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High School Math : How to find the area of a polygon

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Example Questions

Example Question #2 : Geometry

What is the area of a regular heptagon with an apothem of 4 and a side length of 6?

Possible Answers:

Correct answer:

Explanation:

What is the area of a regular heptagon with an apothem of 4 and a side length of 6?

To find the area of any polygon with the side length and the apothem we must know the equation for the area of a polygon which is

First, we must calculate the perimeter using the side length.

To find the perimeter of a regular polygon we take the length of each side and multiply it by the number of sides.

In a heptagon the number of sides is 7 and in this example the side length is 6 so

The perimeter is .

Then we plug in the numbers for the apothem and perimeter into the equation yielding

We then multiply giving us the area of .

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Example Question #5 : Plane Geometry

What is the area of a regular decagon with an apothem of 15 and a side length of 25?

Possible Answers:

3750

2750

375

1875

Correct answer:

1875

Explanation:

To find the area of any polygon with the side length and the apothem we must know the equation for the area of a polygon which is

First, we must calculate the perimeter using the side length.

To find the perimeter of a regular polygon we take the length of each side and multiply it by the number of sides.

In a decagon the number of sides is 10 and in this example the side length is 25 so 25*10=250

The perimeter is 250 .

Then we plug in the numbers for the apothem and perimeter into the equation yielding $Area\:of\:Polygon=\frac{1}{2}(250)15$

We then multiply giving us the area of 1875 .

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Example Question #3 : Geometry

What is the area of a regular heptagon with an apothem of and a side length of ?

Possible Answers:

112

224

Correct answer:

112

Explanation:

To find the area of any polygon with the side length and the apothem we must know the equation for the area of a polygon which is

We must then calculate the perimeter using the side length.

To find the perimeter of a regular polygon we take the length of each side and multiply it by the number of sides .

In a heptagon the number of sides is and in this example the side length is so 8*7=56

The perimeter is 56.

Then we plug in the numbers for the apothem and perimeter into the equation yielding $Area=(\frac{1}{2})(56)(4)$

We then multiply giving us the area of 112 .

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Example Question #4 : Geometry

Find the area of the shaded region:

Screen_shot_2014-02-27_at_6.53.35_pm

Possible Answers:

75m^2

$100\pi m^2 - 25m^2$

$100m^2 + 25\pi m^2$

$100m^2 - 25\pi m^2$

$75\pi m^2$

Correct answer:

$100m^2 - 25\pi m^2$

Explanation:

To find the area of the shaded region, you must subtract the area of the circle from the area of the square.

The formula for the shaded area is:

$A=A_{square}-A_{circle}$

$A = (s)^2 - \pi(r)^2$ ,

where is the side of the square and is the radius of the circle.

Plugging in our values, we get:

$A = (10m)^2 - \pi(5m)^2$

$A = 100m^2 - 25\pi m^2$

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Example Question #5 : Plane Geometry

Find the area of the shaded region:

Screen_shot_2014-03-01_at_9.02.03_pm

Possible Answers:

$6\pi - 18cm^2$

$6\pi - 9cm^2$

$9\pi - 18cm^2$

$9\pi - 9cm^2$

$9\pi - 24cm^2$

Correct answer:

$9\pi - 18cm^2$

Explanation:

To find the area of the shaded region, you need to subtract the area of the triangle from the area of the sector:

$A = A_{sector} - A_{triangle}$

$A = \pi r^2 (part) - \frac{1}{2} (b)(h)$

Where is the radius of the circle, part is the fraction of the circle, is the base of the triangle, and is the height of the triangle

Plugging in our values, we get

$A = \pi (6cm^2) (\frac{90}{360}) - \frac{1}{2} (6cm)(6cm)$

$A = 9\pi - 18cm^2$

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Example Question #7 : Plane Geometry

Find the area of the shaded region:

Screen_shot_2014-03-01_at_9.04.49_pm

Possible Answers:

