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AP Calculus AB : Basic properties of definite integrals (additivity and linearity)

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Example Questions

Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

If f(x),g(x) are continuous functions, $g(x) = \frac{1}{2}f(x)$ , $\int_0^4 f(x) dx = 6$ , and $\int_4^{10} g(x)dx = 8$ , find $\int_0^{10} f(x) dx$ .

Possible Answers:

Not enough information

Correct answer:

Explanation:

We proceed as follows

$\int_0^{10} f(x) dx$ . (Start)

$=\int_0^4 f(x) dx + \int_4^{10}f(x)dx$ . (Break up the integral using the additive rule.)

$=\int_0^4 f(x) dx + \int_4^{10}2g(x)dx$ . (We don't have information about the 2nd integral, so we solve our first equation for f(x) and replace it in this integral.)

$=\int_0^4 f(x) dx + 2\int_4^{10}g(x)dx$ . (Factor out the using linearity.)

=6 +2(8) . (Substitute in what we were given.)

=22 .

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Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

$\begin{align*}&\int_{24}^{9}f(x)dx=-24\\&\int_{24}^{26}f(x)dx=11\\&\int_{26}^{32}f(x)dx=24\\&\int_{32}^{34}f(x)dx=34\\&\text{Calculate from the above values }\int_{9}^{34}f(x)dx\end{align*}$

Possible Answers:

Correct answer:

Explanation:

$\begin{align*}&\text{One of the principles of integrals is one of summation. If the}\\&\text{values of an integral across certain sets of points is known,}\\&\text{this could potentially be used to find integral values at other}\\&\text{points. Imagine a set of points that are in ascending numerical}\\&\text{value: a, b, c, and d. It follows that:}\\&\int_a^d=\int_a^b+\int_b^c+\int_c^d\\&\text{Another principle of integrals is that if an integral value}\\&\text{is known, to take the same integral backwards will give a negative}\\&\text{of the original value:}\\&\int_a^b=-\int_b^a\\&\text{Knowing this, we can calculate }\int_{9}^{34}f(x)dx\\&\int_{9}^{34}f(x)dx=-(-24)+(11)+(24)+(34)\\&\int_{9}^{34}f(x)dx=93\\&\end{align*}$

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Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

$\begin{align*}&\int_{13}^{2}f(x)dx=-94\\&\int_{13}^{19}f(x)dx=-23\\&\int_{23}^{19}f(x)dx=-32\\&\int_{28}^{23}f(x)dx=-18\\&\int_{31}^{28}f(x)dx=-84\\&\text{Determine }\int_{2}^{31}f(x)dx\end{align*}$

Possible Answers:

205

178

Correct answer:

205

Explanation:

$\begin{align*}&\text{One of the principles of integrals is one of summation. If the}\\&\text{values of an integral across certain sets of points is known,}\\&\text{this could potentially be used to find integral values at other}\\&\text{points. Imagine a set of points that are in ascending numerical}\\&\text{value: a, b, c, and d. It follows that:}\\&\int_a^d=\int_a^b+\int_b^c+\int_c^d\\&\text{Another principle of integrals is that if an integral value}\\&\text{is known, to take the same integral backwards will give a negative}\\&\text{of the original value:}\\&\int_a^b=-\int_b^a\\&\text{Knowing this, we can calculate }\int_{2}^{31}f(x)dx\\&\int_{2}^{31}f(x)dx=-\int_{13}^{2}f(x)dx+\int_{13}^{19}f(x)dx-\int_{23}^{19}f(x)dx-\int_{28}^{23}f(x)dx-\int_{31}^{28}f(x)dx\\&\int_{2}^{31}f(x)dx=-(-94)+(-23)-(-32)-(-18)-(-84)\\&\int_{2}^{31}f(x)dx=205\\&\end{align*}$

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Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

