ISEE Lower Level Math : Algebraic Concepts

Study concepts, example questions & explanations for ISEE Lower Level Math

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Example Questions

Example Question #1 : Algebraic Concepts

Determine the value of \dpi{100} x

 

\dpi{100} \small 3x+4=19

Possible Answers:

\dpi{100} 5

\dpi{100} 3

\dpi{100} 4

\dpi{100} 2

Correct answer:

\dpi{100} 5

Explanation:

Find which answer makes the equation true.

\dpi{100} 3(5)+4=19

Example Question #2 : Algebraic Concepts

Simplify

\dpi{100} 2x+10-5+6x

Possible Answers:

\dpi{100} 8x-5

\dpi{100} 8x+5

\dpi{100} 2x-11

\dpi{100} 2x+11

Correct answer:

\dpi{100} 8x+5

Explanation:

Combine the \dpi{100} 2x and the \dpi{100} 6x to get \dpi{100} 8x

\dpi{100} 10-5=5

\dpi{100} 8x+5

Example Question #3 : Algebraic Concepts

Determine the value of 

Possible Answers:

Correct answer:

Explanation:

Example Question #4 : Algebraic Concepts

Simplify

Possible Answers:

Correct answer:

Explanation:

Combine like terms:

So 

Example Question #773 : Isee Lower Level (Grades 5 6) Mathematics Achievement

Solve for :

Possible Answers:

Correct answer:

Explanation:

First subtract 12 from both sides

Now divide both sides by 3.

Example Question #6 : Algebraic Concepts

Solve for :

Possible Answers:

Correct answer:

Explanation:

First add  to both sides

Now divide both sides by

Example Question #5 : Algebraic Concepts

Determine the value of 

Possible Answers:

Correct answer:

Explanation:

Example Question #6 : Algebraic Concepts

Solve for .

Possible Answers:

Correct answer:

Explanation:

Replace the variable so the equation is correct.

Example Question #9 : Algebraic Concepts

Solve for .

Possible Answers:

Correct answer:

Explanation:

Find the anwer for which makes the equation true:

Example Question #7 : Algebraic Concepts

Evaluate the expression if .

Possible Answers:

Correct answer:

Explanation:

To solve, insert 7 for each .

When solving this part of the equation, remember the order of operations (PEMDAS) and square the number in the parentheses BEFORE multiplying by 2.

 

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