All HiSET: Math Resources
Example Questions
Example Question #1 : Quadratic Equations
What is the vertex of the following quadratic polynomial?
Given a quadratic function
the vertex will always be
.
Thus, since our function is
, , and .
We plug these variables into the formula to get the vertex as
.
Hence, the vertex of
is
.
Example Question #2 : Quadratic Equations
Which of the following expressions represents the discriminant of the following polynomial?
The discriminant of a quadratic polynomial
is given by
.
Thus, since our quadratic polynomial is
,
, , and .
Plugging these values into the discriminant equation, we find that the discriminant is
.
Example Question #3 : Quadratic Equations
Which of the following polynomial equations has exactly one solution?
A polynomial equation of the form
has one and only one (real) solution if and only if its discriminant is equal to zero - that is, if its coefficients satisfy the equation
In each of the choices, and , so it suffices to determine the value of which satisfies this equation. Substituting, we get
Solve for by first adding 400 to both sides:
Take the square root of both sides:
The choice that matches this value of is the equation
Example Question #1 : Quadratic Equations
Give the nature of the solution set of the equation
Two irrational solutions
One rational solution
Two imaginary solutions
Two rational solutions
One imaginary solution
Two rational solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
To accomplish this, first, multiply the binomials on the left using the FOIL technique:
Collect like terms:
Add 6 to both sides:
The key to determining the nature of the solution set is to examine the discriminant . Setting , the value of the discriminant is
The discriminant is a positive number; furthermore, it is a perfect square, being equal to the square of 11. Therefore, the solution set comprises two rational solutions.
Example Question #2 : Understand And Apply Concepts Of Equations
Which of the following polynomial equations has exactly one solution?
A polynomial equation of the standard form
has one and only one (real) solution if and only if its discriminant is equal to zero - that is, if its coefficients satisfy the equation
Each of the choices can be rewritten in standard form by subtracting the term on the right from both sides. One of the choices can be rewritten as follows:
By similar reasoning, the other four choices can be written:
In each of the five standard forms, and , so it is necessary to determine the value of that produces a zero discriminant. Substituting accordingly:
Add 900 to both sides and take the square root:
Of the five standard forms,
fits this condition. This is the standard form of the equation
,
the correct choice.
Example Question #1 : Understand And Apply Concepts Of Equations
Give the nature of the solution set of the equation
.
One rational solution
One imaginary solution
Two rational solutions
Two irrational solutions
Two imaginary solutions
Two imaginary solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
This can be done by simply switching the first and second terms:
The key to determining the nature of the solution set is to examine the discriminant . Setting , the value of the discriminant is
The discriminant has a negative value. It follows that the solution set comprises two imaginary values.
Example Question #7 : Quadratic Equations
Give the nature of the solution set of the equation
One rational solution
Two rational solutions
Two imaginary solutions
Two irrational solutions
One imaginary solution
Two imaginary solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
This can be done by adding 17 to both sides:
The key to determining the nature of the solution set is to examine the discriminant
. Setting , the value of the discriminant is
This value is negative. Consequently, the solution set comprises two imaginary numbers.
Example Question #11 : Understand And Apply Concepts Of Equations
Give the nature of the solution set of the equation
Two rational solutions
One rational solution
Two imaginary solutions
Two irrational solutions
One imaginary solution
Two irrational solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
To accomplish this, first, multiply the binomials on the left using the FOIL technique:
Collect like terms:
Now, subtract 18 from both sides:
The key to determining the nature of the solution set is to examine the discriminant . Setting , the value of the discriminant is
The discriminant is a positive number, so there are two real solutions. Since 73 is not a perfect square, the solutions are irrational.
Example Question #1 : Quadratic Equations
Give the nature of the solution set of the equation
One rational solution
Two irrational solutions
One imaginary solution
Two imaginary solutions
Two rational solutions
Two imaginary solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
To accomplish this, first, multiply the binomials on the left using the FOIL technique:
Collect like terms:
Now, add 18 to both sides:
The key to determining the nature of the solution set is to examine the discriminant . Setting , the value of the discriminant is
This discriminant is negative. Consequently, the solution set comprises two imaginary numbers.
Example Question #11 : Understand And Apply Concepts Of Equations
Give the nature of the solution set of the equation
Two imaginary solutions
Two rational solutions
Two irrational solutions
One rational solution
One imaginary solution
Two irrational solutions
To determine the nature of the solution set of a quadratic equation, it is necessary to first express it in standard form
This can be done by switching the first and third terms on the left:
The key to determining the nature of the solution set is to examine the discriminant
. Setting , the value of the discriminant is
.
The discriminant is a positive number but not a perfect square. Therefore, there are two irrational solutions.