All SAT II Math I Resources
Example Questions
Example Question #1 : Types Of Numbers
Express 374 in base six.
To convert a base ten number to base six, divide the number by six, with the remainder being the digit in the units place; continue, dividing each successive quotient by 6 and putting the remainder in the next position to the left until the final quotient is less than 6.
- the rightmost digit is 2
- the next digit to the left is 2
- the next digit to the left is 4, and the digit to the left of that is 1.
Example Question #2 : Types Of Numbers
Express in base ten.
Place values in the base five system are powers of five rather than powers of ten. is equal to
Example Question #3 : Types Of Numbers
Which of the following is the smallest prime number:?
A prime number has only two factor, and itself.
This is not true for or so they are not the answer.
are all prime numbers and is the smallest so it is your answer.
Example Question #1 : Sat Subject Test In Math I
Which of the following is a rational number?
None
A rational number is any number that can be expressed as an integer p or a fraction p/q. In the set of number given only fits into that category.
Example Question #1 : Irrational Numbers
Which of the following is not an irrational number?
A root of an integer is one of two things, an integer or an irrational number. By testing all five on a calculator, only comes up an exact integer - 5. This is the correct choice.
Example Question #2 : Irrational Numbers
Simplify by rationalizing the denominator:
Multiply the numerator and the denominator by the conjugate of the denominator, which is . Then take advantage of the distributive properties and the difference of squares pattern:
Example Question #1 : Irrational Numbers
Example Question #1 : Imaginary Numbers
Multiply:
Use the FOIL technique:
Example Question #61 : Complex Imaginary Numbers
Evaluate:
We can set in the cube of a binomial pattern:
Example Question #1 : Imaginary Numbers
Evaluate
You cannot divide by complex numbers
To divide by a complex number, we must transform the expression by multiplying it by the complex conjugate of the denominator over itself. In the problem, is our denominator, so we will multiply the expression by to obtain:
.
We can then combine like terms and rewrite all terms as . Therefore, the expression becomes:
Our final answer is therefore