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High School Physics : Understanding Calculations with Velocity

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Example Questions

Example Question #1 : Understanding Calculations With Velocity

A spring oscillates back and forth with a period of $\displaystyle 5s$. If its wavelength is 0.02m $\displaystyle 0.02m$, what is the speed of the spring?

Possible Answers:

$0.004\frac{m}{s}$ $\displaystyle 0.004\frac{m}{s}$

$0.025\frac{m}{s}$ $\displaystyle 0.025\frac{m}{s}$

$0.1\frac{m}{s}$ $\displaystyle 0.1\frac{m}{s}$

$1\frac{m}{s}$ $\displaystyle 1\frac{m}{s}$

$0.08\frac{m}{s}$ $\displaystyle 0.08\frac{m}{s}$

Correct answer:

$0.004\frac{m}{s}$ $\displaystyle 0.004\frac{m}{s}$

Explanation:

Velocity is commonly described with respect to wavelength and frequency.

$v=f\lambda$ $\displaystyle v=f\lambda$

We are given the period and the wavelength. Period is simply the inverse of freqeuncy.

$T=\frac{1}{f}$ $\displaystyle T=\frac{1}{f}$

Using this, we can rewrite our original equation in terms of the period.

$v=f\lambda=\frac{1}{T}\lambda$ $\displaystyle v=f\lambda=\frac{1}{T}\lambda$

Now we can use the values given in the question to solve for the velocity.

Plug in our given values and solve.

$v=\frac{1}{5s}(0.02m)$ $\displaystyle v=\frac{1}{5s}(0.02m)$

$v=0.004\frac{m}{s}$ $\displaystyle v=0.004\frac{m}{s}$

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Example Question #2 : Understanding Calculations With Velocity

A wave oscillates with a frequency of 20Hz $\displaystyle 20Hz$. If it has a speed of $30\frac{m}{s}$ $\displaystyle 30\frac{m}{s}$, what is its wavelength?

Possible Answers:

9.8m $\displaystyle 9.8m$

600m $\displaystyle 600m$

1.5m $\displaystyle 1.5m$

0.67m $\displaystyle 0.67m$

$\displaystyle 6m$

Correct answer:

1.5m $\displaystyle 1.5m$

Explanation:

The equation for velocity in terms of wavelength and frequency is $v=\lambda f$ $\displaystyle v=\lambda f$.

We are given the velocity and frequency. Using these values, we can solve for the wavelength.

$v=\lambda f$ $\displaystyle v=\lambda f$

$30\frac{m}{s}=\lambda * 20Hz$ $\displaystyle 30\frac{m}{s}=\lambda * 20Hz$

$\frac{30\frac{m}{s}}{20Hz}=\lambda$ $\displaystyle \frac{30\frac{m}{s}}{20Hz}=\lambda$

$1.5m=\lambda$ $\displaystyle 1.5m=\lambda$

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Example Question #3 : Understanding Calculations With Velocity

A note is played in a gas (which is not a normal atmosphere). Inside of this gas, the note has a frequency of 383Hz $\displaystyle 383Hz$ and a wavelength of 0.12m $\displaystyle 0.12m$. What is the speed of sound in this gas?

Possible Answers:

$4.22\frac{m}{s}$ $\displaystyle 4.22\frac{m}{s}$

$45.96\frac{m}{s}$ $\displaystyle 45.96\frac{m}{s}$

$0.022\frac{m}{s}$ $\displaystyle 0.022\frac{m}{s}$

$3191.67\frac{m}{s}$ $\displaystyle 3191.67\frac{m}{s}$

Correct answer:

$45.96\frac{m}{s}$ $\displaystyle 45.96\frac{m}{s}$

Explanation:

The relationship between velocity, frequency, and wavelength is:

$v=f\lambda$ $\displaystyle v=f\lambda$

Plug in the given information to solve:

$v=f\lambda$ $\displaystyle v=f\lambda$

$\displaystyle v=383Hz*0.12m$

$v=45.96\frac{m}{s}$ $\displaystyle v=45.96\frac{m}{s}$

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High School Physics : Understanding Calculations with Velocity

Study concepts, example questions & explanations for High School Physics

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Example Questions

Example Question #1 : Understanding Calculations With Velocity

Example Question #2 : Understanding Calculations With Velocity

Example Question #3 : Understanding Calculations With Velocity

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