$\begin{align*}&\int_{-10}^{-5}f(x)dx=95\\&\int_{-1}^{-5}f(x)dx=-41\\&\int_{6}^{-1}f(x)dx=-26\\&\int_{21}^{6}f(x)dx=-38\\&\int_{28}^{21}f(x)dx=62\\&\text{Calculate from the above values }\int_{-10}^{28}f(x)dx\end{align*}$

Possible Answers:

138

Correct answer:

138

Explanation:

$\begin{align*}&\text{One of the principles of integrals is one of summation. If the}\\&\text{values of an integral across certain sets of points is known,}\\&\text{this could potentially be used to find integral values at other}\\&\text{points. Imagine a set of points that are in ascending numerical}\\&\text{value: a, b, c, and d. It follows that:}\\&\int_a^d=\int_a^b+\int_b^c+\int_c^d\\&\text{Another principle of integrals is that if an integral value}\\&\text{is known, to take the same integral backwards will give a negative}\\&\text{of the original value:}\\&\int_a^b=-\int_b^a\\&\text{Knowing this, we can calculate }\int_{-10}^{28}f(x)dx\\&\int_{-10}^{28}f(x)dx=\int_{-10}^{-5}f(x)dx-\int_{-1}^{-5}f(x)dx-\int_{6}^{-1}f(x)dx-\int_{21}^{6}f(x)dx-\int_{28}^{21}f(x)dx\\&\int_{-10}^{28}f(x)dx=(95)-(-41)-(-26)-(-38)-(62)\\&\int_{-10}^{28}f(x)dx=138\\&\end{align*}$

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Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

$\begin{align*}&\int_{-3}^{9}f(x)dx=-67\\&\int_{9}^{22}f(x)dx=74\\&\int_{37}^{22}f(x)dx=-18\\&\int_{39}^{37}f(x)dx=-67\\&\int_{42}^{39}f(x)dx=68\\&\int_{42}^{45}f(x)dx=86\\&\text{Calculate from the above values }\int_{-3}^{45}f(x)dx\end{align*}$

Possible Answers:

110

Correct answer:

110

Explanation:

$\begin{align*}&\text{One of the principles of integrals is one of summation. If the}\\&\text{values of an integral across certain sets of points is known,}\\&\text{this could potentially be used to find integral values at other}\\&\text{points. Imagine a set of points that are in ascending numerical}\\&\text{value: a, b, c, and d. It follows that:}\\&\int_a^d=\int_a^b+\int_b^c+\int_c^d\\&\text{Another principle of integrals is that if an integral value}\\&\text{is known, to take the same integral backwards will give a negative}\\&\text{of the original value:}\\&\int_a^b=-\int_b^a\\&\text{Knowing this, we can calculate }\int_{-3}^{45}f(x)dx\\&\int_{-3}^{45}f(x)dx=\int_{-3}^{9}f(x)dx+\int_{9}^{22}f(x)dx-\int_{37}^{22}f(x)dx-\int_{39}^{37}f(x)dx-\int_{42}^{39}f(x)dx+\int_{42}^{45}f(x)dx\\&\int_{-3}^{45}f(x)dx=(-67)+(74)-(-18)-(-67)-(68)+(86)\\&\int_{-3}^{45}f(x)dx=110\\&\end{align*}$

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Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

$\begin{align*}&\int_{-9}^{0}f(x)dx=62\\&\int_{13}^{0}f(x)dx=-46\\&\int_{18}^{13}f(x)dx=20\\&\text{Use the above values to find }\int_{-9}^{18}f(x)dx\end{align*}$

Possible Answers:

Correct answer:

Explanation:

