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Common Core: 3rd Grade Math : Add and Subtract Within 1000: CCSS.Math.Content.3.NBT.A.2

Study concepts, example questions & explanations for Common Core: 3rd Grade Math

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All Common Core: 3rd Grade Math Resources

7 Diagnostic Tests 226 Practice Tests Question of the Day Flashcards Learn by Concept

Example Questions

Example Question #1991 : Common Core Math: Grade 3

Solve:

$\frac{\begin{array}[b]{r}335\\ +\ 204\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}335\\ +\ 204\end{array}}{\space }$

Possible Answers:

539 $\displaystyle 539$

536 $\displaystyle 536$

537 $\displaystyle 537$

538 $\displaystyle 538$

Correct answer:

539 $\displaystyle 539$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

5+4=9 $\displaystyle 5+4=9$

Add the numbers in the tens place:

3+0=3 $\displaystyle 3+0=3$

Add the numbers in the hundreds place:

3+2=5 $\displaystyle 3+2=5$

Your final answer should be 539: $\displaystyle 539:$

$\frac{\begin{array}[b]{r}335\\ +\ 204\end{array}}{\ \ \ \ 539 }$ $\displaystyle \frac{\begin{array}[b]{r}335\\ +\ 204\end{array}}{\ \ \ \ 539 }$

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Example Question #1992 : Common Core Math: Grade 3

Solve:

$\frac{\begin{array}[b]{r}430\\ +\ 126\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}430\\ +\ 126\end{array}}{\space }$

Possible Answers:

553 $\displaystyle 553$

556 $\displaystyle 556$

554 $\displaystyle 554$

555 $\displaystyle 555$

Correct answer:

556 $\displaystyle 556$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

0+6=6 $\displaystyle 0+6=6$

Add the numbers in the tens place:

3+2=5 $\displaystyle 3+2=5$

Add the numbers in the hundreds place:

4+1=5 $\displaystyle 4+1=5$

Your final answer should be 556: $\displaystyle 556:$

$\frac{\begin{array}[b]{r}430\\ +\ 126\end{array}}{\ \ \ 556 }$ $\displaystyle \frac{\begin{array}[b]{r}430\\ +\ 126\end{array}}{\ \ \ 556 }$

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Example Question #1993 : Common Core Math: Grade 3

Solve:

$\frac{\begin{array}[b]{r}487\\ +\ 410\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}487\\ +\ 410\end{array}}{\space }$

Possible Answers:

897 $\displaystyle 897$

896 $\displaystyle 896$

894 $\displaystyle 894$

895 $\displaystyle 895$

Correct answer:

897 $\displaystyle 897$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

7+0=7 $\displaystyle 7+0=7$

Add the numbers in the tens place:

8+1=9 $\displaystyle 8+1=9$

Add the numbers in the hundreds place:

4+4=8 $\displaystyle 4+4=8$

Your final answer should be 897: $\displaystyle 897:$

$\frac{\begin{array}[b]{r}487\\ +\ 410\end{array}}{\ \ \ 897}$ $\displaystyle \frac{\begin{array}[b]{r}487\\ +\ 410\end{array}}{\ \ \ 897}$

Report an Error

Example Question #1994 : Common Core Math: Grade 3

Solve:

$\frac{\begin{array}[b]{r}369\\ +\ 221\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}369\\ +\ 221\end{array}}{\space }$

Possible Answers:

591 $\displaystyle 591$

592 $\displaystyle 592$

593 $\displaystyle 593$

590 $\displaystyle 590$

Correct answer:

590 $\displaystyle 590$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

9+1=10 $\displaystyle 9+1=10$

Because this sum is greater than $\displaystyle 9$, we write the $\displaystyle 0$ from the ones place and carry the $\displaystyle 1$ from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}3^{{\color{Red} 1}}6\ 9\\ +\ 2\ 2\ 1\end{array}}{\ \ \ \ \ \ \ \ 0 }$ $\displaystyle \frac{\begin{array}[b]{r}3^{{\color{Red} 1}}6\ 9\\ +\ 2\ 2\ 1\end{array}}{\ \ \ \ \ \ \ \ 0 }$

Add the numbers in the tens place, including the $\displaystyle 1$ that was carried over:

1+6+2=9 $\displaystyle 1+6+2=9$

Add the numbers in the hundreds place:

3+2=5 $\displaystyle 3+2=5$

Your final answer should be 590: $\displaystyle 590:$

$\frac{\begin{array}[b]{r}369\\ +\ 221\end{array}}{\ \ \ 590 }$ $\displaystyle \frac{\begin{array}[b]{r}369\\ +\ 221\end{array}}{\ \ \ 590 }$

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Example Question #1995 : Common Core Math: Grade 3

Solve:

$\frac{\begin{array}[b]{r}328\\ +\ 628\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}328\\ +\ 628\end{array}}{\space }$

Possible Answers:

957 $\displaystyle 957$

958 $\displaystyle 958$

959 $\displaystyle 959$

956 $\displaystyle 956$

Correct answer:

