To find the perimeter of a regular hendecagon you must first know the number of sides in a hendecagon is 11.

When you know the number of sides of a regular polygon to find the perimeter you must multiply the side length by the number of sides.

In this case it is \(\displaystyle 11*32=352\).

The answer for the perimeter is \(\displaystyle 352\). 

The perimeter of the polygon is 46. Think of this polygon as a rectangle with two of its corners "flipped" inwards. This "flipping" changes the area of the rectangle, but not its perimeter; therefore, the top and bottom sides of the original rectangle would be 12 units long \(\displaystyle \dpi{100} \small (10+2=12)\). The left and right sides would be 11 units long \(\displaystyle \dpi{100} \small (8+3=11)\). Adding all four sides, we find that the perimeter of the recangle (and therefore, of this polygon) is 46.

To find the perimeter of a regular polygon, we take the length of each side, \(\displaystyle l\), and multiply it by the number of sides, \(\displaystyle s\).

\(\displaystyle P=s*l\)

In a nonagon the number of sides is \(\displaystyle 9\), and in this example the side length is \(\displaystyle 15\).

\(\displaystyle P=9*15=135\)

The perimeter is \(\displaystyle 135\).

The formula for the perimeter of an octagon is \(\displaystyle P = 8(side)\).

Plugging in our values, we get:

\(\displaystyle P = 8(12\ m)\)

\(\displaystyle P = 96\ m\)

What is the area of a regular heptagon with an apothem of 4 and a side length of 6?

To find the area of any polygon with the side length and the apothem we must know the equation for the area of a polygon which is

First, we must calculate the perimeter using the side length.

To find the perimeter of a regular polygon we take the length of each side and multiply it by the number of sides.

In a heptagon the number of sides is 7 and in this example the side length is 6 so

The perimeter is .

Then we plug in the numbers for the apothem and perimeter into the equation yielding

We then multiply giving us the area of  .

To find the area of any polygon with the side length and the apothem we must know the equation for the area of a polygon which is

First, we must calculate the perimeter using the side length.

To find the perimeter of a regular polygon we take the length of each side and multiply it by the number of sides.

In a decagon the number of sides is 10 and in this example the side length is 25 so \(\displaystyle 25*10=250\)

The perimeter is  \(\displaystyle 250\).

Then we plug in the numbers for the apothem and perimeter into the equation yielding \(\displaystyle Area\:of\:Polygon=\frac{1}{2}(250)15\)

We then multiply giving us the area of  \(\displaystyle 1875\).

To find the area of any polygon with the side length and the apothem we must know the equation for the area of a polygon which is

We must then calculate the perimeter using the side length.

To find the perimeter of a regular polygon we take the length of each side and multiply it by the number of sides \(\displaystyle n\). 

In a heptagon the number of sides \(\displaystyle n\) is \(\displaystyle 7\) and in this example the side length is \(\displaystyle 8\) so \(\displaystyle 8*7=56\)

The perimeter is 56.

Then we plug in the numbers for the apothem and perimeter into the equation yielding \(\displaystyle Area=(\frac{1}{2})(56)(4)\)

We then multiply giving us the area of  \(\displaystyle 112\).

To find the area of the shaded region, you must subtract the area of the circle from the area of the square.

The formula for the shaded area is:

\(\displaystyle A=A_{square}-A_{circle}\)

\(\displaystyle A = (s)^2 - \pi(r)^2\),

where \(\displaystyle s\) is the side of the square and \(\displaystyle r\) is the radius of the circle.

Plugging in our values, we get:

\(\displaystyle A = (10m)^2 - \pi(5m)^2\)

\(\displaystyle A = 100m^2 - 25\pi m^2\)

To find the area of the shaded region, you need to subtract the area of the triangle from the area of the sector:

\(\displaystyle A = A_{sector} - A_{triangle}\)

\(\displaystyle A = \pi r^2 (part) - \frac{1}{2} (b)(h)\)

Where \(\displaystyle r\) is the radius of the circle, \(\displaystyle part\) is the fraction of the circle, \(\displaystyle b\) is the base of the triangle, and \(\displaystyle h\) is the height of the triangle

Plugging in our values, we get

\(\displaystyle A = \pi (6cm^2) (\frac{90}{360}) - \frac{1}{2} (6cm)(6cm)\)

\(\displaystyle A = 9\pi - 18cm^2\)

To find the area of the shaded region, you need to subtract the area of the equilateral triangle from the area of the sector:

\(\displaystyle A = A_{sector} - A_{equilateral triangle}\)

\(\displaystyle A = \pi r^2 (part) - \frac{s^2 \sqrt{3}}{4}\)

Where \(\displaystyle r\) is the radius of the circle, \(\displaystyle part\) is the fraction of the circle, and \(\displaystyle s\) is the side of the triangle

Plugging in our values, we get

\(\displaystyle A = \pi (5cm^2) \frac{60}{360} - \frac{(5cm)^2\sqrt{3}}{4}\)

\(\displaystyle A=\frac{25\pi }{6}- \frac{25\sqrt{3}}{4} cm^2\)