$\begin{align*}&\text{One of the principles of integrals is one of summation. If the}\\&\text{values of an integral across certain sets of points is known,}\\&\text{this could potentially be used to find integral values at other}\\&\text{points. Imagine a set of points that are in ascending numerical}\\&\text{value: a, b, c, and d. It follows that:}\\&\int_a^d=\int_a^b+\int_b^c+\int_c^d\\&\text{Another principle of integrals is that if an integral value}\\&\text{is known, to take the same integral backwards will give a negative}\\&\text{of the original value:}\\&\int_a^b=-\int_b^a\\&\text{Knowing this, we can calculate }\int_{-9}^{18}f(x)dx\\&\int_{-9}^{18}f(x)dx=\int_{-9}^{0}f(x)dx-\int_{13}^{0}f(x)dx-\int_{18}^{13}f(x)dx\\&\int_{-9}^{18}f(x)dx=(62)-(-46)-(20)\\&\int_{-9}^{18}f(x)dx=88\\&\end{align*}$

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Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

$\begin{align*}&\int_{-10}^{3}f(x)dx=95\\&\int_{3}^{13}f(x)dx=63\\&\int_{23}^{13}f(x)dx=78\\&\int_{23}^{37}f(x)dx=-54\\&\int_{37}^{50}f(x)dx=-56\\&\int_{50}^{56}f(x)dx=77\\&\text{Use the above values to find }\int_{-10}^{56}f(x)dx\end{align*}$

Possible Answers:

172

203

Correct answer:

Explanation:

$\begin{align*}&\text{One of the principles of integrals is one of summation. If the}\\&\text{values of an integral across certain sets of points is known,}\\&\text{this could potentially be used to find integral values at other}\\&\text{points. Imagine a set of points that are in ascending numerical}\\&\text{value: a, b, c, and d. It follows that:}\\&\int_a^d=\int_a^b+\int_b^c+\int_c^d\\&\text{Another principle of integrals is that if an integral value}\\&\text{is known, to take the same integral backwards will give a negative}\\&\text{of the original value:}\\&\int_a^b=-\int_b^a\\&\text{Knowing this, we can calculate }\int_{-10}^{56}f(x)dx\\&\int_{-10}^{56}f(x)dx=\int_{-10}^{3}f(x)dx+\int_{3}^{13}f(x)dx-\int_{23}^{13}f(x)dx+\int_{23}^{37}f(x)dx+\int_{37}^{50}f(x)dx+\int_{50}^{56}f(x)dx\\&\int_{-10}^{56}f(x)dx=(95)+(63)-(78)+(-54)+(-56)+(77)\\&\int_{-10}^{56}f(x)dx=47\\&\end{align*}$

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Example Question #5 : Basic Properties Of Definite Integrals (Additivity And Linearity)

$\begin{align*}&\int_{-4}^{6}f(x)dx=5\\&\int_{12}^{6}f(x)dx=90\\&\int_{15}^{12}f(x)dx=73\\&\int_{19}^{15}f(x)dx=-70\\&\int_{22}^{19}f(x)dx=97\\&\int_{24}^{22}f(x)dx=36\\&\text{Calculate from the above values }\int_{-4}^{24}f(x)dx\end{align*}$

Possible Answers:

231

Correct answer:

Explanation:

$\begin{align*}&\text{One of the principles of integrals is one of summation. If the}\\&\text{values of an integral across certain sets of points is known,}\\&\text{this could potentially be used to find integral values at other}\\&\text{points. Imagine a set of points that are in ascending numerical}\\&\text{value: a, b, c, and d. It follows that:}\\&\int_a^d=\int_a^b+\int_b^c+\int_c^d\\&\text{Another principle of integrals is that if an integral value}\\&\text{is known, to take the same integral backwards will give a negative}\\&\text{of the original value:}\\&\int_a^b=-\int_b^a\\&\text{Knowing this, we can calculate }\int_{-4}^{24}f(x)dx\\&\int_{-4}^{24}f(x)dx=\int_{-4}^{6}f(x)dx-\int_{12}^{6}f(x)dx-\int_{15}^{12}f(x)dx-\int_{19}^{15}f(x)dx-\int_{22}^{19}f(x)dx-\int_{24}^{22}f(x)dx\\&\int_{-4}^{24}f(x)dx=(5)-(90)-(73)-(-70)-(97)-(36)\\&\int_{-4}^{24}f(x)dx=-221\\&\end{align*}$