956 $\displaystyle 956$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

8+8=16 $\displaystyle 8+8=16$

Because this sum is greater than $\displaystyle 9$, we write the $\displaystyle 6$ from the ones place and carry the $\displaystyle 1$ from he tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}3^{{\color{Red} 1}}2\ 8\\ +\ 6\ 2\ 8\end{array}}{\ \ \ \ \ \ \ \ 6 }$ $\displaystyle \frac{\begin{array}[b]{r}3^{{\color{Red} 1}}2\ 8\\ +\ 6\ 2\ 8\end{array}}{\ \ \ \ \ \ \ \ 6 }$

Add the numbers in the tens place, including the $\displaystyle 1$ that was carried over:

1+2+2=5 $\displaystyle 1+2+2=5$

Add the numbers in the hundreds place:

3+6=9 $\displaystyle 3+6=9$

Your final answer should be 956: $\displaystyle 956:$

$\frac{\begin{array}[b]{r}328\\ +\ 628\end{array}}{\ \ \ 956 }$ $\displaystyle \frac{\begin{array}[b]{r}328\\ +\ 628\end{array}}{\ \ \ 956 }$

Report an Error

Example Question #181 : Understanding Place Value And Properties Of Operations For Multi Digit Arithmetic

Solve:

$\frac{\begin{array}[b]{r}295\\ +\ 519\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}295\\ +\ 519\end{array}}{\space }$

Possible Answers:

815 $\displaystyle 815$

814 $\displaystyle 814$

816 $\displaystyle 816$

813 $\displaystyle 813$

Correct answer:

814 $\displaystyle 814$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

5+9=14 $\displaystyle 5+9=14$

Because this sum is greater than $\displaystyle 9$, we write the $\displaystyle 4$ from the ones place and carry the $\displaystyle 1$ from he tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}2^{{\color{Red} 1}}9\ 5\\ +\ 5\ 1\ 9\end{array}}{\ \ \ \ \ \ \ \ 4 }$ $\displaystyle \frac{\begin{array}[b]{r}2^{{\color{Red} 1}}9\ 5\\ +\ 5\ 1\ 9\end{array}}{\ \ \ \ \ \ \ \ 4 }$

Add the numbers in the tens place, including the $\displaystyle 1$ that was carried over:

$\displaystyle 1+9+1=11$

Because this sum is greater than $\displaystyle 9$, we write the $\displaystyle 1$ from the ones place and carry the $\displaystyle 1$ from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}^{{\color{Red} 1}}2^{{\color{Red} 1}}9\ 5\\ +\ 5\ 1\ 9\end{array}}{\ \ \ \ \ \ 1\ 4 }$ $\displaystyle \frac{\begin{array}[b]{r}^{{\color{Red} 1}}2^{{\color{Red} 1}}9\ 5\\ +\ 5\ 1\ 9\end{array}}{\ \ \ \ \ \ 1\ 4 }$

Add the numbers in the hundreds place, including the $\displaystyle 1$ that was carried over:

1+2+5=8 $\displaystyle 1+2+5=8$

Your final answer should be 814: $\displaystyle 814:$

$\frac{\begin{array}[b]{r}295\\ +\ 519\end{array}}{\ \ \ 814}$ $\displaystyle \frac{\begin{array}[b]{r}295\\ +\ 519\end{array}}{\ \ \ 814}$

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Example Question #1996 : Common Core Math: Grade 3

Solve:

$\frac{\begin{array}[b]{r}500\\ +\ 224\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}500\\ +\ 224\end{array}}{\space }$

Possible Answers:

727 $\displaystyle 727$

724 $\displaystyle 724$

726 $\displaystyle 726$

725 $\displaystyle 725$

Correct answer:

724 $\displaystyle 724$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

0+4=4 $\displaystyle 0+4=4$

Add the numbers in the tens place:

0+2=2 $\displaystyle 0+2=2$

Add the numbers in the hundreds place:

5+2=7 $\displaystyle 5+2=7$

Your final answer should be 724: $\displaystyle 724:$

$\frac{\begin{array}[b]{r}500\\ +\ 224\end{array}}{\ \ \ 724 }$ $\displaystyle \frac{\begin{array}[b]{r}500\\ +\ 224\end{array}}{\ \ \ 724 }$

Report an Error

Example Question #1997 : Common Core Math: Grade 3

Solve:

$\frac{\begin{array}[b]{r}269\\ +\ 323\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}269\\ +\ 323\end{array}}{\space }$

Possible Answers:

593 $\displaystyle 593$

591 $\displaystyle 591$

590 $\displaystyle 590$

592 $\displaystyle 592$

Correct answer:

592 $\displaystyle 592$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

9+3=12 $\displaystyle 9+3=12$

Because this sum is greater than $\displaystyle 9$, we write the $\displaystyle 2$ from the ones place and carry the $\displaystyle 1$ from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}2^{{\color{Red} 1}}6\ 9\\ +\ 3\ 2\ 3\end{array}}{\ \ \ \ \ \ \ \ 2 }$ $\displaystyle \frac{\begin{array}[b]{r}2^{{\color{Red} 1}}6\ 9\\ +\ 3\ 2\ 3\end{array}}{\ \ \ \ \ \ \ \ 2 }$

