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Flashcards: Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

Evaluate: $169^{\frac{3}{2}}$ $\displaystyle 169^{\frac{3}{2}}$

235.5 $\displaystyle 235.5$

169 $\displaystyle 169$

2197 $\displaystyle 2197$

$\displaystyle 13$

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All Common Core: High School - Number and Quantity Resources

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Flashcards: Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

Evaluate: $169^{\frac{3}{2}}$ $\displaystyle 169^{\frac{3}{2}}$

235.5 $\displaystyle 235.5$

169 $\displaystyle 169$

2197 $\displaystyle 2197$

$\displaystyle 13$

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Flashcards: Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

Evaluate: $169^{\frac{3}{2}}$ $\displaystyle 169^{\frac{3}{2}}$

Your answer:

235.5 $\displaystyle 235.5$

Your answer:

169 $\displaystyle 169$

Your answer:

$\displaystyle 13$

Correct answer:

2197 $\displaystyle 2197$

Explanation:

To evaluate this, let's rewrite the problem.

$169^{\frac{3}{2}}=(\sqrt[]{64})^3$ $\displaystyle 169^{\frac{3}{2}}=(\sqrt[]{64})^3$

Now lets break down the square root.

$(\sqrt[]{169})^3=(\sqrt[]{13\cdot13})^3=(\sqrt[]{13^2})^3=13^3=2197$ $\displaystyle (\sqrt[]{169})^3=(\sqrt[]{13\cdot13})^3=(\sqrt[]{13^2})^3=13^3=2197$

Flashcards: Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

If the temperature is $33 ^{\circ} C$ $\displaystyle 33 ^{\circ} C$ find the temperature in degrees Fahrenheit.

$\displaystyle 33$

$\displaystyle 65$

92.4 $\displaystyle 92.4$

59.4 $\displaystyle 59.4$

91.4 $\displaystyle 91.4$

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Flashcards: Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

If the temperature is $33 ^{\circ} C$ $\displaystyle 33 ^{\circ} C$ find the temperature in degrees Fahrenheit.

Your answer:

$\displaystyle 33$

Your answer:

$\displaystyle 65$

Your answer:

92.4 $\displaystyle 92.4$

Your answer:

59.4 $\displaystyle 59.4$

Correct answer:

91.4 $\displaystyle 91.4$

Explanation:

In order to do this problem, we need to recall the equation that converts Celsius into Fahrenheit.

$\displaystyle F = 1.8 C + 32$

Since we are given Celsius, we simply plug it into the equation for, $\uptext{C}$ $\displaystyle \uptext{C}$ .

$F = 1.8 \cdot 33 +32$ $\displaystyle F = 1.8 \cdot 33 +32$

$\displaystyle F = 59.4 +32$

$\displaystyle F = 91.4$

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Flashcards: Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

All Common Core: High School - Number and Quantity Resources

Flashcards: Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

Flashcards: Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

Flashcards: Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

Flashcards: Use, Understand, and Interpret Units: CCSS.Math.Content.HSN-Q.A.1

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