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Example Question #33 : Interpretations And Properties Of Definite Integrals

$\begin{align*}&\int_{-4}^{0}f(x)dx=-13\\&\int_{15}^{0}f(x)dx=56\\&\int_{15}^{23}f(x)dx=-53\\&\int_{23}^{31}f(x)dx=96\\&\int_{31}^{32}f(x)dx=-44\\&\text{Calculate from the above values }\int_{-4}^{32}f(x)dx\end{align*}$

Possible Answers:

Correct answer:

Explanation:

$\begin{align*}&\text{One of the principles of integrals is one of summation. If the}\\&\text{values of an integral across certain sets of points is known,}\\&\text{this could potentially be used to find integral values at other}\\&\text{points. Imagine a set of points that are in ascending numerical}\\&\text{value: a, b, c, and d. It follows that:}\\&\int_a^d=\int_a^b+\int_b^c+\int_c^d\\&\text{Another principle of integrals is that if an integral value}\\&\text{is known, to take the same integral backwards will give a negative}\\&\text{of the original value:}\\&\int_a^b=-\int_b^a\\&\text{Knowing this, we can calculate }\int_{-4}^{32}f(x)dx\\&\int_{-4}^{32}f(x)dx=\int_{-4}^{0}f(x)dx-\int_{15}^{0}f(x)dx+\int_{15}^{23}f(x)dx+\int_{23}^{31}f(x)dx+\int_{31}^{32}f(x)dx\\&\int_{-4}^{32}f(x)dx=(-13)-(56)+(-53)+(96)+(-44)\\&\int_{-4}^{32}f(x)dx=-70\\&\end{align*}$

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Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

$\begin{align*}&\int_{3}^{6}f(x)dx=-8\\&\int_{6}^{16}f(x)dx=-87\\&\int_{24}^{16}f(x)dx=-85\\&\int_{39}^{24}f(x)dx=48\\&\int_{53}^{39}f(x)dx=42\\&\text{Determine }\int_{3}^{53}f(x)dx\end{align*}$

Possible Answers:

Correct answer:

Explanation:

$\begin{align*}&\text{One of the principles of integrals is one of summation. If the}\\&\text{values of an integral across certain sets of points is known,}\\&\text{this could potentially be used to find integral values at other}\\&\text{points. Imagine a set of points that are in ascending numerical}\\&\text{value: a, b, c, and d. It follows that:}\\&\int_a^d=\int_a^b+\int_b^c+\int_c^d\\&\text{Another principle of integrals is that if an integral value}\\&\text{is known, to take the same integral backwards will give a negative}\\&\text{of the original value:}\\&\int_a^b=-\int_b^a\\&\text{Knowing this, we can calculate }\int_{3}^{53}f(x)dx\\&\int_{3}^{53}f(x)dx=\int_{3}^{6}f(x)dx+\int_{6}^{16}f(x)dx-\int_{24}^{16}f(x)dx-\int_{39}^{24}f(x)dx-\int_{53}^{39}f(x)dx\\&\int_{3}^{53}f(x)dx=(-8)+(-87)-(-85)-(48)-(42)\\&\int_{3}^{53}f(x)dx=-100\\&\end{align*}$

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AP Calculus AB : Basic properties of definite integrals (additivity and linearity)

Study concepts, example questions & explanations for AP Calculus AB

All AP Calculus AB Resources

Example Questions

Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

Example Question #5 : Basic Properties Of Definite Integrals (Additivity And Linearity)

Example Question #33 : Interpretations And Properties Of Definite Integrals

Example Question #1 : Basic Properties Of Definite Integrals (Additivity And Linearity)

All AP Calculus AB Resources

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