Add the numbers in the tens place, including the $\displaystyle 1$ that was carried over:

1+6+2=9 $\displaystyle 1+6+2=9$

Add the numbers in the hundreds place:

2+3=5 $\displaystyle 2+3=5$

Your final answer should be 592: $\displaystyle 592:$

$\frac{\begin{array}[b]{r}269\\ +\ 323\end{array}}{\ \ \ 592 }$ $\displaystyle \frac{\begin{array}[b]{r}269\\ +\ 323\end{array}}{\ \ \ 592 }$

Report an Error

Example Question #1998 : Common Core Math: Grade 3

Solve:

$\frac{\begin{array}[b]{r}228\\ +\ 548\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}228\\ +\ 548\end{array}}{\space }$

Possible Answers:

778 $\displaystyle 778$

776 $\displaystyle 776$

775 $\displaystyle 775$

777 $\displaystyle 777$

Correct answer:

776 $\displaystyle 776$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

8+8=16 $\displaystyle 8+8=16$

Because this sum is greater than $\displaystyle 9$, we write the $\displaystyle 6$ from the ones place and carry the $\displaystyle 1$ from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}2^{{\color{Red} 1}}2\ 8\\ +\ 5\ 4\ 8\end{array}}{\ \ \ \ \ \ \ \ 6 }$ $\displaystyle \frac{\begin{array}[b]{r}2^{{\color{Red} 1}}2\ 8\\ +\ 5\ 4\ 8\end{array}}{\ \ \ \ \ \ \ \ 6 }$

Add the numbers in the tens place, including the $\displaystyle 1$ that was carried over:

1+2+4=7 $\displaystyle 1+2+4=7$

Add the numbers in the hundreds place:

2+5=7 $\displaystyle 2+5=7$

Your final answer should be 776: $\displaystyle 776:$

$\frac{\begin{array}[b]{r}228\\ +\ 548\end{array}}{\ \ \ 776}$ $\displaystyle \frac{\begin{array}[b]{r}228\\ +\ 548\end{array}}{\ \ \ 776}$

Report an Error

Example Question #1999 : Common Core Math: Grade 3

Solve:

$\frac{\begin{array}[b]{r}507\\ +\ 328\end{array}}{\space }$ $\displaystyle \frac{\begin{array}[b]{r}507\\ +\ 328\end{array}}{\space }$

Possible Answers:

835 $\displaystyle 835$

833 $\displaystyle 833$

834 $\displaystyle 834$

832 $\displaystyle 832$

Correct answer:

835 $\displaystyle 835$

Explanation:

When we add with multi-digit numbers, we start with the numbers in the ones place, and then move to the left to the tens place, followed by the hundreds place.

Add the numbers in the ones place:

7+8=15 $\displaystyle 7+8=15$

Because this sum is greater than $\displaystyle 9$, we write the $\displaystyle 5$ from the ones place and carry the $\displaystyle 1$ from the tens place over to the left. Your work should look something like this:

$\frac{\begin{array}[b]{r}5^{{\color{Red} 1}}0\ 7\\ +\ 3\ 2\ 8\end{array}}{\ \ \ \ \ \ \ \ 5 }$ $\displaystyle \frac{\begin{array}[b]{r}5^{{\color{Red} 1}}0\ 7\\ +\ 3\ 2\ 8\end{array}}{\ \ \ \ \ \ \ \ 5 }$

Add the numbers in the tens place, including the $\displaystyle 1$ that was carried over:

1+0+2=3 $\displaystyle 1+0+2=3$

Add the numbers in the hundreds place:

5+3=8 $\displaystyle 5+3=8$

Your final answer should be 835: $\displaystyle 835:$

$\frac{\begin{array}[b]{r}507\\ +\ 328\end{array}}{\ \ \ 835}$ $\displaystyle \frac{\begin{array}[b]{r}507\\ +\ 328\end{array}}{\ \ \ 835}$

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All Common Core: 3rd Grade Math Resources

7 Diagnostic Tests 226 Practice Tests Question of the Day Flashcards Learn by Concept

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Common Core: 3rd Grade Math : Add and Subtract Within 1000: CCSS.Math.Content.3.NBT.A.2

Study concepts, example questions & explanations for Common Core: 3rd Grade Math

All Common Core: 3rd Grade Math Resources

Example Questions

Example Question #1991 : Common Core Math: Grade 3

Example Question #1992 : Common Core Math: Grade 3

Example Question #1993 : Common Core Math: Grade 3

Example Question #1994 : Common Core Math: Grade 3

Example Question #1995 : Common Core Math: Grade 3

Example Question #181 : Understanding Place Value And Properties Of Operations For Multi Digit Arithmetic

Example Question #1996 : Common Core Math: Grade 3

Example Question #1997 : Common Core Math: Grade 3

Example Question #1998 : Common Core Math: Grade 3

Example Question #1999 : Common Core Math: Grade 3

All Common Core: 3rd Grade Math Resources

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