All High School Chemistry Resources
Example Questions
Example Question #31 : Chemical Reactions
What is the coefficient on sulfur dioxide if the following redox reaction is balanced in an acidic solution?
Balancing redox reactions involves the following steps:
1. Divide the reaction into oxidation and reduction half reactions and balance all atoms that are not oxygen and hydrogen:
2. Balance the oxygens by adding water molecules on the opposite side of the reactions:
3. Balance the hydrogens by adding protons to the opposite side of the equation:
4. Add electrons in order to equal the charges on both sides of the equation:
5. In order to make the electron exchange equal in each half step, we must multiply the top half reaction by 3:
6. Add up the reactants and products while cancelling out substances on opposite sides of the reactions. For example: we will cancel the 6 water molecules as reactants and be left with only one water molecule as a product. In addition, only 2 protons will be left on the reactant's side after canceling the 12 from the product's side.
In the balanced redox reaction, the coefficient on sulfur dioxide is 3.
Example Question #1 : Balancing Oxidation Reduction Reactions
For the following unbalanced redox reaction, how many electrons are transferred and which chemical species is being oxidized?
One electron is transferred; Hg is oxidized
Two electrons are transferred; Hg is oxidized
One electron is transferred; P is oxidized
Two electrons are transferred; P is oxidized
Two electrons are transferred; Hg is oxidized
To begin, we will need to separate the given reaction into the two half-reactions by identifying changes in oxidation number. In this case, mercury (Hg) and phosphorus (P) show a change in oxidation number. Mercury begins with an oxidation number of zero, and ends with an oxidation number of . Phosphorus begins with an oxidation number of
and ends with an oxidation number of
. Note that the oxidation numbers for fluorine and iodine reamain constant at
for each.
Now we can begin to look at the half-reactions.
Balance the atoms.
Now balance the electrons. We know that each mercury atom loses one electron and each fluorine atom gains one electron.
We can see that two electrons are tranferred. To identify the element being oxidized, we must find the element that is losing electrons. In this case, mercury is being oxidized.
Example Question #1 : Balancing Oxidation Reduction Reactions
Oxidation is the __________ of electrons, reduction is the __________ of electrons.
loss . . . gain
None of these; it depends on the reaction.
gain . . . loss
loss . . . loss
gain . . . gain
loss . . . gain
An oxidation-reduction (redox) reaction is a reaction where electrons are transferred between two substances. When an atom is oxidized, it is called the reducing agent, and it loses a number of electrons. Similarly, a reduced atom is called the oxidizing agent, and gains the same number of electrons. A popular mnemonic to help remember is OIL RIG, or Oxidation is Loss of electrons, Reduction is Gain of electrons.
All High School Chemistry Resources
![Learning Tools by Varsity Tutors](https://vt-vtwa-app-assets.varsitytutors.com/assets/problems/og_image_practice_problems-9cd7cd1b01009043c4576617bc620d0d5f9d58294f59b6d6556fd8365f7440cf.jpg)