### All Algebra II Resources

## Example Questions

### Example Question #1 : Graphing Parabolic Inequalities

Give the solution set of the inequality:

**Possible Answers:**

The inequality has no solution

**Correct answer:**

Rewrite in standard form and factor:

The zeroes of the polynomial are therefore , so we test one value in each of three intervals , , and to determine which ones are included in the solution set.

:

Test :

False; is not in the solution set.

:

Test

True; is in the solution set

:

Test :

False; is not in the solution set.

Since the inequality symbol is , the boundary points are not included. The solution set is the interval .

### Example Question #2 : Graphing Parabolic Inequalities

Give the set of solutions for this inequality:

**Possible Answers:**

This inequality has no solution.

**Correct answer:**

The first step of questions like this is to get the quadratic in its standard form. So we move the over to the left side of the inequality:

This quadratic can easily be factored as. So now we can write this in the form

and look at each of the factors individually. Recall that a negative number times a negative is a positive number. Therefore the boundaries of our solution interval is going to be when both of these factors are negative. is negative whenever , and is negative whenever . Since , one of our boundaries will be . Remember that this will be an open interval since it is less than, not less than or equal to.

Our other boundary will be the other point when the product of the factors becomes positive. Remember that is positive when , so our other boundary is . So the solution interval we arrive at is

### Example Question #3 : Graphing Parabolic Inequalities

Solve for

**Possible Answers:**

**Correct answer:**

When asked to solve for x we need to isolate x on one side of the equation.

To do this our first step is to subtract 7 from both sides.

From here, we divide by 4 to solve for x.

### Example Question #4 : Graphing Parabolic Inequalities

Solve for

**Possible Answers:**

**Correct answer:**

When asked to solve for y we need to isolate the variable on one side and the constants on the other side.

To do this we first add 9 to both sides.

From here, we divide by -12 to solve for y.

### Example Question #5 : Graphing Parabolic Inequalities

The graphs for the lines and are shown in the figure. The region is defined by which two inequalities?

**Possible Answers:**

**Correct answer:**

The region contains only values which are greater than or equal to those on the line , so its values are .

Also, the region contains only values which are less than or equal to those on the line , so its values are .

### Example Question #1 : Quadratic Inequalities

The graphs of the lines and are shown on the figure. The region is defined by which two inequalities?

**Possible Answers:**

**Correct answer:**

The region contains only values which are greater than or equal to those on the line , so its values are .

Similarly, the region contains only values which are less than or equal to those on the line , so its values are .

### Example Question #11 : New Sat Math Calculator

Which of the following graphs correctly represents the quadratic inequality below (solutions to the inequalities are shaded in blue)?

**Possible Answers:**

**Correct answer:**

To begin, we analyze the equation given: the base equation, is shifted *left* one unit and *vertically stretched* by a factor of 2. The graph of the equation is:

To solve the inequality, we need to take a test point and plug it in to see if it matches the inequality. The only points that cannot be used are those directly on our parabola, so let's use the origin . If plugging this point in makes the inequality *true*, then we shade the area containing that point (in this case, *outside *the parabola); if it makes the inequality *untrue*, then the opposite side is shaded (in this case, the *inside* of the parabola). Plugging the numbers in shows:

Simplified as:

Which is *not* true, so the area inside of the parabola should be shaded, resulting in the following graph: