A=4\times 6$ $\displaystyle A=4\times 6$ $A=4\times 2$ $\displaystyle A=4\times 2$

$\displaystyle A=24in^2$ A=8in^2 $\displaystyle A=8in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 24in^2+8in^2=32in^2$

Report an Error

Example Question #3 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

What is the area of the figure below?

Possible Answers:

25in^2 $\displaystyle 25in^2$

9in^2 $\displaystyle 9in^2$

36in^2 $\displaystyle 36in^2$

18in^2 $\displaystyle 18in^2$

34in^2 $\displaystyle 34in^2$

Correct answer:

34in^2 $\displaystyle 34in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

7.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$A=5\times 5$ $\displaystyle A=5\times 5$ $A=3\times 3$ $\displaystyle A=3\times 3$

$\displaystyle A=25in^2$ A=9in^2 $\displaystyle A=9in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 25in^2+9in^2=34in^2$

Report an Error

Example Question #4 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

What is the area of the figure below?

Possible Answers:

48in^2 $\displaystyle 48in^2$

40in^2 $\displaystyle 40in^2$

36in^2 $\displaystyle 36in^2$

44in^2 $\displaystyle 44in^2$

8in^2 $\displaystyle 8in^2$

Correct answer:

44in^2 $\displaystyle 44in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

6.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$A=4\times 2$ $\displaystyle A=4\times 2$ $A=9\times 4$ $\displaystyle A=9\times 4$

A=8in^2 $\displaystyle A=8in^2$ $\displaystyle A=36in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 8in^2+36in^2=44in^2$

Report an Error

Example Question #71 : Geometry

What is the area of the figure below?

Possible Answers:

31in^2 $\displaystyle 31in^2$

35in^2 $\displaystyle 35in^2$

22in^2 $\displaystyle 22in^2$

9in^2 $\displaystyle 9in^2$

40in^2 $\displaystyle 40in^2$

Correct answer:

31in^2 $\displaystyle 31in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

5.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$A=3\times 3$ $\displaystyle A=3\times 3$ $A=11\times 2$ $\displaystyle A=11\times 2$

A=9in^2 $\displaystyle A=9in^2$ $\displaystyle A=22in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 9in^2+22in^2=31in^2$

Report an Error

Example Question #261 : Plane Geometry

What is the area of the figure below?

Possible Answers:

62in^2 $\displaystyle 62in^2$

24in^2 $\displaystyle 24in^2$

68in^2 $\displaystyle 68in^2$

64in^2 $\displaystyle 64in^2$

40in^2 $\displaystyle 40in^2$

Correct answer:

64in^2 $\displaystyle 64in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

4.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$A=8\times 5$ $\displaystyle A=8\times 5$ $A=6\times 4$ $\displaystyle A=6\times 4$

$\displaystyle A=40in^2$ $\displaystyle A=24in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 40in^2+24in^2=64in^2$

Report an Error

Example Question #72 : Geometry

What is the area of the figure below?

Possible Answers:

18n^2 $\displaystyle 18n^2$

4in^2 $\displaystyle 4in^2$

24in^2 $\displaystyle 24in^2$

28in^2 $\displaystyle 28in^2$

16in^2 $\displaystyle 16in^2$

Correct answer:

28in^2 $\displaystyle 28in^2$

Explanation:

To find the area of the figure above, we need to slip the figure into two rectangles.

3.5

Using our area formula, $A=l\times w$ $\displaystyle A=l\times w$, we can solve for the area of both of our rectangles

$A=2\times 12$ $\displaystyle A=2\times 12$ $A=2\times 2$ $\displaystyle A=2\times 2$

$\displaystyle A=24in^2$ A=4in^2 $\displaystyle A=4in^2$

To find our final answer, we need to add the areas together.

$\displaystyle 24in^2+4in^2=28in^2$

Report an Error

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Common Core: 3rd Grade Math : Find Areas of Rectilinear Figures: CCSS.Math.Content.3.MD.C.7d

Study concepts, example questions & explanations for Common Core: 3rd Grade Math

All Common Core: 3rd Grade Math Resources

Example Questions

Example Question #1 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

Example Question #1 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

Example Question #411 : Measurement & Data

Example Question #2 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

Example Question #412 : Measurement & Data

Example Question #3 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

Example Question #4 : Find Areas Of Rectilinear Figures: Ccss.Math.Content.3.Md.C.7d

Example Question #71 : Geometry

Example Question #261 : Plane Geometry

Example Question #72 : Geometry

All Common Core: 3rd Grade Math Resources

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