$\frac{25\pi }{6}- \frac{25\sqrt{3}}{6} cm^2$

$\frac{25\pi }{6}- \frac{25\sqrt{3}}{4} cm^2$

$\frac{25\pi }{4}- \frac{25\sqrt{3}}{4} cm^2$

$\frac{25\pi }{4}- \frac{25\sqrt{3}}{6} cm^2$

$\frac{25\pi }{6}- \frac{25\sqrt{2}}{4} cm^2$

Correct answer:

$\frac{25\pi }{6}- \frac{25\sqrt{3}}{4} cm^2$

Explanation:

To find the area of the shaded region, you need to subtract the area of the equilateral triangle from the area of the sector:

$A = A_{sector} - A_{equilateral triangle}$

$A = \pi r^2 (part) - \frac{s^2 \sqrt{3}}{4}$

Where is the radius of the circle, part is the fraction of the circle, and is the side of the triangle

Plugging in our values, we get

$A = \pi (5cm^2) \frac{60}{360} - \frac{(5cm)^2\sqrt{3}}{4}$

$A=\frac{25\pi }{6}- \frac{25\sqrt{3}}{4} cm^2$

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Example Question #1 : How To Find The Area Of A Polygon

Find the area of the shaded region:

Possible Answers:

$30 \pi\ m^2$

$32 \pi\ m^2$

$24 \pi\ m^2$

$26 \pi\ m^2$

$28 \pi\ m^2$

Correct answer:

$28 \pi\ m^2$

Explanation:

The formula for the area of the shaded region is

$A = A_{large circle}-A_{small circle}= \pi r_{large}^2 - \pi r_{small}^2,$

where is the radius of the circle.

Plugging in our values, we get:

$A = \pi (8\ m)^2 - \pi (6\ m)^2$

$A = 28 \pi\ m^2$

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Example Question #2 : How To Find The Area Of A Polygon

Find the area of the following octagon:

Possible Answers:

$288\sqrt{2}+288\ m^2$

$200\sqrt{2}+288\ m^2$

$288\sqrt{2}+280\ m^2$

$280\sqrt{2}+288\ m^2$

$280\sqrt{2}+280\ m^2$

Correct answer:

$288\sqrt{2}+288\ m^2$

Explanation:

The formula for the area of a regular octagon is:

$A = \frac{1}{2}(perimeter)(apothem)$

Plugging in our values, we get:

$A = \frac{1}{2}(96\ m)(6\sqrt{2}\ m+6\ m)$

$A = 288\sqrt{2}+288\ m^2$

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Example Question #1 : How To Find The Area Of A Polygon

Find the area of a rectangle with a base of (x + 3) and a width of (x - 3) in terms of .

Possible Answers:

$x^{2 } - 3x - 9$

$x^{2 } + 9$

$x^{2}$

none of the other answers

$x^{2} - 9$

Correct answer:

$x^{2} - 9$

Explanation:

This problem simply becomes a matter of FOILing (first outer inner last)

The area of the shape is Base times Height.

So, multiplying (x + 3) and (x - 3) using FOIL, we get an area of $x^{2} - 9$

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Example Question #11 : Plane Geometry

Find the area of a square whose diagonal is .

Possible Answers:

144

none of these answers

Correct answer:

Explanation:

If the diagonal of a square is , we can use the pythagorean theorem to solve for the length of the sides.

= length of side of the square

Doing so, we get $2x^{2} = 144$

$x = \sqrt{72}$

To find the area of the square, we square , resulting in .

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High School Math : How to find the area of a polygon

Study concepts, example questions & explanations for High School Math

All High School Math Resources

Example Questions

Example Question #2 : Geometry

Example Question #5 : Plane Geometry

Example Question #3 : Geometry

Example Question #4 : Geometry

Example Question #5 : Plane Geometry

Example Question #7 : Plane Geometry

Example Question #1 : How To Find The Area Of A Polygon

Example Question #2 : How To Find The Area Of A Polygon

Example Question #1 : How To Find The Area Of A Polygon

Example Question #11 : Plane Geometry

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