The volume of a given prism $\displaystyle V=Bh$, where $\displaystyle B$ is the base area and $\displaystyle h$ is the height. For a rectangular prism, the base area $\displaystyle B=l \times w$, or length times width. Therefore:

$\displaystyle V=Bh$

$\displaystyle V=(l\times w)h$

Substituting in our known values:

$\displaystyle V=(9\:cm\times 5\:cm)7\:cm$

$\displaystyle V=45\:cm^{2}\times 7\:cm$

$\displaystyle V=315\:cm^{3}$

The volume of a given prism $\displaystyle V=Bh$, where $\displaystyle B$ is the base area and $\displaystyle h$ is the height. For a circular prism, the base area $\displaystyle B=\pi r^{2}$, or pi times the square of the radius. Therefore:

$\displaystyle V=(\pi r^{2})h$

Substituting in our known values:

$\displaystyle V=(\pi (11\:cm)^{2})(20\:cm)$

$\displaystyle V=(121\pi\:cm^{2})(20\:cm)$

$\displaystyle V=2420\pi\:cm^{3}$

The volume of a given prism $\displaystyle V=Bh$, where $\displaystyle B$ is the base area and $\displaystyle h$ is the prism height. For a triangular prism, the base area $\displaystyle B=\frac{1}{2}bh_{2}$, where $\displaystyle b$ is the base of the triangle and $\displaystyle h_{2}$ is the height of the triangle (not of the prism).

Therefore, we can substitute the base area equation into the equation for the volume of a prism:

$\displaystyle V=Bh$

$\displaystyle V=(\frac{1}{2}bh_{2})h$

Substituting in our known values:

$\displaystyle V=(\frac{1}{2}(4\:cm)(8\:cm))(12\:cm)$

$\displaystyle V=(16\:cm^{2})(12\:cm)$

$\displaystyle V=192\:cm^{3}$

The volume $\displaystyle V$ of a rectangular prism is the product of its base area $\displaystyle A$ and its height $\displaystyle h$: $\displaystyle V=Ah$. Since we can determine the base area of the rectangular prism from its length and width, we can rewrite the equation and solve:

$\displaystyle V=Ah$

$\displaystyle V=lwh$

$\displaystyle V=(12)(6)(8)$

$\displaystyle V=12 \times48$

$\displaystyle V=576$

The volume $\displaystyle V$ of a rectangular prism is the product of its base area $\displaystyle A$ and its height $\displaystyle h$: $\displaystyle V=Ah$. Since we can determine the base area of the rectangular prism from its length and width, we can rewrite the equation and solve:

$\displaystyle V=Ah$

$\displaystyle V=lwh$

$\displaystyle V=(10)(7)(25)$

$\displaystyle V=1050$

The formula for volume of a rectangular prism is $\displaystyle \small v=l\times w\times h$

$\displaystyle \small v=3\times1\times2$

$\displaystyle \small v=6cm^3$

Remember, volume is always labeled as units to the third power. 

The formula for volume of a rectangular prism is $\displaystyle \small v=l\times w\times h$

$\displaystyle \small v=6\times3\times2$

$\displaystyle \small v=36cm^3$

Remember, volume is always labeled as units to the third power. 

The formula for volume of a rectangular prism is $\displaystyle \small v=l\times w\times h$

$\displaystyle \small v=2\times3\times7$

$\displaystyle \small v=42cm^3$

Remember, volume is always labeled as units to the third power. 

The formula for volume of a rectangular prism is $\displaystyle \small v=l\times w\times h$

$\displaystyle \small v=8\times4\times6$

$\displaystyle \small v=192cm^3$

Remember, volume is always labeled as units to the third power. 

The formula for volume of a rectangular prism is $\displaystyle \small v=l\times w\times h$

$\displaystyle \small v=6\times3\times6$

$\displaystyle \small v=108cm^3$

Remember, volume is always labeled as units to the third power.