PSAT Math : How to find the length of the diameter

Study concepts, example questions & explanations for PSAT Math

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Example Questions

Example Question #132 : Plane Geometry

If the area of a circle is four times larger than the circumference of that same circle, what is the diameter of the circle?

Possible Answers:

8

16

4

2

32

Correct answer:

16

Explanation:

Set the area of the circle equal to four times the circumference πr2 = 4(2πr). 

Cross out both π symbols and one r on each side leaves you with r = 4(2) so r = 8 and therefore = 16.

Example Question #2 : How To Find The Length Of The Diameter

The perimeter of a circle is 36 π.  What is the diameter of the circle?

Possible Answers:

3

36

72

6

18

Correct answer:

36

Explanation:

The perimeter of a circle = 2 πr = πd

Therefore d = 36

Example Question #1 : How To Find The Length Of The Diameter

Sat_math_picture

If the area of the circle touching the square in the picture above is \displaystyle 81\pi, what is the closest value to the area of the square?

Possible Answers:

\displaystyle 81

\displaystyle 162

\displaystyle 211

\displaystyle 100

\displaystyle 144

Correct answer:

\displaystyle 162

Explanation:

Obtain the radius of the circle from the area.

\displaystyle A=\pi r^2=81\pi

\displaystyle r^2=81

\displaystyle r=9

Split the square up into 4 triangles by connecting opposite corners. These triangles will have a right angle at the center of the square, formed by two radii of the circle, and two 45-degree angles at the square's corners. Because you have a 45-45-90 triangle, you can calculate the sides of the triangles to be \displaystyle x, \displaystyle x, and \displaystyle x\sqrt{2}. The radii of the circle (from the center to the corners of the square) will be 9. The hypotenuse (side of the square) must be \displaystyle 9\sqrt{2}.

The area of the square is then \displaystyle (9\sqrt{2})^2=162.

Example Question #522 : Plane Geometry

Two legs of a right triangle measure 3 and 4, respectively. What is the area of the circle that circumscribes the triangle? 

Possible Answers:

\displaystyle 25\pi

\displaystyle 12.5\pi

\displaystyle 6\pi

\displaystyle 5\pi

\displaystyle 6.25\pi

Correct answer:

\displaystyle 6.25\pi

Explanation:

For the circle to contain all 3 vertices, the hypotenuse must be the diameter of the circle. The hypotenuse, and therefore the diameter, is 5, since this must be a 3-4-5 right triangle.

The equation for the area of a circle is A = πr2.

\displaystyle A=\pi (5/2)^2=6.25\pi

Example Question #3 : Diameter And Chords

Sector

Note: Figure NOT drawn to scale.

In the above circle, the length of arc \displaystyle \widehat{MYN} is \displaystyle 42 \pi, and \displaystyle x = 60. What is the diameter of the circle?

Possible Answers:

\displaystyle 50 \frac{2}{5 }

\displaystyle 35

\displaystyle 42

\displaystyle 36

\displaystyle 49

Correct answer:

\displaystyle 50 \frac{2}{5 }

Explanation:

Call the diameter \displaystyle d. Since \displaystyle x = 60\displaystyle \widehat{MN} is \displaystyle \frac{60}{360} = \frac{1}{6} of the circle, and \displaystyle \widehat{MYN} is \displaystyle \frac{5}{6 } of a circle with circumference \displaystyle \pi d.

\displaystyle \widehat{MYN} is \displaystyle 42 \pi in length, so

\displaystyle \frac{5}{6} \pi d = 42 \pi

\displaystyle d = 42 \pi \div \frac{5}{6} \pi =\frac{ 42 \pi }{1}\cdot \frac{6}{5 \pi} = \frac{252}{5 } = 50 \frac{2}{5 }

Example Question #1 : How To Find The Length Of The Diameter

Sector

Note: Figure NOT drawn to scale.

In the above circle, the length of arc \displaystyle \widehat{M N} is 10, and \displaystyle x = 72. Give the diameter of the circle. (Nearest tenth).

Possible Answers:

\displaystyle 19.1

\displaystyle 9.5

Insufficient information exists to answer the question.

\displaystyle 15.9

\displaystyle 8.0

Correct answer:

\displaystyle 15.9

Explanation:

Call the diameter \displaystyle d. Since \displaystyle x = 72\displaystyle \widehat{MN} is \displaystyle \frac{72}{360} = \frac{1}{5} of a circle with circumference \displaystyle \pi d. Since it is of length 10, the circumference of the circle is 5 times this, or 50. Therefore, set \displaystyle C = 50 in the circumference formula:

\displaystyle \pi d = C

\displaystyle \pi d = 50

\displaystyle d = \frac{50 }{\pi } \approx \frac{50 }{3.14159} \approx 15.9

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