All Differential Equations Resources
Example Questions
Example Question #1 : Separable Variables
Solve the given differential equation by separation of variables.
To solve this differential equation use separation of variables. This means move all terms containing to one side of the equation and all terms containing to the other side.
First, multiply each side by .
Now divide by on both sides.
Next, divide by on both sides.
From here take the integral of both sides. Remember rules for logarithmic functions as they will be used in this problem.
Example Question #1 : Separable Variables
Solve the following differential equation
So this is a separable differential equation. The first step is to move all of the x terms (including dx) to one side, and all of the y terms (including dy) to the other side.
So the differential equation we are given is:
Which rearranged looks like:
At this point, in order to solve for y, we need to take the anti-derivative of both sides:
Which equals:
And since this an anti-derivative with no bounds, we need to include the general constant C
So, solving for y, we raise e to the power of both sides:
which, simplified gives us our answer:
Example Question #1 : First Order Differential Equations
Solve the following separable differential equation: with .
The simplest way to solve a separable differential equation is to rewrite as and, by an abuse of notation, to "multiply both sides by dt". This yields
.
Next, we get all the y terms with dy and all the t terms with dt and integrate. Thus,
Combining the constants of integration and exponentiating, we have
The plus minus and the can be combined into another arbitrary constant, yielding .
Plugging in our initial condition, we have
and
Example Question #1 : First Order Differential Equations
Solve the general solution for the ODE:
where C is an arbitrary constant
where C is an arbitrary constant
where C is an arbitrary constant
where C is an arbitrary constant
where C is an arbitrary constant
First the differential equation can be separated to:
And then integrated simply to:
Example Question #2 : Separable Variables
Is the following differential equation separable? If So, how does the equation separate?
The differential equation is separable and becomes:
The differential equation is separable and becomes:
This differential equation is autonomous and is therefore not separable.
The differential equation is separable and becomes:
The differential equation is separable and becomes:
Using exponential rules, we note that becomes . Meaning that the
differential equation is equivalent to:
which by separation of variables is:
Example Question #1 : Separable Variables
Is the following differential equation separable, if so, how does the equation separate?
The Differential equation is separable and becomes:
The differential equation is not separable.
The Differential equation is separable and becomes:
The Differential equation is separable and becomes:
The differential equation is not separable.
The differential equation cannot be written as and is therefore not separable.
Example Question #2 : Separable Variables
Solve the given differential equation by separation of variables.
To solve this differential equation use separation of variables. This means move all terms containing to one side of the equation and all terms containing to the other side.
First, multiply each side by .
Now divide by on both sides.
Next, divide by on both sides.
From here take the integral of both sides. Remember rules for logarithmic functions as they will be used in this problem.
Example Question #1 : Separable Variables
Solve the following initial value problem: , .
This is a separable differential equation. The simplest way to solve this is to first rewrite as and then by an abuse of notation to "multiply both sides by dt." This yields . Then group all the y terms with dy and integrate, getting us to . Solving for y, we have . Plugging in our condition, we find . Raising both sides to the power of -1/3, we see . Thus, our final solution is
Example Question #1 : Separable Variables
Solve the following equation
This is a separable ODE, so rearranging
Integrating
Plugging in the initial condition and solving gives us
Solving for gives us
Example Question #1 : Linear & Exact Equations
Find the general solution of the given differential equation and determine if there are any transient terms in the general solution.
First, divide by on both sides of the equation.
Identify the factor term.
Integrate the factor.
Substitute this value back in and integrate the equation.
Now divide by to get the general solution.
The transient term means a term that when the values get larger the term itself gets smaller. Therefore the transient term for this function is .
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