All GRE Subject Test: Biology Resources
Example Questions
Example Question #1 : Cell Metabolism
What are the net products of the Krebs cycle from one glucose molecule?
6 NADH, 2 FADH2, 2 GTP, 4 CO2
4 NADH, 2 FADH2, 2 GTP, 6 CO2
2 pyruvate, 2 NADH, 2 ATP
3 NADH, 1 FADH2, 1 GTP, 2 CO2
6 NADH, 2 FADH2, 2 GTP, 4 CO2
The Krebs cycle is very important for the production of the electron carriers NADH and FADH2. NADH is produced in a higher quantity, partially due to the fact that it is more energetically favorable during the electron transport chain. During one turn of the Krebs cycle, one acetyl-CoA is used to generate a CoA residue, three NADH, one GTP, one FADH2, and two carbon dioxide. Each glucose molecule produces two acetyl-CoA, fueling two turns of the Krebs cycle and doubling these amounts.
The net products of glycolysis are 2 pyruvate, 2 ATP, and 2 NADH.
Example Question #2 : Cell Metabolism
Which of the following products is produced in the highest quantity during the Krebs cycle?
For every two molecules of pyruvate that enter the Krebs cycle, six molecules of NADH are generated. Only four molecules of carbon dioxide, two molecules of FADH2, and two molecules of ATP (GTP) are produced. The reason this has significance is because NADH is an important electron carrier that will help produce large amounts of ATP during the electron transport chain. The primary purpose of the Krebs cycle is to generate large amounts of this electron carrier in order to fuel the electron transport chain and oxidative phosphorylation, which is eventually responsible for mass production of ATP.
Example Question #3 : Cell Metabolism
What molecule joins with acetyl CoA in order to produce citrate?
Ketoglutarate
Succinate
Oxaloacetate
Pyruvate
Oxaloacetate
Acetyl CoA (a two-carbon molecule) enters the Krebs cycle by joining with oxaloacetate (a four-carbon molecule) in order to create the six-carbon molecule citrate.
Example Question #1 : Cell Metabolism
__________ is the loss of electrons caused by __________ agents.
Reduction . . . oxidizing
None of these
Oxidation . . . oxidizing
Reduction . . . reducing
Oxidation . . . reducing
Oxidation . . . oxidizing
Oxidation is the process by which a molecule loses an electron, which is caused by an oxidizing agent. Reduction is the process by which a molecule gains an electron, which is caused by a reducing agent. Remember: OIL RIG (Oxidation Is Loss of electrons, Reduction Is Gain of electrons)
Example Question #4 : Understanding The Krebs Cycle
Which of the following are high energy intermediates produced during the citric acid cycle?
I.
II.
III.
IV.
I, II, and III
I and III
I, II, III, and IV
I, III, and IV
II and III
I and III
and are the only high energy intermediates produced in cellular respiration. is produced instead in the light reactions of photosynthesis or in the pentose phosphate pathway. However, all three of these can pass on their high energy electrons to reduce other substrates. Even though is produced in cellular respiration, it is not a high energy intermediate. is the most oxidized form of carbon and cannot be tapped into for further energy by standard metabolic processes.
Example Question #5 : Understanding The Krebs Cycle
Which molecule reacts with oxaloacetate (four-carbons) to form citrate (six-carbons) in the beginning of the citric acid cycle?
Alpha-ketoglutarate
Malate
Succinate
Fumarate
Acetyl CoA
Acetyl CoA
The acetyl group from the molecule acetyl CoA (two-carbons) is added to oxaloacetate to form citrate in the beginning of the citric acid cycle. Alpha-ketoglutarate (five-carbons), succinate (four-carbons), fumarate (four-carbons), and malate (four-carbons) are all intermediates of the citric acid cycle. Acetyl-CoA can come from various metabolic pathways including glycolysis (and subsequent pyruvate dehydrogenation) and beta-oxidation of fatty acids.
Example Question #1 : Understanding The Krebs Cycle
Which high energy intermediate is produced when pyruvate and coenzyme A react to form acetyl-CoA and carbon dioxide?
The decarboxylation of pyruvate results in the production of NADH. NADH can then pass its high energy electrons through the electron transport chain, which leads to ATP production. The other high energy intermediates, except for NADPH, are produced in other stages of cellular respiration (glycolysis and Krebs cycle). Cyclic AMP is an intracellular second messenger that is involved in signal transduction and regulation of many cellular processes.
Example Question #1 : Understanding The Krebs Cycle
The hydrolysis of ATP to ADP and an inorganic phosphate is a(n) __________ reaction.
I. exergonic
II. endergonic
III. spontaneous
IV. nonspontaneous
I only
II and IV
I and IV
I and III
II only
I and III
The hydrolysis of ATP releases energy, making it an exergonic reaction. Endergonic reactions require energy from a source such as the hydrolysis of ATP. ATP will spontaneously hydrolyze to form ADP and Pi, this is because the products have greater entropy, lower free energy, and thus a negative . ATP is unstable because it has three negatively-charged phosphate groups that repel one another, and because upon hydrolysis, the phosphate group(s) exhibit resonance.
Example Question #3 : Understanding The Krebs Cycle
Glucose is not the only molecule from which ATP can be derived. Which molecule type produces the most amount of ATP per gram?
Alcohol
Carbohydrates
Nucleic acids
Proteins
Lipids
Lipids
Lipids yield the most amount of ATP per gram because they contain the most reduced form of carbon. Alcohols, such as ethanol, are a close second because their carbons are more reduced than they are in carbohydrates. A general guide is that lipids produce about 9kcal per gram, alcohols produce about 7kcal per gram, carbohydrates and proteins produce about 4kcal per gram and nucleic acids produce about 2kcal per gram, although they are rarely used for energy.
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