\(\displaystyle \small mean=\frac{sum\ of\ all\ values}{number\ of\ values}\)

\(\displaystyle \small mean=\frac{29+40+40+20+11}{5}=\frac{140}{5}=28\)

\(\displaystyle \textup{The mean, or average, of a set of values }= \frac{\textup{sum of the values}}{\textup{number of values}}\)

In this list, \(\displaystyle \frac{\textup{sum of the values}}{\textup{number of values}}=\frac{18+19+20+20+22+22+23+24}{8}=21\)

The mean of a data set is the sum of its elements divided by the number of elements, which here is 8:

\(\displaystyle \frac{5+6+7+8+8+9+10+11}{8} = \frac{64}{8} = 8\)

The median of a data set with an even number of elements is the mean of the middle two values when the set is arranged in ascending order; both of the middle elements are 8, so the median is 8.

The mode of a data set is the most frequently occurring element. Here, only 8 appears twice, so it is the mode.

All three are equal.

The mean score is the sum of all scores divided by the number of scores.

First, find the sum of all three test scores, then divide by the number of tests, 3.

\(\displaystyle Average = \frac{Score 1 + Score 2 + Score 3}{Number\ of\ Scores}\)

If Veronica wants her average to be 80, the equation becomes:

\(\displaystyle 80 = \frac{75 + 71 + x}{3}\)

We need to solve for \(\displaystyle x\).

First, multiply both sides of the equation by 3:

\(\displaystyle 240= 75 + 71 + x\)

\(\displaystyle 240 = 146 + x\)

Subtract 146 from both sides:

\(\displaystyle 94 = x\)

Veronica must score a 94 on her third test in order to bring her mean score to 80.

The mean of a set is the sum of all elements divided by the number of elements in the set:

\(\displaystyle Mean = \frac{total\ sum}{\#\ of\ elements}\)

\(\displaystyle Mean = \frac{8+10+6+3+7+10+2+5+3}{9}= \frac{54}{9} = 6\)

The mean is $6.

The mean in a data set of scores is the sum of all scores divided by the number of scores:

\(\displaystyle Mean = \frac{Sum\ of\ Scores}{\#\ of\ Scores}\)

Call the fourth test score \(\displaystyle x\). Plug in what we know and solve for \(\displaystyle x\):

\(\displaystyle 90= \frac{100+70+96+x}{4} = \frac{266+x}{4}\)

Multiply both sides by 4:

\(\displaystyle 360= 266 + x\)

Then, subtract 266 from both sides:.

\(\displaystyle 94 = x\)

To finish with a mean of 90, James must score a 94 on his fourth test.

\(\displaystyle mean=\frac{\textup{sum of the elements}}{\textup{\# of elements}}=\frac{72+143+68+171+91}{5}=\frac{545}{5}=109\)

In order for John to maintain a 90 average for the marking period, his total for four tests must be 360.

\(\displaystyle \frac{360}{4} = 90\) or  \(\displaystyle 90 \times 4 = 360\)

If you add up the scores that he already received, he already has 267 points.

\(\displaystyle 78+ 89 + 100 = 267\)

If you take the total of 267, which is the total amount of points for the three tests already taken and subtract it from the 360 points which is the total amount of points needed for a 90 average, he would need to get a 93 on his last test.

\(\displaystyle 360 - 267 = 93\)

The mean is the average of all the numbers in the set of data.

Add the numbers together and divide the sum by 4.

\(\displaystyle \frac{5+(-9)+14+1}{4} = \frac{11}{4}\)

The answer is:  \(\displaystyle \frac{11}{4}\)

The mean is the average of all the number ins the data set.

Add all the numbers and divide the sum by four.

\(\displaystyle \frac{3+(-8)+26+19}{4} = \frac{40}{4}\)

The answer is:  \(\displaystyle 10\)