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AP Physics C Electricity : Current

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Example Questions

Example Question #1 : Current

A lamp has a 60W bulb. If the house wiring provides 110V to light up that bulb, how much current does the bulb draw?

Possible Answers:

$0.72\ \text{A}$

$1.37\ \text{A}$

$0.03\ \text{A}$

$0.55\ \text{A}$

$5.83\ \text{A}$

Correct answer:

$0.55\ \text{A}$

Explanation:

The formula for power is , P=IV and we are given the following values.

$P=60\ \text{W}$

$V=110\ \text{V}$

Solve for the current, .

$I=\frac{P}{V}=\frac{60\ \text{W}}{110\ \text{V}}=0.55\ \text{A}$

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Example Question #2 : Current

A particle accelerator with a radius of 500 meters can have up to $10^{15}$ protons circulating within it at once.

$q_{proton}=1.60*10^{-19}C$

How fast must the protons in the accelerator move in order to produce a current of 1A?

Possible Answers:

$9.21*10^{7}\frac{m}{s}$

$2.04*10^8\frac{m}{s}$

$1.96*10^7\frac{m}{s}$

$1.95*10^6\frac{m}{s}$

$3.00*10^8\frac{m}{s}$

Correct answer:

$1.96*10^7\frac{m}{s}$

Explanation:

The current produced is the total charge that circulates the particle accelerator per unit time.

$I=\frac{dQ}{dt}$

We calculate this by the equation:

$I = \frac{nqv}{2\pi R}$

is the number of protons, is the charge per proton, is the velocity of each proton, and is the radius of the particle accelerator.

Using the given current, we then solve for the velocity:

$1A = \frac{(10^{15})(1.60*10^{-19}C)v}{2\pi (500m)}$

$v=\frac{(1A)2\pi(500m)}{(10^{15})(1.60*10^{-19}C)}= 1.96*10^7\frac{m}{s}$

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All AP Physics C Electricity Resources

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AP Physics C Electricity : Current

Study concepts, example questions & explanations for AP Physics C Electricity

All AP Physics C Electricity Resources

Example Questions

Example Question #1 : Current

Example Question #2 : Current

All AP Physics C Electricity Resources

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